The image above represents pressure head.

To compute for pressure head, three essential parameters are needed and these parameters are **Pressure (P), Density (ρ) **and **Acceleration due to Gravity (g).**

The formula for calculating pressure head:

h_{p} = ^{P} / _{ρg}

Where:

h_{p} = Pressure Head

P = Pressure

p = Density

g = Acceleration due to Gravity

Let’s solve an example;

Find the pressure head when the pressure is 18, the density is 14 and the acceleration due to gravity is 9.

This implies that;

P = Pressure = 18

p = Density = 14

g = Acceleration due to Gravity = 9

h_{p} = ^{P} / _{ρg}

h_{p} = ^{18} / _{(14)(9)}

h_{p} = ^{18} / _{126}

h_{p} = 0.142

Therefore, the **pressure head **is **0.142.**

**Calculating the Pressure when the Pressure Head, the Density and the Acceleration due to Gravity is Given.**

P = h_{p} x pg

Where;

P = Pressure

h_{p} = Pressure Head

p = Density

g = Acceleration due to Gravity

Let’s solve an example;

Find the pressure when the pressure head is 25, the density is 6 and the acceleration due to gravity is 9.

This implies that;

h_{p} = Pressure Head = 25

p = Density = 6

g = Acceleration due to Gravity = 9

P = h_{p} x pg

P = 25 x (6)(9)

P = 25 x 54

P = 1350

Therefore, the **pressure **is **1350.**

**Calculating the Density when the Pressure Head, the Pressure and the Acceleration due to Gravity is Given.**

p = ^{P} / _{hp x g}

Where;

p = Density

h_{p} = Pressure Head

P = Pressure

g = Acceleration due to Gravity

Let’s solve an example;

Find the density when the pressure head is 4, the pressure is 48 and the acceleration due to gravity is 9.

This implies that;

h_{p} = Pressure Head = 4

P = Pressure = 48

g = Acceleration due to Gravity = 9

p = ^{P} / _{hp x g}

p = ^{48} / _{4 x 9}

p = ^{48} / _{36}

p = 1.33

Therefore, the **density **is **1.33.**

**Calculating the Acceleration due to Gravity when the Pressure Head, the Pressure and the Density is Given.**

g = ^{P} / _{hp x p}

Where;

g = Acceleration due to Gravity

h_{p} = Pressure Head

P = Pressure

p = Density

Let’s solve an example;

Find the acceleration due to gravity when the pressure head is 10, the pressure is 40 and the density is 2.

This implies that;

h_{p} = Pressure Head = 10

P = Pressure = 40

p = Density = 2

g = ^{P} / _{hp x p}

g = ^{40} / _{10 x 2}

g = ^{40} / _{20}

g = 2

Therefore, the **acceleration due to gravity **is **2.**

Nickzom Calculator – **The Calculator Encyclopedia** is capable of calculating the pressure head.

To get the answer and workings of the pressure head using the **Nickzom Calculator – The Calculator Encyclopedia. **First, you need to obtain the app.

You can get this app via any of these means:

**Web** – https://www.nickzom.org/calculator-plus

To get access to the **professional **version via web, you need to **register** and **subscribe **for** NGN 2,000 **per** annum** to have utter access to all functionalities.

You can also try the **demo **version via https://www.nickzom.org/calculator

**Android (Paid)** – https://play.google.com/store/apps/details?id=org.nickzom.nickzomcalculator

**Android (Free)** – https://play.google.com/store/apps/details?id=com.nickzom.nickzomcalculator

**Apple (Paid)** – https://itunes.apple.com/us/app/nickzom-calculator/id1331162702?mt=8

Once, you have obtained the calculator encyclopedia app, proceed to the **Calculator Map, **then click on **Geology**** **under **Add-on****.**

Now, Click on **Aquifer Characteristics **under **Geology**

Now, Click on **Pressure Head **under **Aquifer Characteristics**

The screenshot below displays the page or activity to enter your values, to get the answer for the pressure head according to the respective parameters which are the **Pressure (P), Density (ρ) **and **Acceleration due to Gravity (g).**

Now, enter the values appropriately and accordingly for the parameters as required by the **Pressure (P), Density (ρ) **and **Acceleration due to Gravity (g).**

Finally, Click on Calculate

As you can see from the screenshot above, **Nickzom Calculator**– The Calculator Encyclopedia solves for the pressure head and presents the formula, workings and steps too.