The image above represents the linear flow rate.

To compute for the linear flow rate, four parameters are needed and these parameters are **I****nitial pressure (P _{1}), Final Pressure (P_{2}), Thickness (h) **and

**Permeability (k).**

The formula for calculating linear flow rate:

q = 0.001127kh[P_{1} – P_{2}]

Where:

q = Linear Flow Rate

P_{1} = Initial Pressure

P_{2} = Final Pressure

h = Thickness

k = Permeability

Let’s solve an example;

Find the linear flow rate when the initial pressure is 12, final pressure is 22, thickness is 18 and permeability is 44.

This implies that;

P_{1} = Initial Pressure = 12

P_{2} = Final Pressure = 22

h = Thickness = 18

k = Permeability = 44

q = 0.001127kh [P_{1} – P_{2}]

q = 0.001127 x 44 x 18 [12 – 22]

q = 0.001127 x 44 x 18 [-10]

q = 0.892584 [-10]

q = -8.92584

Therefore, the **linear flow rate** is **-8.92584** ^{bbl}/_{day}.

**Calculating Permeability when the linear flow rate, Initial Pressure, Final Pressure and Thickness is Given.**

k = ^{q} / _{0.001127h (p}_{1} – p_{2})

Where;

k = Permeability

q = Linear Flow Rate

P_{1} = Initial Pressure

P_{2} = Final Pressure

h = Thickness

Let’s solve an example;

Find the permeability when the initial pressure is 34, final pressure is 24, thickness is 12 and linear flow rate is 50.

This implies that;

q = Linear Flow Rate = 50

P_{1} = Initial Pressure = 34

P_{2} = Final Pressure = 24

h = Thickness = 12

k = ^{q} / _{0.001127h (p1 – p2)}

k = ^{50} / _{0.001127h (34 – 24)}

k = ^{50} / _{0.001127h (10)}

k = ^{50} / _{0.01127}

k = 4436.5

Therefore, the **permeability** is **4436.5.**