{"id":6856,"date":"2021-12-11T10:47:41","date_gmt":"2021-12-11T09:47:41","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=6856"},"modified":"2024-05-21T07:51:31","modified_gmt":"2024-05-21T06:51:31","slug":"how-to-calculate-and-solve-for-risk-of-rupture-polymer-deformation","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2021\/12\/11\/how-to-calculate-and-solve-for-risk-of-rupture-polymer-deformation\/","title":{"rendered":"How to Calculate and Solve for Risk of Rupture | Polymer Deformation"},"content":{"rendered":"

\"\"<\/p>\n

The image above represents risk of rupture. To calculate risk of rupture, four essential parameters are needed and these parameters are Applied Stress (\u03c3), Stress below Zero Probability of Failure (\u03c3u<\/sub>), Characteristic Strength (\u03c3o<\/sub>) <\/strong>and Weibull Modulus (m).<\/strong><\/p>\n

The formula for calculating risk of rupture:<\/strong><\/h3>\n

R = (\u03c3 – \u03c3u<\/sub><\/sup> \/ \u03c3o<\/sub>)m<\/sup><\/p>\n

Where:<\/p>\n

R = Risk of Rupture
\n\u03c3 = Applied Stress
\n\u03c3u<\/sub> = Stress below Zero Probability of Failure
\nAnd also, \u03c3o<\/sub> = Characteristic Strength
\nm = Weibull Modulus<\/p>\n

Let’s solve an example;
\nFind the risk of rupture when the applied stress is 14, the stress below zero proability of failure is 7, the characteristic strength is 18 and the weibull modulus is 2.<\/p>\n

This implies that;<\/p>\n

\u03c3 = Applied Stress = 14
\n\u03c3u<\/sub> = Stress below Zero Probability of Failure = 7
\nAnd then, \u03c3o<\/sub> = Characteristic Strength = 18
\nm = Weibull Modulus = 2<\/p>\n

R = (\u03c3 – \u03c3u<\/sub><\/sup> \/ \u03c3o<\/sub>)m<\/sup>
\nR = (14 – 7<\/sup> \/ 18<\/sub>)2<\/sup>
\nThat is, R = (7<\/sup> \/ 18<\/sub>)2<\/sup>
\nR = (0.388)2<\/sup>
\nR = 0.151<\/p>\n

Therefore, the risk of rupture <\/strong>is 0.151.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Surface Roughness Parameter I Polymer Deformation<\/a><\/p>\n

How to Calculate the Risk of Rupture With Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the risk of rupture.<\/p>\n

\n

To get the answer and workings of the risk of rupture using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe <\/strong>to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><\/p>\n

Apple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Materials and Metallurgical\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n<\/div>\n

<\/p>\n

Now, Click on Polymer Deformation <\/b>under\u00a0Materials and Metallurgical<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Risk of Rupture<\/strong> under Polymer Deformation
\n<\/strong><\/p>\n

\"\"<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the risk of rupture according to the respective parameter which is the Applied Stress (\u03c3), Stress below Zero Probability of Failure (\u03c3u<\/sub>), Characteristic Strength (\u03c3o<\/sub>) <\/strong>and Weibull Modulus (m).<\/strong><\/p>\n

\"\"<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the\u00a0 Applied Stress (\u03c3)<\/strong> is 14<\/strong>, Stress below Zero Probability of Failure (\u03c3u<\/sub>)<\/strong> is 7<\/strong>, Characteristic Strength (\u03c3o<\/sub>)<\/strong> is 18 <\/strong>and Weibull Modulus (m)<\/strong> is 2<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How
\n\"How<\/p>\n

As you can see from\u00a0the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the risk of rupture and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents risk of rupture. To calculate risk of rupture, four essential parameters are needed and…","protected":false},"author":5,"featured_media":15515,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[1945,1947,60,543,1935,1949,1946,1948],"class_list":["post-6856","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-applied-stress","tag-characteristic-strength","tag-engineering","tag-materials-and-metallurgical","tag-polymer-deformation","tag-risk-of-rupture","tag-stress-below-zero-probability-of-failure","tag-weibull-modulus","cs-entry"],"yoast_head":"\nHow to Calculate and Solve for Risk of Rupture | Polymer Deformation<\/title>\n<meta name=\"description\" content=\"These are the steps and the formula on How to Calculate and Solve for Risk of Rupture. 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