The image above represents %heat loss in flue gas.

To compute for %heat loss in flue gas, four essential parameters are needed and these parameters are **Mass (m), Specific Heat of Stock (C _{p}), Change in Temperature (ΔT)** and

**Gross Calorific Value of Fuel (GCV**

_{f}).The formula for calculating %heat loss in fuel gas:

%Q_{L} = 100(^{mCpΔT}/_{GCVf})

Where:

%Q_{L} = %Heat Loss in Flue Gas

m = Mass

C_{p} = Specific Heat of Stock

ΔT = Change in Temperature

GCV_{f} = Gross Calorific Value of Fuel

Let’s solve an example;

Find the %heat loss in flue gas when the mass is 10, the specific heat of shock is 14, the change in temperature is 12 and the gross calorific value of fuel is 18.

This implies that;

m = Mass = 10

C_{p} = Specific Heat of Stock = 14

ΔT = Change in Temperature = 12

GCV_{f} = Gross Calorific Value of Fuel = 18

%Q_{L} = 100(^{mCpΔT}/_{GCVf})

%Q_{L} = 100(^{10(14)(12)}/_{18})

%Q_{L} = 100(^{1680}/_{18})

%Q_{L} = 100(93.33)

%Q_{L} = 9333.3

Therefore, the **%heat loss of flue gas**** is 9333.3%.**

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