{"id":6540,"date":"2021-11-23T10:43:15","date_gmt":"2021-11-23T09:43:15","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=6540"},"modified":"2024-05-17T10:51:56","modified_gmt":"2024-05-17T09:51:56","slug":"how-to-calculate-and-solve-for-newtons-drag-force-for-turbulent-resistance-mineral-processing","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2021\/11\/23\/how-to-calculate-and-solve-for-newtons-drag-force-for-turbulent-resistance-mineral-processing\/","title":{"rendered":"How to Calculate and Solve for Newton&#8217;s Drag Force for Turbulent Resistance | Mineral Processing"},"content":{"rendered":"<p><img decoding=\"async\" class=\"alignnone size-full wp-image-6546\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/newtons-drag-force-for-turbulent-resistance.jpg\" alt=\"\" width=\"249\" height=\"202\" \/><\/p>\n<p>The image above represents newton&#8217;s drag force for turbulent resistance. To calculate newton&#8217;s drag force for turbulent resistance, three essential parameters are needed and these parameters are <strong>Particle Diameter (d), Terminal Velocity (v) <\/strong>and <strong>Density of Fluid (\u03c1<sub>f<\/sub>).<\/strong><\/p>\n<h3><strong>The formula for calculating newton&#8217;s drag force for turbulent resistance:<\/strong><\/h3>\n<p>D = 0.055\u03c0.d\u00b2v\u00b2\u03c1<sub>f<\/sub><\/p>\n<p>Where:<\/p>\n<p>D = Newton&#8217;s Drag Force for Turbulent Resistance<br \/>\nd = Particle Diameter<br \/>\nv = Terminal Velocity<br \/>\n\u03c1<sub>f<\/sub> = Density of Fluid<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the newton&#8217;s drag force for turbulent resistance when the particle diameter is 8, the terminal velocity is 4 and the density of fluid is 2.<\/p>\n<p>This implies that;<\/p>\n<p>d = Particle Diameter = 8<br \/>\nv = Terminal Velocity = 4<br \/>\n\u03c1<sub>f<\/sub> = Density of Fluid = 2<\/p>\n<p>D = 0.055\u03c0.d\u00b2v\u00b2\u03c1<sub>f<\/sub><br \/>\nD = 0.055\u03c0.(8)\u00b2(4)\u00b2(2)<br \/>\nThat is, D = 0.055\u03c0.(64)(16)(2)<br \/>\nD = 0.055\u03c0.(2048)<br \/>\nD = 353.86<\/p>\n<p>Therefore, the <strong>newton&#8217;s drag force for turbulent resistance <\/strong>is <strong>353.86 N.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2021\/11\/23\/how-to-calculate-and-solve-for-velocity-at-turbulent-flow-mineral-processing\/\">How to Calculate and Solve for Velocity at Turbulent Flow | Mineral Processing<\/a><\/p>\n<h3><strong>Calculating the Particle Diameter when the Newton&#8217;s Drag Force for Turbulent Resistance, the Terminal Velocity and the Density of Fluid are Given<\/strong><\/h3>\n<p>d = \u221a(<sup>D<\/sup> \/ <sub>0.055\u03c0.v\u00b2\u03c1<sub>f<\/sub><\/sub>)<\/p>\n<p>Where:<\/p>\n<p>d = Particle Diameter<br \/>\nD = Newton&#8217;s Drag Force for Turbulent Resistance<br \/>\nv = Terminal Velocity<br \/>\n\u03c1<sub>f<\/sub> = Density of Fluid<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the particle diameter when the newton&#8217;s drag force for turbulent resistance is 42, the terminal velocity is 2 and the density of fluid is 4.<\/p>\n<p>This implies that;<\/p>\n<p>D = Newton&#8217;s Drag Force for Turbulent Resistance = 42<br \/>\nv = Terminal Velocity = 2<br \/>\n\u03c1<sub>f<\/sub> = Density of Fluid = 4<\/p>\n<p>d = \u221a(<sup>D<\/sup> \/ <sub>0.055\u03c0.v\u00b2\u03c1<sub>f<\/sub><\/sub>)<br \/>\nThat is, d = \u221a(<sup>42<\/sup> \/ <sub>0.055\u03c0.(2\u00b2)(4)<\/sub>)<br \/>\nd = \u221a(<sup>42<\/sup> \/ <sub>0.055\u03c0.16<\/sub>)<br \/>\nd = \u221a(<sup>42<\/sup> \/ <sub>2.76<\/sub>)<br \/>\nSo, d = \u221a15.2<br \/>\nd = 3.89<\/p>\n<p>Therefore, the <strong>particle diameter <\/strong>is <strong>3.89.