The image above represents boiling point elevation.

To compute for the boiling point elevation, three parameters are needed and these parameters are **Van’t Hoff’s Factor (i), ebullioscopic constant (K _{b}**) and

**Molality**.

The formula for calculating boiling point elevation:

δT_{b} = iK_{b} x Molality

Where;

δT_{b} = boiling point elevation

i = Van’t Hoff’s Factor

K_{b} = ebullioscopic constant

Molality

Let’s solve an example;

Find the boiling point elevation when the Van’t Hoff’s Factor is 42, ebullioscopic constant is 60 and molality of 180.

This implies that;

i = Van’t Hoff’s Factor = 42

K_{b} = ebullioscopic constant = 60

Molality = 180

δT_{b} = iK_{b} x Molality

δT_{b} = (42)(60) x 180

δT_{b} = (2520) x 180

δT_{b} = 453600

Therefore, the **boiling point elevation** is **453600 °C m-1.**

**Calculating the Molality using the Boiling Point Elevation, Van’t Hoff’s Factor and Ebullioscopic Constant.**

Molality = ^{δTb} / _{iK}_{b}

Where;

Molality

δT_{b} = boiling point elevation

i = Van’t Hoff’s Factor

K_{b} = ebullioscopic constant

Let’s solve an example;

Find the molality with a boiling point elevation of 120 and a van’t hoff’s factor of 32 with a ebullioscopic constant of 12.

This implies that;

δT_{b} = boiling point elevation = 120

i = Van’t Hoff’s Factor = 32

K_{b} = ebullioscopic constant = 12

Molality = ^{δTb} / _{iK}_{b}

Molality = ^{120} / _{384}

Molality = 0.3125

Therefore, the **molality **is **0.3125.**