The image above represents marhoun’s gas solubility.

To compute for the marhoun’s gas solubility, four essential parameters are needed and these parameters are **Gas Specific Gravity (γ _{g}), Temperature (°Rankine) (T), Pressure (P) and Stock Tank Oil Gravity (γ_{o}).**

The formula for calculating the marhoun’s gas solubility:

R_{s} = [a γ_{g}^{b} γ_{o}^{c} T^{d} P]^{e}

Where:

R_{s} = Marhoun’s Gas Solubility

a = 185.843208

b = 1.877840

c = -3.1437

d = -1.32657

e = 1.398441

γ_{g} = Gas Specific Gravity

T = Temperature (°Rankine)

P = Pressure

γ_{o} = Stock Tank Oil Gravity

Let’s solve an example;

Find the marhoun’s gas solubility when the gas specific gravity is 14, temperature is 80, pressure is 40 and the stock tank oil gravity is 24.

This implies that;

γ_{g} = Gas Specific Gravity = 14

T = Temperature (°Rankine) = 80

P = Pressure = 40

γ_{o} = Stock Tank Oil Gravity = 24

R_{s} = [a γ_{g}^{b} γ_{o}^{c} T^{d} P]^{e}

R_{s} = [185.843208 x 14^{1.87784} x 24^{-3.1437} x 80^{-1.32657} x 40]^{1.398441}

R_{s} = [185.843208 x 141.98 x 24^{-3.1437} x 80^{-1.32657} x 40]^{1.398441}

R_{s} = [185.843208 x 141.98 x 0.0000458 x 80^{-1.32657} x 40]^{1.398441}

R_{s} = [185.843208 x 141.98 x 0.0000458 x 0.00298 x 40]^{1.398441}

R_{s} = [0.1445]^{1.398441}

R_{s} = 0.0668

Therefore, the **marhoun’s gas solubility **is **0.0668.**