The image above represent velocity of newtonian fluid.

To compute for velocity of newtonian fluid, five essential parameters are needed and these parameters are **Change in Pressure (ΔP), Distance between Fluid Flow (L), Diameter of Pipe (y), Separation Distance of Atoms (δ)** and **Viscosity (η).**

The formula for calculating velocity of newtonian fluid:

v = ^{(δ² – y²)ΔP} / _{2η.L}

Where:

v = Velocity of Newtonian Fluid

ΔP = Change in Pressure

L = Distance between Fluid Flow

y = Diameter of Pipe

δ = Separation Distance of Atoms

η = Viscosity

Let’s solve an example;

Find the velocity of newtonian fluid when the change in pressure is 22, the distance between fluid flow is 13, the diameter of pipe is 7, the separation distance of atoms is 11 and the viscosity is 5.

This implies that;

ΔP = Change in Pressure = 22

L = Distance between Fluid Flow = 13

y = Diameter of Pipe = 7

δ = Separation Distance of Atoms = 11

η = Viscosity = 5

v = ^{(δ² – y²)ΔP} / _{2η.L}

v = ^{(11² – 7²)22} / _{2(5).(13)}

v = ^{(121 – 49)22} / _{(10).(13)}

v = ^{(72)22} / _{130}

v = ^{1584} / _{130}

v = 12.18

Therefore, the **velocity of newtonian fluid **is **12.18 m/s.**

**Calculating the Change in Pressure when the Velocity of Newtonian Fluid, the Distance between Fluid Flow, the Diameter of Pipe, the Separation Distance of Atoms and the Viscosity is Given.**

ΔP = ^{v x 2η.L} / _{(δ² – y²)}

Where:

ΔP = Change in Pressure

v = Velocity of Newtonian Fluid

L = Distance between Fluid Flow

y = Diameter of Pipe

δ = Separation Distance of Atoms

η = Viscosity

Let’s solve an example;

Find the change in pressure when the velocity of newtonian fluid is 4, the distance between fluid flow is 2, the diameter of pipe is 3, the separation distance of atoms is 8 and the viscosity is 6.

This implies that;

v = Velocity of Newtonian Fluid = 4

L = Distance between Fluid Flow = 2

y = Diameter of Pipe = 3

δ = Separation Distance of Atoms = 8

η = Viscosity = 6

ΔP = ^{v x 2η.L} / _{(δ² – y²)}

ΔP = ^{4 x 2(6).(2)} / _{(8² – 3²)}

ΔP = ^{4 x 24} / _{(64 – 9)}

ΔP = ^{96} / _{55}

ΔP = 1.745

Therefore, the **change in pressure **is **1.745.**

Continue reading How to Calculate and Solve for Velocity of Newtonian Fluid | Transport Phenomena