The image above represents average linear velocity.

To compute for average linear velocity, three essential parameters are needed and these parameters are **Discharge (Q), Effective Porosity (n _{e}) **and

**Cross-Sectional Area (A).**

The formula for calculating average linear velocity:

v_{x} = ^{Q} / _{n}_{e}A

Where:

v_{x} = Average Linear Velocity

Q = Discharge

n_{e} = Effective Porosity

A = Cross-Sectional Area

Let’s solve an example;

Find the average linear velocity when the discharge is 12, the effective porosity is 9 and the cross-sectional area is 22.

This implies that;

Q = Discharge = 12

n_{e} = Effective Porosity = 9

A = Cross-Sectional Area = 22

v_{x} = ^{Q} / _{neA}

v_{x} = ^{12} / _{9(22)}

v_{x} = ^{12} / _{198}

v_{x} = 0.060

Therefore, the **average linear velocity **is **0.060 m/s.**

**Calculating the Discharge when the Average Linear Velocity, the Effective Porosity and the Cross-Sectional Area is Given.**

Q = v_{x} x n_{e} A

Where;

Q = Discharge

v_{x} = Average Linear Velocity

n_{e} = Effective Porosity

A = Cross-Sectional Area

Let’s solve an example;

Find the discharge when the average linear velocity is 22, the effective pororsity is 10 and the cross-sectional area is 14.

This implies that;

v_{x} = Average Linear Velocity = 22

n_{e} = Effective Porosity = 10

A = Cross-Sectional Area = 14

Q = v_{x} x n_{e} A

Q = 22 x 10 x 14

Q = 3080

Therefore, the **discharge **is **3080.**

Continue reading How to Calculate and Solve for Average Linear Velocity | Aquifer Characteristics