The image above represents flexural strength for circular cross-section in defects.

To compute for flexural strength for circular cross-section in defects, three essential parameters are needed and these parameters are **Load at fracture (F _{f}), Specimen radius (R)** and

**Distance between support Points (L).**

The formula for calculating flexural strength for circular cross-section in defects:

σ_{fs} = ^{FfL} / _{πR³}

Where:

σ_{fs} = Flexural Strength

L = Distance between Support Points

F_{f} = Load at Fracture

R = Specimen Radius

Lets’s solve an example;

Find the flexural strength when the distance between support points is 30, load at fracture is 21 and the specimen radius is 11.

This implies that;

L = Distance between Support Points = 30

F_{f} = Load at Fracture = 21

R = Specimen Radius = 11

σ_{fs} = ^{FfL} / _{πR³}

σ_{fs} = ^{(21)(30)} / _{π(11)³}

σ_{fs} = ^{(630)} / _{π(1331)}

σ_{fs} = ^{(630)} / _{(4181.4)}

σ_{fs} = 0.150

Therefore, the **flexural strength for circular cross-section **is **0.150 Pa.**

**Calculating the Distance Between Support Points when the Flexural Strength for Circular Cross-section, the Specimen Radius and the Load at Fracture is Given.**

L = ^{σfs x πR³} / _{Ff}

Where;

L = Distance between Support Points

σ_{fs} = Flexural Strength

F_{f} = Load at Fracture

R = Specimen Radius

Let’s solve an example;

Find the distance between support points when the flexural strength is 44, load at fracture is 3 and specimen radius is 20.

This implies that;

σ_{fs} = Flexural Strength = 44

F_{f} = Load at Fracture = 3

R = Specimen Radius = 20

L = ^{σfs x πR³} / _{Ff}

L = ^{44 x π x 3³} / _{20}

L = ^{44 x π x 27} / _{20}

L = ^{3732.2} / _{20}

L = 186.61

Therefore, the **distance between support point **is **186.61.**

**Calculating the Load at Fracture when the Flexural Strength, the Specimen Radius and the Distance Between Support Point is Given.**

F_{f} = ^{σfs x πR³} / _{L}

Where;

F_{f} = Load at Fracture

σ_{fs} = Flexural Strength

L = Distance between Support Points

R = Specimen Radius

Let’s solve an example;

Find the load at fracture when the distance between support points is 14, the flexural strength is 7 and the specimen radius is 4.

This implies that;

σ_{fs} = Flexural Strength = 7

L = Distance between Support Points = 14

R = Specimen Radius = 4

F_{f} = ^{σfs x πR³} / _{L}

F_{f} = ^{7 x π x 4³} / _{14}

F_{f} = ^{7 x π x 64} / _{14}

F_{f} = ^{1407.4} / _{14}

F_{f} = 100.5

Therefore, the **load at fracture **is **100.5.**

**Calculating the Specimen Radius when the Flexural Strength, the Distance Between Support Points and the Load at fracture is Given.**

R = ^{3}√(^{FfL} / _{σfs} x ^{1} / _{π})

Where;

R = Specimen Radius

σ_{fs} = Flexural Strength

L = Distance between Support Points

F_{f} = Load at Fracture

Let’s solve an example;

Find the specimen radius when the flexural strength is 18, the distance between support points is 11 and the load at fracture is 7.

This implies that;

σ_{fs} = Flexural Strength = 18

L = Distance between Support Points = 11

F_{f} = Load at Fracture = 7

R = ^{3}√(^{FfL} / _{σfs} x ^{1} / _{π})

R = ^{3}√(^{7 x 11} / _{18} x ^{1} / _{π})

R = ^{3}√(^{77} / _{18} x 0.318)

R = ^{3}√(4.27 x 0.318)

R = ^{3}√1.35786

R = 1.107

Therefore, the **specimen radius **is **1.107.**

Nickzom Calculator – **The Calculator Encyclopedia** is capable of calculating the flexural strength for circular cross-section.

To get the answer and workings of the flexural strength for circular cross-section using the **Nickzom Calculator – The Calculator Encyclopedia. **First, you need to obtain the app.

You can get this app via any of these means:

**Web** – https://www.nickzom.org/calculator-plus

To get access to the **professional **version via web, you need to **register** and **subscribe **for** NGN 1,500 **per** annum** to have utter access to all functionalities.

You can also try the **demo **version via https://www.nickzom.org/calculator

**Android (Paid)** – https://play.google.com/store/apps/details?id=org.nickzom.nickzomcalculator

**Android (Free)** – https://play.google.com/store/apps/details?id=com.nickzom.nickzomcalculator

**Apple (Paid)** – https://itunes.apple.com/us/app/nickzom-calculator/id1331162702?mt=8

Once, you have obtained the calculator encyclopedia app, proceed to the **Calculator Map, **then click on **Materials & Metallurgical**** **under **Engineering****.**

Now, Click on **Ceramics**** **under **Material & Metallurgical**

Now, Click on **Flexural Strength for Circular Cross-Section in Defects**** **under **Ceramics**

The screenshot below displays the page or activity to enter your values, to get the answer for the flexural strength for circular cross-section in defects according to the respective parameters which are the **Load at fracture (F _{f}), Specimen radius (R)** and

**Distance between support Points (L).**

Now, enter the values appropriately and accordingly for the parameters as required by the **Load at fracture (F _{f})** is

**21**,

**Specimen radius (R)**is

**11**and

**Distance between support Points (L)**is

**30**.

Finally, Click on Calculate

As you can see from the screenshot above, **Nickzom Calculator**– The Calculator Encyclopedia solves for the flexural strength for cross-section in defects and presents the formula, workings and steps too.