## How to Calculate and Solve for Reaction: Lift Falls Freely | Motion

The image above represents reaction: lift falls freely.

To compute for reaction: lift falls freely, two essential parameters are needed and these parameters are mass (m) and acceleration due to gravity (g).

The formula for calculating reaction: lift falls freely:

R = mg

Where;

R = Reaction
m = Mass
g = acceleration due to gravity

Let’s solve an example;
Find the reaction when the mass is 30 and acceleration due to gravity is 9.8.

This implies that;

m = Mass = 30
g = acceleration due to gravity = 9.8

R = mg
R = 30 x 9.8
R = 294

Therefore, the reaction is 294 N.

Calculating the Mass when the Reaction and the Acceleration due to Gravity is Given.

m = R / g

Where;

m = Mass
R = Reaction
g = acceleration due to gravity

Let’s solve an example;
Find the mass when the reaction is 40 and the acceleration due to gravity is 9.8

This implies that;

R = Reaction = 40
g = acceleration due to gravity = 9.8

m = R / g
m = 40 / 9.8
m = 40 / 9.8
m = 4.08

Therefore, the mass is 4.08.

## How to Calculate and Solve for Reaction: Lift Moves Down | Motion

The image above represents reaction: lift moves down.

To compute for reaction: lift moves down, three essential parameters are needed and these parameters are mass (m), acceleration (a) and acceleration due to gravity (g).

The formula for calculating reaction: lift moves down:

R = m(g – a)

Where;

R = Reaction
m = Mass
g = acceleration due to gravity
a = Acceleration

Let’s solve an example;
Find the reaction when the mass is 28, acceleration is 9 and acceleration due to gravity is 9.8.

This implies that;

m = Mass = 28
g = acceleration due to gravity = 9.8
a = Acceleration = 9

R = m(g – a)
R = 28(9.8 – 9)
R = 28(0.80)
R = 22.4

Therefore, the reaction is 22.4 N.

Calculating the Mass when the Reaction, the Acceleration and the Acceleration due to Gravity is Given.

m = R / g – a

Where;

m = Mass
R = Reaction
g = acceleration due to gravity
a = Acceleration

Let’s solve an example;
Find the mass when the reaction is 42, the acceleration is 8 and the acceleration due to gravity is 9.8

This implies that;

R = Reaction = 42
g = acceleration due to gravity = 9.8
a = Acceleration = 8

m = R / g – a
m = 42 / 9.8 + 8
m = 42 / 17.8
m = 2.359

Therefore, the mass is 2.359.

## How to Calculate and Solve for Reaction: Lift Moves Up | Motion

The image above represents reaction: lift moves up.

To compute for reaction: lift moves up, three essential parameters are needed and these parameters are mass (m), acceleration (a) and acceleration due to gravity (g).

The formula for calculating reaction: lift moves up:

R = m(a + g)

Where;

R = Reaction
m = Mass
g = acceleration due to gravity
a = Acceleration

Let’s solve an example;
Find the reaction when the mass is 18, acceleration is 21 and acceleration due to gravity is 9.8.

This implies that;

m = Mass = 18
g = acceleration due to gravity = 21
a = Acceleration = 9.8

R = m(a + g)
R = 18(21 + 9.8)
R = 18(30.8)
R = 554.4

Therefore, the reaction is 554.4 N.

Calculating the Mass when the Reaction, the Acceleration and the Acceleration due to Gravity is Given.

m = R / a + g

Where;

m = Mass
R = Reaction
g = acceleration due to gravity
a = Acceleration

Let’s solve an example;
Find the mass when the reaction is 42, the acceleration is 21 and the acceleration due to gravity is 9.8

This implies that;

R = Reaction = 42
g = acceleration due to gravity = 9.8
a = Acceleration = 21

m = R / a + g
m = 42 / 21 + 9.8
m = 42 / 30.8
m = 1.36

Therefore, the mass is 1.36.

