{"id":7150,"date":"2022-07-12T04:57:38","date_gmt":"2022-07-12T03:57:38","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=7150"},"modified":"2024-05-24T17:40:27","modified_gmt":"2024-05-24T16:40:27","slug":"how-to-calculate-and-solve-for-enthalpy-at-constant-pressure-heating-or-cooling-enthalpy","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2022\/07\/12\/how-to-calculate-and-solve-for-enthalpy-at-constant-pressure-heating-or-cooling-enthalpy\/","title":{"rendered":"How to Calculate and Solve for Enthalpy at Constant Pressure Heating or Cooling | Enthalpy"},"content":{"rendered":"

The enthalpy at constant pressure heating or cooling is illustrated by the image below. To calculate enthalpy at constant pressure (heating or cooling), two essential parameters are needed and these parameters are Enthalpy at Point 1 (h1<\/sub>)<\/strong> and Enthalpy at Point 2 (h2<\/sub>).<\/strong><\/p>\n

\"\"<\/p>\n

The formula for calculating enthalpy at constant pressure:<\/strong><\/h3>\n

Q = h2<\/sub>\u00a0– h1<\/sub><\/p>\n

Where:<\/p>\n

Q = Enthalpy at Constant Pressure
\nh1<\/sub>\u00a0= Enthalpy at Point 1
\nh2<\/sub>\u00a0= Enthalpy at Point 2<\/p>\n

Given an example;
\nFind the enthalpy at constant pressure when the enthalpy at point 1 is 20 and the enthalpy at point 2 is 28.<\/p>\n

This implies that;<\/p>\n

h1<\/sub> = Enthalpy at Point 1 = 20
\nh2<\/sub> = Enthalpy at Point 2 = 28<\/p>\n

Q = h2<\/sub>\u00a0– h1<\/sub>
\nThat is, Q = 28 – 20
\nQ = 8<\/p>\n

Therefore, the\u00a0enthalpy at constant pressure\u00a0<\/strong>is\u00a08 J\/Kg.<\/strong><\/p>\n

Calculating the Enthalpy at Point 1 when the Enthalpy at Constant Pressure and the Enthalpy at Point 2 are Given<\/strong><\/h3>\n

h1<\/sub> = h2<\/sub> – Q<\/p>\n

Where:<\/p>\n

h1<\/sub>\u00a0= Enthalpy at Point 1
\nQ = Enthalpy at Constant Pressure
\nh2<\/sub>\u00a0= Enthalpy at Point 2<\/p>\n

Let’s solve an example;
\nFind the enthalpy at point 1 when the enthalpy at constant pressure is 12 and the enthalpy at point 2 is 32.<\/p>\n

This implies that;<\/p>\n

Q = Enthalpy at Constant Pressure = 12
\nh2<\/sub> = Enthalpy at Point 2 = 32<\/p>\n

h1<\/sub> = h2<\/sub> – Q
\nThen, h1<\/sub> = 32 – 12
\nh1<\/sub> = 20<\/p>\n

Therefore, the\u00a0enthalpy at point 1\u00a0<\/strong>is\u00a020 J\/Kg.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Work of Evapouration | Enthalpy<\/a><\/p>\n

Calculatint the Enthalpy at Point 2 when the Enthalpy at Constant Pressure and the Enthalpy at Point 1 are Given<\/strong><\/h3>\n

h2<\/sub> = Q + h1<\/sub><\/p>\n

Where:<\/p>\n

h2<\/sub>\u00a0= Enthalpy at Point 2
\nQ = Enthalpy at Constant Pressure
\nh1<\/sub> = Enthalpy at Point 1<\/p>\n

Let’s solve an example;
\nGiven that the enthalpy at point 1 is 12 and the enthalpy at constant pressure is 10. Find the Enthalpy at point 2?<\/p>\n

This implies that;<\/p>\n

Q = Enthalpy at Constant Pressure = 10
\nh1<\/sub> = Enthalpy at Point 1 = 12<\/p>\n

So, h2<\/sub> = Q + h1<\/sub>
\nh2<\/sub> = 10 + 12
\nh2<\/sub> = 22<\/p>\n

Therefore, the\u00a0enthalpy at point 2\u00a0<\/strong>is\u00a022J\/Kg.<\/strong><\/p>\n

How to Calculate Enthalpy at Constant Pressure Heating or Cooling With Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the enthalpy at constant pressure heating or cooling.<\/p>\n

\n

To get the answer and workings of the enthalpy at constant pressure heating or cooling using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><\/p>\n

Apple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Materials and Metallurgical\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n<\/div>\n

<\/p>\n

Now, Click on\u00a0Chemical Reaction Thermodynamics<\/strong>\u00a0<\/b>under\u00a0Materials and Metallurgical<\/strong><\/p>\n

\"\"<\/p>\n

So, Click on Enthalpy<\/strong>\u00a0under\u00a0Chemical Reaction Thermodynamics
\n<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Enthalpy at Constant Pressure Heating or Cooling <\/strong>under\u00a0Enthalpy<\/strong><\/p>\n

\"\"<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the enthalpy at constant pressure heating or cooling according to the respective parameter which is the Enthalpy at Point 1 (h1<\/sub>)<\/strong> and Enthalpy at Point 2 (h2<\/sub>).<\/strong><\/p>\n

\"How<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the Enthalpy at Point 1 (h1<\/sub>)\u00a0<\/strong>is\u00a020<\/strong> and Enthalpy at Point 2 (h2<\/sub>)<\/strong> is 28<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How<\/p>\n

As you can see from\u00a0the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia can calculate the enthalpy at constant pressure heating or cooling and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The enthalpy at constant pressure heating or cooling is illustrated by the image below. To calculate enthalpy at…","protected":false},"author":5,"featured_media":15676,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[1982,60,1981,2017,2015,2016],"class_list":["post-7150","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-chemical-reaction-thermodynamics","tag-engineering","tag-enthalpy","tag-enthalpy-at-constant-pressure-heating-or-cooling","tag-enthalpy-at-point-1","tag-enthalpy-at-point-2","cs-entry"],"yoast_head":"\nHow 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