The image above represents total cross-sectional areas of gates.

To compute for total cross-sectional areas of gates, four essential parameters are needed and these parameters are **mass of the casting (G), density of melt (ρ), pouring time (t) **and **pouring speed (v).**

The formula for calculating total cross-sectional areas of gates:

F_{g} = ^{G} / _{ρtv}

Where:

F_{g} = Total Cross-Sectional Area of Gates

G = Mass of the Casting

ρ = Density of Melt

t = Pouring Time

v = Pouring Speed

Let’s solve an example;

Find the total cross-sectional areas of gates when mass of the casting is 12, density of melt is 16, pouring time is 5 and pouring speed is 25.

This implies that;

G = Mass of the Casting = 12

ρ = Density of Melt = 16

t = Pouring Time = 5

v = Pouring Speed = 25

F_{g} = ^{G} / _{ρtv}

F_{g} = ^{12} / _{16 x 5 x 25}

F_{g} = ^{12} / _{2000}

F_{g} = 0.006

Therefore, the **total cross-sectional areas of gates **is **0.006 m ^{2}.**

**Calculating the Mass of the Casting when the Total Cross-Sectional Areas of Gates, the Density of Melt, the Pouring Time and the Pouring Speed is Given.**

G = F_{g} x ρtv

Where;

G = Mass of the Casting

F_{g} = Total Cross-Sectional Area of Gates

ρ = Density of Melt

t = Pouring Time

v = Pouring Speed

Let’s solve an example;

Find the mass of the casting when the total cross-sectional areas of gates is 32, the density of melt is 4, the pouring time is 10 and the pouring speed is 2.

This implies that;

F_{g} = Total Cross-Sectional Area of Gates = 32

ρ = Density of Melt = 4

t = Pouring Time = 10

v = Pouring Speed = 2

G = F_{g} x ρtv

G = 32 x 4 x 10 x 2

G = 2560

Therefore, the **mass of the Casting **is **2560 m.**