The image above represents dimensionless pressure drop.

To compute for the dimensionless pressure drop, five essential parameters are needed and these parameters are **Permeability-Thickness Product (kh), Pressure Drop (ΔP), Oil Rate (Q _{o}), Oil Viscosity (μ_{o}) **and

**Oil FVF (B**

_{o}).The formula for calculating dimensionless pressure drop:

P_{D} = ^{khΔP} / _{141.2Q}_{o}B_{o}μ_{o}

Where;

P_{D} = Dimensionless Pressure Drop

kH = Permeability-Thickness Product

ΔP = Pressure Drop

Q_{o} = Oil Rate

μ_{o} = Oil Viscosity

B_{o} = Oil FVF

Let’s solve an example;

Find the dimensionless pressure drop with a permeability-thickness product of 70, a pressure drop of 30, an oil rate of 49, an oil viscosity of 19 and oil FVF of 31.

This implies that;

kh = Permeability-Thickness Product = 20

ΔP = Pressure Drop = 30

Q_{o} = Oil Rate = 49

μ_{o} = Oil Viscosity = 19

B_{o} = Oil FVF = 31

P_{D} = ^{khΔP} / _{141.2Q}_{o}B_{o}μ_{o}

P_{D} = ^{20 x 30}/_{141.2 x 49 x 31 x 19}

P_{D} = ^{20 x 30}/_{4075173.19}

P_{D} = ^{600}/_{4075173.19}

P_{D} = 0.000147

Therefore, the **dimensionless pressure drop **is **0.000147 psi.**

**Calculating the Permeability-Thickness Product when Dimensionless Pressure Drop, Pressure Drop, Oil Rate, Oil Viscosity and Oil FVF.**

kh = ^{PD x 141.2QoBoμo} / _{ΔP}

Where;

kh = Permeability-Thickness Product

P_{D} = Dimensionless Pressure Drop

ΔP = Pressure Drop

Q_{o} = Oil Rate

μ_{o} = Oil Viscosity

B_{o} = Oil FVF

Let’s solve an example;

Find the permeability-thickness product with a dimensionless pressure drop of 28, a pressure drop of 16, an oil rate of 21, an oil viscosity of 18 and oil FVF of 24 .

This implies that;

P_{D} = Dimensionless Pressure Drop = 28

ΔP = Pressure Drop =16

Q_{o} = Oil Rate = 21

μ_{o} = Oil Viscosity = 18

B_{o} = Oil FVF = 24

kh = ^{PD x 141.2QoBoμo} / _{ΔP}

kh = ^{28 x 141.2 x 21 x 24 x 18} / _{16}

kh = ^{35867059.8} / _{16}

kh = 2241691.2

Therefore, the **permeability-thickness product **is **2241691.2.**

**Calculating the Pressure Drop when Dimensionless Pressure Drop, Permeability-Thickness Product, Oil Rate, Oil Viscosity and Oil FVF.**

ΔP = ^{PD x 141.2QoBoμo} / _{kh}

Where;

ΔP = Pressure Drop

P_{D} = Dimensionless Pressure Drop

kh = Permeability-Thickness Product

Q_{o} = Oil Rate

μ_{o} = Oil Viscosity

B_{o} = Oil FVF

Let’s solve an example;

Find the pressure drop with a dimensionless pressure drop of 38, a permeability-thickness product of 24, an oil rate of 11, an oil viscosity of 8 and oil FVF of 12.

This implies that;

P_{D} = Dimensionless Pressure Drop = 38

kh = Permeability-Thickness Product = 24

Q_{o} = Oil Rate = 11

μ_{o} = Oil Viscosity = 8

B_{o} = Oil FVF = 12

ΔP = ^{PD x 141.2QoBoμo} / _{kh}

ΔP = ^{38 x 141.2 x 11 x 12 x 8} / _{24}

ΔP = ^{5666073.6} / _{24}

ΔP = 236086.4

Therefore, the **pressure drop** is **236086.4.**