How to Calculate and Solve for Flexural Strength for Rectangular Cross-section in Defects | Ceramics

The image above represents flexural strength for rectangular cross-section in defects.

To compute for flexural strength for rectangular cross-section in defect, four essential parameters are needed and these parameters are Load at fracture (Ff), Length of the cross-section (b), Width of the cross-section (d) and Distance between support points (L).

The formula for calculating flexural strength for rectangular cross-section in defects:

σfs = 3FfL / 2bd²

Where:

σfs = Flexural Strength
Ff = Load at Fracture
L = Distance between Support Points
b = Length of Cross-section
d = Width of Cross-section

Let’s solve an example;
Find the flexural strength when the load at fracture is 10, the length of cross-section is 7, width of cross-section is 9 and the distance between support points is 21.

This implies that;

Ff = Load at Fracture = 10
L = Distance between Support Points = 21
b = Length of Cross-section = 7
d = Width of Cross-section = 9

σfs = 3FfL / 2bd²
σfr = 3(10)(21) / 2(7)(9)²
σfr = (630) / 2(7)(81)
σfr = (630) / (1134)
σfr = 0.55

Therefore, the flexural strength for rectangular cross-section in defect is 0.55 Pa.

Calculating the Distance Between Support Points when the Flexural Strength for Rectangular Cross-Section in Defects, Load at Fracture, length of the cross-section and width of cross-section is Given.

L = σfs x 2bd2 / 3Ff

Where;

L = Distance between Support Points
σfs = Flexural Strength
Ff = Load at Fracture
b = Length of Cross-section
d = Width of Cross-section

Let’s solve an example;
Find the distance between support points when the flexural strength is 20, the load at fracture is 12, the length of cross-section is 7 and the width of cross-section is 9.

This implies that;

σfs = Flexural Strength = 20
Ff = Load at Fracture = 12
b = Length of Cross-section = 7
d = Width of Cross-section = 9

L = σfs x 2bd2 / 3Ff
L = 20 x 2 x 7 x 92 / 3 x 12
L = 280 x 81 / 36
L = 22680 / 36
L = 630

Therefore, the distance between support points is 630.

Continue reading How to Calculate and Solve for Flexural Strength for Rectangular Cross-section in Defects | Ceramics

How to Calculate and Solve for Flexural Strength for Circular Cross-section in Defects | Ceramics

The image above represents flexural strength for circular cross-section in defects.

To compute for flexural strength for circular cross-section in defects, three essential parameters are needed and these parameters are Load at fracture (Ff), Specimen radius (R) and Distance between support Points (L).

The formula for calculating flexural strength for circular cross-section in defects:

σfs = FfL / πR³

Where:

σfs = Flexural Strength
L = Distance between Support Points
Ff = Load at Fracture
R = Specimen Radius

Lets’s solve an example;
Find the flexural strength when the distance between support points is 30, load at fracture is 21 and the specimen radius is 11.

This implies that;

L = Distance between Support Points = 30
Ff = Load at Fracture = 21
R = Specimen Radius = 11

σfs = FfL / πR³
σfs = (21)(30) / π(11)³
σfs = (630) / π(1331)
σfs = (630) / (4181.4)
σfs = 0.150

Therefore, the flexural strength for circular cross-section is 0.150 Pa.

Calculating the Distance Between Support Points when the Flexural Strength for Circular Cross-section, the Specimen Radius and the Load at Fracture is Given.

L = σfs x πR³ / Ff

Where;

L = Distance between Support Points
σfs = Flexural Strength
Ff = Load at Fracture
R = Specimen Radius

Let’s solve an example;
Find the distance between support points when the flexural strength is 44, load at fracture is 3 and specimen radius is 20.

This implies that;

σfs = Flexural Strength = 44
Ff = Load at Fracture = 3
R = Specimen Radius = 20

L = σfs x πR³ / Ff
L = 44 x π x 3³ / 20
L = 44 x π x 27 / 20
L = 3732.2 / 20
L = 186.61

Therefore, the distance between support point is 186.61.

Continue reading How to Calculate and Solve for Flexural Strength for Circular Cross-section in Defects | Ceramics