How to Calculate and Solve for Glide Shear | Fracture Mechanics

The image above represents glide shear.

To compute for glide shear, two essential parameters are needed and these parameters are Stacking Fault Energy (γ) and Varying Grain Constant (M’).

The formula for calculating glide shear:

E = γ / M’

Where:

E = Glide Shear
γ = Stacking Fault Energy
M’ = Varying Grain Constant

Let’s solve an example;
Find the glide shear when the stacking fault energy is 18 and the varying grain constant is 2.

This implies that;

γ = Stacking Fault Energy = 18
M’ = Varying Grain Constant = 2

E = γ / M’
E = 18 / 2
E = 9

Therefore, the glide shear is 9 Pa.

Calculating the Stacking Fault Energy when the Glide Shear and the Varying Grain Constant is Given.

γ = E x M’

Where;

γ = Stacking Fault Energy
E = Glide Shear
M’ = Varying Grain Constant

Let’s solve an example;
Find the stacking fault energy when the glide shear is 14 and the varying grain constant is 8.

This implies that;

E = Glide Shear = 14
M’ = Varying Grain Constant = 8

γ = E x M’
γ = 14 x 8
γ = 112

Therefore, the stacking fault energy is 112.

Continue reading How to Calculate and Solve for Glide Shear | Fracture Mechanics

How to Calculate and Solve for Partial Dislocation Separation | Fracture Mechanics

The image above represents partial dislocation separation.

To compute for partial dislocation separation, four essential parameters are needed and these parameters are Shear Modulus (G), Burger Vector (b2), Burger Vector (b3and Stacking Fault Energy (γ).

The formula for calculating partial dislocation separation:

d = Gb2b3 / 2πγ

Where:

d = Partial Dislocation Separation
G = Shear Modulus
b2 and b3 = Burger Vectors
γ = Stacking Fault Energy

Let’s solve an example;
Find the partial dislocation separation when the shear modulus is 4. the burger vectors is 8 and 10, the stacking fault energy is 14.

This implies that;

G = Shear Modulus = 4
b2 and b3 = Burger Vectors = 8 and 10
γ = Stacking Fault Energy = 14

d = Gb2b3 / 2πγ
d = (4)(8)(10) / 2π(14)
d = 320 / 87.96
d = 3.64

Therefore, the partial dislocation separation is 3.64 m.

Continue reading How to Calculate and Solve for Partial Dislocation Separation | Fracture Mechanics