The image above represents monochromatic emissive power.

To compute for monochromatic emissive power, five essential parameters are needed and these parameters are **Planck’s Constant (h), Velocity of Light (c), Wavelength (λ), Boltzmann’s Constant (K _{B})** and

**Temperature (T).**

The formula for calculating monochromatic emissive power:

e_{bx} = ^{2πhc²λ-5} / _{exp(ch/KBλT) – 1}

Where:

e_{bx} = Monochromatic Emissive Power | Planck’s Equation

h = Planck’s Constant

c = Velocity of Light

λ = Wavelength

K_{B} = Boltzmann’s Constant

T = Temperature

Let’s solve an example;

Find the monochromatic emissive power when the planck’s constant is 6.626E-24, the velocity of light is 3E8, the wavelength is 22, the boltzmann’s constant is 1.380E-23 and the temperature is 10.

This implies that;

h = Planck’s Constant = 6.626E-24

c = Velocity of Light = 3E8

λ = Wavelength = 22

K_{B} = Boltzmann’s Constant = 1.380E-23

T = Temperature = 10

e_{bx} = ^{2πhc²λ-5} / _{exp(ch/KBλT) – 1}

e_{bx} = ^{2π(6.62607004e-34)(300000000)²(22)-5} / _{exp((300000000)(6.62607004e-34)/(1.38064852e-23)(22)(10)) – 1}

e_{bx} = ^{2π(6.62607004e-34)(90000000000000000)(1.94037e-7)} / _{exp(1.987821012e-25/3.037426744e-21) – 1}

e_{bx} = ^{7.270512005456302e-23} / _{exp(0.00006544424539379114) – 1}

e_{bx} = ^{7.270512005456302e-23} / _{1.0000654463869152 – 1}

e_{bx} = ^{7.270512005456302e-23} / _{0.00006544638691519111}

e_{bx} = 1.11e-18

Therefore, the **monochromatic emissive power **is **1.11e-18.**