The image above represents total anomalous mass.

To compute for total anomalous mass, one essential parameter is needed and this parameter is **Number of Area Segments (n).**

The formula for calculating total anomalous mass:

M_{E} = 23.9 Σ(ΔgδA)

Where:

M_{E} = Total Anomalous Mass

Δg = Change in Gravity

δA = Area Segment

Let’s solve an example;

Find the total anomalous mass when the number of area of segments is 2 (change of gravity (Δg_{1}) is 5, area segment (δA_{1}) is 12, change of gravity (Δg_{2}) is 8 and area segment (δA_{2}) is 10).

This implies that;

δA_{1} = Area Segment = 12

Δg_{1} = Change in Gravity = 5

δA_{2} = Area Segment = 10

Δg_{2} = Change in Gravity = 8

Δg | δA | ΔgδA |
---|---|---|

5 | 12 | 60 |

8 | 10 | 80 |

Σ(ΔgδA) = 60 + 80

Σ(ΔgδA) = 140

Therefore,

M_{E} = 23.9 Σ(ΔgδA)

M_{E} = 23.9 (140)

M_{E} = 3346

Therefore, the **total anomalous mass **is **3346 g.**