The image above represents the osmotic pressure.

To compute for the osmotic pressure, five parameters are needed and these parameters are I**deal Gas Constant (R)**, **Temperature in Kelvin (T)**, **Number of Moles (n), Volume (V) **and **Van’t Hoff’s Factor ****(i).**

The formula for calculating osmotic pressure:

π = i ^{nRT} ⁄ _{V}

Where;

π = osmotic pressure

n = number of moles

R = ideal gas constant

T = temperature in Kelvin

i = Van’t Hoff’s Factor

V = Volume

Let’s solve an example;

Find the osmotic pressure when the ideal gas constant is 0.08206 with a temperature in kelvin of 120, number of moles is 32, a volume of 48 and a van’t hoff’s factor of 24.

This implies that;

n = number of moles = 32

R = ideal gas constant = 0.08206

T = temperature in Kelvin = 120

i = Van’t Hoff’s Factor = 24

V = Volume = 48

π = i ^{nRT} ⁄ _{V}

π = 24 ^{32 x 0.08206 x 120} ⁄ _{48}

π = (24) ^{(315.110)} ⁄ _{(48)}

π = (24)(6.5647)

π = 157.5

Therefore, the **osmotic pressure **is **157.5 atm.**

**Calculating the Van’t Hoff’s Factor using the Osmotic Pressure, Number of Moles, Temperature in Kelvin, Ideal Gas Constant and Volume.**

i = ^{Vπ} / _{nRT}

Where;

i = Van’t Hoff’s Factor

π = osmotic pressure

V = Volume

n = number of moles

R = ideal gas constant

T = temperature in Kelvin

Let’s solve an example;

Find the Van’t Hoff’s Factor when the osmotic pressure is 220, volume of 50, temperature in kelvin of 180 and number of moles of 60. (R = 0.08206)

This implies that;

π = osmotic pressure = 220

V = Volume = 50

n = number of moles = 60

R = ideal gas constant = 0.08206

T = temperature in Kelvin = 180

i = ^{Vπ} / _{nRT}

i = ^{50 x 220} / _{60 x 0.08206 x 180}

i = ^{11000} / _{866.808}

i = 12.69

Therefore, the **Van’t Hoff’s Factor **is **12.69.**

**Calculating the Volume using the Osmotic Pressure, Number of Moles, Temperature in Kelvin, Ideal Gas Constant and Van’t Hoff’s Factor.**

V = ^{i (nRT)} / _{π}

Where;

V = Volume

i = Van’t Hoff’s Factor

π = osmotic pressure

n = number of moles

R = ideal gas constant

T = temperature in Kelvin

Let’s solve an example;

Find the volume when the osmotic pressure is 280, Van’t Hoff’s Factor of 40, temperature in kelvin of 90 and number of moles of 70. (R = 0.08206)

This implies that;

i = Van’t Hoff’s Factor = 40

π = osmotic pressure = 280

n = number of moles = 70

R = ideal gas constant = 0.08206

T = temperature in Kelvin = 90

V = ^{i (nRT)} / _{π}

V = ^{40 (70 x 0.08206 x 90)} / _{280}

V = ^{40 (516.978)} / _{280}

V = ^{20679.12} / _{280}

V = 73.854

Therefore, the **volume **is **73.854.**