The image above represents newton’s laws of viscosity of gases.
To compute for newton’s laws of viscosity of gases, four essential parameters are needed and these parameters are Number of Molecules (m), Boltzmann’s Constant (KB), Temperature (T) and Pipe Diameter (d).
The formula for calculating newton’s laws of viscosity of gases:
η = 2(mKBT)0.5 / 3π1.5.d²
Where:
η = Newton’s Law of Viscosity of Gases
m = Number of Molecules
KB = Boltzmann’s Constant
T = Temperature
d = Pipe Diameter
Let’s solve an example;
Find the newton’s law of viscosity of gases when the number of molecules is 14, the boltzmann’s constant is 1.380E-23, the temperature is 10 and the pipe diameter is 21.
This implies that;
m = Number of Molecules = 14
KB = Boltzmann’s Constant = 1.380E-23
T = Temperature = 10
d = Pipe Diameter = 21
η = 2(mKBT)0.5 / 3π1.5.d²
η = 2((14)(1.380e-23)(10))0.5 / 3π1.5.(21)²
η = 2(1.93e-21)0.5 / (16.70).(441)
η = 2(4.396e-11) / 7366.89
η = 8.79e-11 / 7366.89
η = 1.19e-14
Therefore, the newton’s law of viscosity of gases is 1.19e-14 m²/s.