The image above represents total volume shrinkage.

To compute for total volume shrinkage, three essential parameters are needed and these parameters are **Liquid Shrinkage of Metal or Alloy (ε _{v.l}), Freezing Shrinkage (ε_{v.f}) **and

**Solid Shrinkage (ε**

_{v.s}).The formula for calculating the total volume shrinkage:

ε_{v.t} = ε_{v.l} + ε_{v.f} + ε_{v.s}

Where:

ε_{v.t} = Total Volume Shrinkage

ε_{v.l} = Liquid Shrinkage of Metal or Alloy

ε_{v.f} = Freezing Shrinkage

ε_{v.s} = Solid Shrinkage

Let’s solve an example;

Find the total volume shrinkage when the liquid shrinkage of metal or alloy is 14, the freezing shrinkage is 7 and the solid shrinkage is 2.

This implies that;

ε_{v.l} = Liquid Shrinkage of Metal or Alloy = 14

ε_{v.f} = Freezing Shrinkage = 7

ε_{v.s} = Solid Shrinkage = 2

ε_{v.t} = ε_{v.l} + ε_{v.f} + ε_{v.s}

ε_{v.t} = 14 + 7 + 4

ε_{v.t} = 25

Therefore, the **total volume shrinkage **is **25.**

**Calculating the Liquid Shrinkage of Metal or Alloy when the Total Volume Shrinkage, the Freezing Shrinkage and the Solid Shrinkage is Given.**

ε_{v.l} = ε_{v.t} – ε_{v.f} – ε_{v.s}

Where:

ε_{v.l} = Liquid Shrinkage of Metal or Alloy

ε_{v.t} = Total Volume Shrinkage

ε_{v.f} = Freezing Shrinkage

ε_{v.s} = Solid Shrinkage

Let’s solve an example;

Find the liquid shrinkage of metal or alloy when the total volume shrinkage is 44, the freezing shrinkage is 12 and the solid shrinkage is 6.

This implies that;

ε_{v.t} = Total Volume Shrinkage = 44

ε_{v.f} = Freezing Shrinkage = 12

ε_{v.s} = Solid Shrinkage = 6

ε_{v.l} = ε_{v.t} – ε_{v.f} – ε_{v.s}

ε_{v.l} = 44 – 12 – 6

ε_{v.l} = 26

Therefore, the **liquid shrinkage of metal or alloy **is **26.**