{"id":8314,"date":"2022-12-15T07:52:08","date_gmt":"2022-12-15T06:52:08","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=8314"},"modified":"2024-06-04T15:25:52","modified_gmt":"2024-06-04T14:25:52","slug":"how-to-calculate-and-solve-for-critical-wall-stress-of-spherical-body-fracture","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2022\/12\/15\/how-to-calculate-and-solve-for-critical-wall-stress-of-spherical-body-fracture\/","title":{"rendered":"How to Calculate and Solve for Critical Wall Stress of Spherical Body | Fracture"},"content":{"rendered":"

The image of the critical wall stress of a spherical body is represented below. To calculate the critical wall stress of a spherical body, three essential parameters are needed: W<\/strong>all Pressure (p)<\/strong>, Radius of the Sphere (r)<\/strong>,\u00a0<\/strong>and\u00a0Wall Thickness (t).<\/strong><\/p>\n

\"\"<\/p>\n

The formula for calculating critical wall stress of spherical body:<\/strong><\/h3>\n

\u03c3y<\/sub>\u00a0=\u00a0pr<\/sup>\/2t<\/sub><\/p>\n

Where:<\/p>\n

\u03c3y<\/sub>\u00a0= Critical Wall Stress of Spherical Body
\np = Wall Pressure
\nr = Radius of Sphere
\nt = Wall Thickness<\/p>\n

Let’s solve an example;
\nFind the critical wall stress of spherical body when the wall pressure is 17, the radius of sphere is 13 and the wall thickness is 5.<\/p>\n

This implies that;<\/p>\n

p = Wall Pressure = 17
\nr = Radius of Sphere = 13
\nt = Wall Thickness = 5<\/p>\n

\u03c3y<\/sub>\u00a0=\u00a0pr<\/sup>\/2t<\/sub>
\nThat is, \u03c3y<\/sub>\u00a0=\u00a0(17)(13)<\/sup>\/2(5)<\/sub>
\n\u03c3y<\/sub>\u00a0=\u00a0(221)<\/sup>\/(10)<\/sub>
\n\u03c3y<\/sub> = 22.1<\/p>\n

Therefore, the\u00a0critical wall stress of spherical body\u00a0<\/strong>is\u00a022.1 Pa.<\/strong><\/p>\n

Calculating the Wall Pressure when the Critical Wall Stress of Spherical Body, the Radius of Sphere and the Wall Thickness are Given<\/strong><\/h3>\n

p = \u03c3y<\/sub> x 2t<\/sup> \/ r<\/sub><\/p>\n

Where:<\/p>\n

p = Wall Pressure
\n\u03c3y<\/sub>\u00a0= Critical Wall Stress of Spherical Body
\nr = Radius of Sphere
\nt = Wall Thickness<\/p>\n

Let’s solve an example;
\nFind the wall pressure when the critical wall stress of spherical body is 8, the radius of sphere is 4 and the wall thickness is 2.<\/p>\n

This implies that;<\/p>\n

\u03c3y<\/sub> = Critical Wall Stress of Spherical Body = 8
\nr = Radius of Sphere = 4
\nt = Wall Thickness = 2<\/p>\n

p = \u03c3y<\/sub> x 2t<\/sup> \/ r<\/sub>
\np = 8 x 2(2)<\/sup> \/ 4<\/sub>
\nThat is, p = 8 x 4<\/sup> \/ 4<\/sub>
\np = 32<\/sup> \/ 4<\/sub>
\np = 8<\/p>\n

Therefore, the\u00a0wall pressure\u00a0<\/strong>is\u00a08.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Stress Ratio | Fracture<\/a><\/p>\n

Calculating the Radius of Sphere when the Critical Wall Stress of Spherical Body, the Wall Thickness are Given<\/strong><\/h3>\n

r = \u03c3y<\/sub> x 2t<\/sup> \/ p<\/sub><\/p>\n

Where:<\/p>\n

r = Radius of Sphere
\n\u03c3y<\/sub>\u00a0= Critical Wall Stress of Spherical Body
\np = Wall Pressure
\nt = Wall Thickness<\/p>\n

Let’s solve an example;
\nFind the radius of sphere when the critical wall stress of spherical body is 10, the wall pressure is 6 and the wall thickness is 3.<\/p>\n

This implies that;<\/p>\n

\u03c3y<\/sub> = Critical Wall Stress of Spherical Body = 10
\np = Wall Pressure = 6
\nt = Wall Thickness = 3<\/p>\n

r = \u03c3y<\/sub> x 2t<\/sup> \/ p<\/sub>
\nr = 10 x 2(3)<\/sup> \/ 6<\/sub>
\nSo, r = 10 x 6<\/sup> \/ 6<\/sub>
\nr = 60<\/sup> \/ 6<\/sub>
\nr = 10<\/p>\n

Therefore, the\u00a0radius of sphere\u00a0<\/strong>is\u00a010 m.<\/strong><\/p>\n

Calculating the Wall Thickness when the Critical Wall Stress of Spherical Body, the Wall Pressure and the Radius of Sphere are Given<\/strong><\/h3>\n

t = pr<\/sup> \/ 2\u03c3y<\/sub><\/sub><\/p>\n

Where:<\/p>\n

t = Wall Thickness
\n\u03c3y<\/sub>\u00a0= Critical Wall Stress of Spherical Body
\np = Wall Pressure
\nr = Radius of Sphere<\/p>\n

Let’s solve an example;
\nGiven that the critical wall stress of spherical body is 6, the wall pressure is 14 and the radius of sphere is 2.<\/p>\n

This implies that;<\/p>\n

\u03c3y<\/sub> = Critical Wall Stress of Spherical Body = 6
\np = Wall Pressure = 14
\nr = Radius of Sphere = 2<\/p>\n

t = pr<\/sup> \/ 2\u03c3y<\/sub><\/sub>
\nSo, t = 14(2)<\/sup> \/ 2(6)<\/sub>
\nt = 28<\/sup> \/ 12<\/sub>
\nt = 2.3<\/p>\n

Therefore, the\u00a0wall thickness\u00a0<\/strong>is\u00a02.3 m.<\/strong><\/p>\n

How to Calculate Critical Wall Stress of Spherical Body Using Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the critical wall stress of spherical body.<\/p>\n

\n

To get the answer and workings of the critical wall stress of spherical body using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><\/p>\n

Apple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Materials and Metallurgical\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n<\/div>\n

<\/p>\n

Now, Click on\u00a0Fracture<\/strong>\u00a0<\/b>under\u00a0Materials and Metallurgical<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Critical Wall Stress of Spherical Body<\/strong>\u00a0<\/strong>under\u00a0Fracture<\/strong><\/p>\n

\"\"<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the critical wall stress of spherical body according to the respective parameter which is the Wall Pressure (p), Radius of Sphere (r)\u00a0<\/strong>and\u00a0Wall Thickness (t).<\/strong><\/p>\n

\"How<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the Wall Pressure (p)<\/strong> is 17<\/strong>, Radius of Sphere (r)<\/strong> is 13 <\/strong>and Wall Thickness (t)<\/strong> is 5<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How<\/p>\n

As you can see from\u00a0the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the critical wall stress of spherical body and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image of the critical wall stress of a spherical body is represented below. To calculate the critical…","protected":false},"author":5,"featured_media":16420,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"Calculate Critical Wall Stress of Spherical Body","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"Find all the steps needed and the formula required on How to Calculate and Solve for Critical Wall Stress of Spherical 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