## How to Calculate and Solve for Force | Motion

The image above represents force.

To compute for force, two essential parameters are needed and these parameters are mass (m) and acceleration (a).

The formula for calculating force:

F = ma

Where;

F = Force
m = Mass
a = Acceleration

Let’s solve an example;
Find the force when the mass is 12 and the acceleration is 26?

This implies that;

m = Mass = 12
a = Acceleration = 26

F = ma
F = 12 x 26
F = 312

Therefore, the force is 312 N.

Calculating for Mass when the Force and the Acceleration is Given.

m = F / a

Where;

m = Mass
F = Force
a = Acceleration

Let’s solve an example;
Find the mass when the force is 100 and the acceleration is 20.

This implies that;

F = Force = 100
a = Acceleration = 20

m = F / a
m = 100 / 20
m = 5

Therefore, the mass is 5.

## How to Calculate and Solve for Linear Momentum | Motion

The image above represents linear momentum.

To compute for linear momentum, two essential parameters are needed and these parameters are mass (m) and velocity (v).

The formula for calculating linear momentum:

p = mv

Where;

p = Momentum
m = Mass
v = Velocity

Let’s solve an example;
Find the momentum when the mass is 8 and the velocity is 12.

This implies that;

m = Mass = 8
v = Velocity = 12

p = mv
p = 8 x 12
p = 96

Therefore, the momentum is 96 Kgm/s.

Calculating the Mass when the Momentum and the Velocity is Given.

m = p / v

Where;

m = Mass
p = Momentum
v = Velocity

Let’s solve an example;
Find the mass when the momentum is 40 and the velocity is 18.

This implies that;

p = Momentum = 40
v = Velocity = 18

m = p / v
m = 40 / 18
m = 2.22

Therefore, the mass is 2.22 kg.

## How to Calculate and Solve for Angular Velocity | Motion

The image above represents angular velocity.

To compute for angular velocity, two essential parameters are needed and these parameters are mass (m) and elastic constant (k).

The formula for calculating angular velocity:

ω = √(k / m)

Where;

ω = Angular Velocity
k = Elastic Constant
m = Mass

Let’s solve an example;
Find the angular velocity when the mass is 11 and the elastic constant is 28.

This implies that;

k = Elastic Constant = 28
jm = Mass = 11

ω = √(k / m)
ω = √(28 / 11)
ω = √(2.54)
ω = 1.59

Therefore, the angular velocity is 1.59 rad/s.

Calculating the Elastic Constant when the Angular Velocity and the Mass is Given.

k = ω2m

Where;

k = Elastic Constant
ω = Angular Velocity
m = Mass

Let’s solve an example;
Find the elastic constant when the angular velocity is 12 and the mass is 8.

This implies that;

ω = Angular Velocity = 12
m = Mass = 8

k = ω2m
k = 1228
k = 144 x 8
k = 1152

Therefore, the elastic constant is 1152.

## How to Calculate and Solve for Period | Motion

The image above represents period.

To compute for period, two essential parameters are needed and these parameters are mass (m) and elastic constant (k).

The formula for calculating period:

T = 2π(√(m / k))

Where;

T = Period
m = Mass
k = Elastic Constant

Let’s solve an example;
Find the period when the mass is 32 and the elastic constant is 16.

This implies that;

m = Mass = 32
k = Elastic Constant = 16

T = 2π(√(m / k))
T = 2π x (√(32 / 16))
T = 2π x (√(2))
T = 2π x 1.41
T = 6.28 x 1.41
T = 8.88

Therefore, the period is 8.88 s.

Calculating the Mass when the Period and the Elastic Constant is Given.

m = (T / 2π)2 x k

Where;

m = Mass
T = Period
k = Elastic Constant

Let’s solve an example;
Find the mass when the period is 22 and the elastic constant is 8.

