The image above represents the maximum velocity to avoid overturning of a vehicle moving along a level circular path.

To compute for the maximum velocity, four essential parameters are needed and these parameters are **Acceleration due to Gravity (g), Height of Centre of Gravity of the Vehicle from Ground Level (h), Radius of Circular Path (r) and Half of the Distance between the Centre Lines of the Wheel (a).**

The formula for calculating the maximum velocity:

v_{max} = √(^{gra} / _{h})

Where:

v_{max} = Maximum Velocity to avoid Overturning of a Vehicle moving along a Level Circular Path

g = Acceleration due to Gravity

h = Height of Centre of Gravity of the Vehicle from Ground Level

r = Radius of Circular Path

a = Half of the Distance between the Centre Lines of the Wheel

Let’s solve an example;

Find the maximum velocity when the Acceleration due to Gravity (g) is 10.2, Height of Centre of Gravity of the Vehicle from Ground Level (h) is 14, Radius of Circular Path (r) is 22 and Half of the Distance between the Centre Lines of the Wheel (a) is 32.

This implies that;

g = Acceleration due to Gravity = 10.2

h = Height of Centre of Gravity of the Vehicle from Ground Level = 14

r = Radius of Circular Path = 22

a = Half of the Distance between the Centre Lines of the Wheel = 32

v_{max} = √(^{gra} / _{h})

v_{max} = √(^{(10.2)(22)(32)}/_{14})

v_{max} = √(^{(7180.79)}/_{14})

v_{max} = √(512.91)

v_{max} = 22.647

Therefore, the **maximum velocity to avoid Overturning of a Vehicle moving along a Level Circular Path** is **22.647 m/s.**