## How to Calculate and Solve for Galileo’s Number | Fluidization The image above represents galileo’s number.

To compute for galileo’s number, two essential parameters are needed and these parameters are Porosity at Minimum Fluidization (emf) and Reynold’s Number at Minimum Fluidization (Re’mf).

The formula for calculating galileo’s number:

Ga = 150(1 – emf/emf³)Re’mf + (1.75/emf³)Re’mf²

Where:

Ga = Galileo’s Number
emf = Porosity at Minimum Fluidization
Re’mf = Reynold’s Number at Minimum Fluidization

Let’s solve an example;
Find the galileo’s number when the porosity at minimum fluidization is 12 and the reynold’s number at minimum fluidization is 6.

This implies that;

emf = Porosity at Minimum Fluidization = 12
Re’mf = Reynold’s Number at Minimum Fluidization = 6

Ga = 150(1 – emf/emf³)Re’mf + (1.75/emf³)Re’mf²
Ga = 150(1 – 12/12³)6 + (1.75/12³)6²
Ga = 150(-11/1728)6 + (1.75/1728)36
Ga = 150(-0.0063)6 + (0.00101)36
Ga = -5.729 + 0.0364
Ga = -5.692

Therefore, Galileo’s number, Ga is -5.69.

## How to Calculate and Solve for Reynold’s Number at Minimum Fluidization | Fluidization The image above represents reynold’s number.

To compute for reynold’s number, four essential parameters are needed and these parameters are Fluidization at Minimum Velocity (umf), Diameter of Bed (d), Density (ρ) and Viscosity (μ).

The formula for calculating reynold’s number:

Re’mf = umf/μ

Where:

Re’mf = Reynold’s Number at Minimum Fluidization
umf = Fluidization at Minimum Velocity
d = Diameter of Bed
ρ = Density
μ = Viscosity

Let’s solve an example;
Find the reynold’s number at minimum fluidization when the fluidization at minimum is 14, the diameter of bed is 8, the density is 12 and the viscosity is 2.

This implies that;

umf = Fluidization at Minimum Velocity = 14
d = Diameter of Bed = 8
ρ = Density = 12
μ = Viscosity = 2

Re’mf = umf/μ
Re’mf = (14)(8)(12)/2
Re’mf = (1344)/2
Re’mf = 672

Therefore, the reynold’s number at minimum fluidization is 672.

Calculating the Fluidization at Minimum Velocity when the Reynold’s Number at Minimum Fluidization, the Diameter of Bed, the Density and the Viscosity is Given.

umf = Re’mf x μ /

Where;

umf = Fluidization at Minimum Velocity
Re’mf = Reynold’s Number at Minimum Fluidization
d = Diameter of Bed
ρ = Density
μ = Viscosity

Let’s solve an example;
Find the fluidization at minimum velocity when the reynold’s number at minimum fluidization is 12, the diameter of bed is 4, the density is 8 and the viscosity is 3.

This implies that;

Re’mf = Reynold’s Number at Minimum Fluidization = 12
d = Diameter of Bed = 4
ρ = Density = 8
μ = Viscosity = 3

umf = Re’mf x μ /
umf = 12 x 3 / (4)(8)
umf = 36 / 32
umf = 1.125

Therefore, the fluidization at minimum velocity is 1.125.