This implies that;

T = Period = 22
k = Elastic Constant = 8

m = (T / )2 x k
m = (22 / 6.28)2 x 8
m = (3.50)2 x 8
m = 12.25 x 8
m = 98

Therefore, the mass is 98.

## How to Calculate and Solve for TEX | Polymer & Textile

The image above represents TEX.

To compute for TEX, two essential parameters are needed and these parameters are mass (M) and length (L).

The formula for calculating TEX:

TEX = M/L x 1000

Where:

TEX = TEX
M = Mass
L = Length

Let’s solve an example;
Find the TEX when the mass is 8 and the length is 14.

This implies that;

M = Mass = 8
L = Length = 14

TEX = M/L x 1000
TEX = 8/14 x 1000
TEX = 0.57 x 1000
TEX = 571.4

Therefore, the TEX is 571.4.

Calculating the Mass when the TEX and the Length is Given.

M = TEX x L / 1000

Where:

M = Mass
TEX = TEX
L = Length

Let’s solve an example;
Find the mass when the TEX is 40 and the length is 8.

This implies that;

TEX = TEX = 40
L = Length = 8

M = TEX x L / 1000
M = 40 x 8 / 1000
M = 320 / 1000
M = 0.32

Therefore, the mass is 0.32.

## How to Calculate and Solve for Denier | Polymer & Textile

The image above represents denier.

To compute for denier, two essential parameters are needed and these parameters are mass (M) and length (L).

The formula for calculating denier:

Denier = M/L x 9000

Where;

D = Denier
M = Mass
L = Length

Let’s solve an example;
Find the denier with a mass of 24 and a length of 28.

This implies that;

M = Mass = 24
L = Length = 28

Denier = M/L x 9000
Denier = 24/28 x 9000
Denier = 0.857

Therefore, the denier is 0.857.

Calculating the Mass when the Denier and the Length is Given.

M = DL / 9000

Where;

M = Mass
D = Denier
L = Length

Let’s solve an example;
Find the mass of a denier with 30 and a length of 18.

This implies that;

D = Denier = 30
L = Length = 18

M = DL / 9000
M = 30 x 18 / 9000
M = 540 / 9000
M = 0.06

Therefore, the mass is 0.06.

## How to Calculate and Solve for Maximum Velocity to avoid Overturning of a Vehicle moving along a Level Circular Path | The Calculator Encyclopedia

The image above represents the maximum velocity to avoid overturning of a vehicle moving along a level circular path.

To compute for the maximum velocity, four essential parameters are needed and these parameters are Acceleration due to Gravity (g), Height of Centre of Gravity of the Vehicle from Ground Level (h), Radius of Circular Path (r) and Half of the Distance between the Centre Lines of the Wheel (a).

The formula for calculating the maximum velocity:

vmax = √(gra / h)

Where:
vmax = Maximum Velocity to avoid Overturning of a Vehicle moving along a Level Circular Path
g = Acceleration due to Gravity
h = Height of Centre of Gravity of the Vehicle from Ground Level
r = Radius of Circular Path
a = Half of the Distance between the Centre Lines of the Wheel

Let’s solve an example;
Find the maximum velocity when the Acceleration due to Gravity (g) is 10.2, Height of Centre of Gravity of the Vehicle from Ground Level (h) is 14, Radius of Circular Path (r) is 22 and Half of the Distance between the Centre Lines of the Wheel (a) is 32.

This implies that;
g = Acceleration due to Gravity = 10.2
h = Height of Centre of Gravity of the Vehicle from Ground Level = 14
r = Radius of Circular Path = 22
a = Half of the Distance between the Centre Lines of the Wheel = 32

vmax = √(gra / h)
vmax = √((10.2)(22)(32)/14)
vmax = √((7180.79)/14)
vmax = √(512.91)
vmax = 22.647

Therefore, the maximum velocity to avoid Overturning of a Vehicle moving along a Level Circular Path is 22.647 m/s.