The image above represents permeation.

To compute for permeation, six essential parameters are needed and these parameters are **Length of Vessel (L), Diameter (D), Initial Concentration (c _{1}), Final Concentration (c_{2}), Inlet Radius of Pipe (r_{1}) **and

**Exit Radius of Pipe (r**

_{2}).The formula for calculating permeation:

j = -2πLD (^{c1 – c2} / _{In(r1/r2)})

Where:

j = Permeation

L = Length of Vessel

D = Diameter

c_{1} = Initial Concentration

c_{2} = Final Concentration

r_{1} = Inlet Radius of Pipe

r_{2} = Exit Radius of Pipe

Let’s solve an example;

Find the permeation when the length of vessel is 8, the diameter is 2, the initial concentration is 4, the final concentration is 9, the inlet radius of pipe is 13 and the exit radius of pipe is 11.

This implies that;

L = Length of Vessel = 8

D = Diameter = 2

c_{1} = Initial Concentration = 4

c_{2} = Final Concentration = 9

r_{1} = Inlet Radius of Pipe = 13

r_{2} = Exit Radius of Pipe = 11

j = -2πLD (^{c1 – c2} / _{In(r1/r2)})

j = -2π(8)(2) (^{4 – 9}/_{In(13/11)})

j = (-100.53) (^{-5}/_{In(1.18)})

j = (-100.53) (^{-5}/_{0.167})

j = (-100.53) (-29.93)

j = 3008.9

Therefore, the **permeation **is **3008.9 m².**

Continue reading How to Calculate and Solve for Permeation | Mass Transfer