The image above represents effective heat of fusion.

To compute for effective heat of fusion, three essential parameters are needed and these parameters are **Latent Heat of Fusion (H _{f}), Heat Capacity at Constant Pressure (c_{p}) **and

**Change in Temperature (ΔT).**

The formula for calculating effective heat of fusion:

H = H_{f} + c_{p}ΔT

Where:

H = Effective Heat of Fusion

H_{f} = Latent Heat of Fusion

c_{p} = Heat Capacity at Constant Pressure

ΔT = Change in Temperature

Let’s solve an example;

Find the effective heat of fusion when the latent heat of fusion is 12, the heat capacity at constant pressure is 14 and the change in temperature is 10.

This implies that;

H_{f} = Latent Heat of Fusion = 12

c_{p} = Heat Capacity at Constant Pressure = 14

ΔT = Change in Temperature = 10

H = H_{f} + c_{p}ΔT

H = 12 + 14(10)

H = 12 + 140

H = 152

Therefore, the **effective heat of fusion **is **152 J/Kg.**

**Calculating the Latent Heat of Fusion when the Effective Heat of Fusion, the Heat Capacity at Constant Pressure and the Change in Temperature is Given.**

H_{f} = H – c_{p}ΔT

Where:

H_{f} = Latent Heat of Fusion

H = Effective Heat of Fusion

c_{p} = Heat Capacity at Constant Pressure

ΔT = Change in Temperature

Let’s solve an example;

Find the latent heat of fusion when the effective heat of fusion is 42, the heat capacity at constant pressure is 10 and the change in temperature is 2.

This implies that;

H = Effective Heat of Fusion = 42

c_{p} = Heat Capacity at Constant Pressure = 10

ΔT = Change in Temperature = 2

H_{f} = H – c_{p}ΔT

H_{f} = 42 – (10)(2)

H_{f} = 42 – 20

H_{f} = 22

Therefore, the **latent heat of fusion **is **22.**

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