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2021\/11\/23\/how-to-calculate-and-solve-for-velocity-of-fine-particles-mineral-processing\/\">How to Calculate and Solve for Velocity of Fine Particles | Mineral Processing<\/a><\/p>\n<h3><strong>Calculating the Terminal Velocity when the Newton&#8217;s Drag Force for Turbulent Resistance, the Particle Diameter and the Density of Fluid are Given<\/strong><\/h3>\n<p>v = \u221a(<sup>D<\/sup> \/ <sub>0.055\u03c0.d\u00b2\u03c1<sub>f<\/sub><\/sub>)<\/p>\n<p>Where:<\/p>\n<p>v = Terminal Velocity<br \/>\nD = Newton&#8217;s Drag Force for Turbulent Resistance<br \/>\nd = Particle Diameter<br \/>\n\u03c1<sub>f<\/sub> = Density of Fluid<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the terminal velocity when the newton&#8217;s drag force for turbulent resistance is 50, the particle diameter is 5 and the density of fluid is 2.<\/p>\n<p>This implies that;<\/p>\n<p>D = Newton&#8217;s Drag Force for Turbulent Resistance = 50<br \/>\nd = Particle Diameter = 5<br \/>\n\u03c1<sub>f<\/sub> = Density of Fluid = 2<\/p>\n<p>v = \u221a(<sup>D<\/sup> \/ <sub>0.055\u03c0.d\u00b2\u03c1<sub>f<\/sub><\/sub>)<br \/>\nThen, v = \u221a(<sup>50<\/sup> \/ <sub>0.055\u03c0.(5\u00b2)(2)<\/sub>)<br \/>\nv = \u221a(<sup>50<\/sup> \/ <sub>0.055\u03c0.50<\/sub>)<br \/>\nv = \u221a(<sup>50<\/sup> \/ <sub>8.64<\/sub>)<br \/>\nSo, v = \u221a5.78<br \/>\nv = 2.40<\/p>\n<p>Therefore, the <strong>terminal velocity <\/strong>is <strong>2.40.<\/strong><\/p>\n<h3><strong>Calculating the Density of Fluid when the Newton&#8217;s Drag Force for Turbulent Resistance, the Particle Diameter and the Terminal Velocity are Given<\/strong><\/h3>\n<p>\u03c1<sub>f<\/sub> = <sup>D<\/sup> \/ <sub>0.055\u03c0.d\u00b2v\u00b2<\/sub><\/p>\n<p>Where:<\/p>\n<p>\u03c1<sub>f<\/sub> = Density of Fluid<br \/>\nD = Newton&#8217;s Drag Force for Turbulent Resistance<br \/>\nd = Particle Diameter<br \/>\nv = Terminal Velocity<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the density of fluid when the newton&#8217;s drag force for turbulent resistance is 35, the particle diameter is 6 and the terminal velocity is 3.<\/p>\n<p>This implies that;<\/p>\n<p>D = Newton&#8217;s Drag Force for Turbulent Resistance = 35<br \/>\nd = Particle Diameter = 6<br \/>\nv = Terminal Velocity = 3<\/p>\n<p>\u03c1<sub>f<\/sub> = <sup>D<\/sup> \/ <sub>0.055\u03c0.d\u00b2v\u00b2<\/sub><br \/>\nThis means, \u03c1<sub>f<\/sub> = <sup>35<\/sup> \/ <sub>0.055\u03c0.(6\u00b2)(3\u00b2)<\/sub><br \/>\n\u03c1<sub>f<\/sub> = <sup>35<\/sup> \/ <sub>0.055\u03c0.(36)(9)<\/sub><br \/>\n\u03c1<sub>f<\/sub> = <sup>35<\/sup> \/ <sub>0.055\u03c0.324<\/sub><br \/>\nSo, \u03c1<sub>f<\/sub> = <sup>35<\/sup> \/ <sub>55.9<\/sub><br \/>\n\u03c1<sub>f<\/sub> = 0.626<\/p>\n<p>Therefore, the <strong>density of fluid <\/strong>is <strong>0.626.<\/strong><\/p>\n<h3><strong>How to Calculate Newton&#8217;s Drag Force for Turbulent Resistance Using Nickzom Calculator<\/strong><\/h3>\n<p>Nickzom Calculator \u2013\u00a0<strong>The Calculator Encyclopedia<\/strong> is capable of calculating the newton&#8217;s drag force for turbulent resistance.<\/p>\n<div>\n<p>To get the answer and workings of the newton&#8217;s drag force for turbulent resistance using the <strong>Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n<p>You can get this app via any of these means:<\/p>\n<p><strong>Web<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator-plus\">https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n<p>To get access to the\u00a0<strong>professional\u00a0<\/strong>version via web, you need to\u00a0<strong>register<\/strong>\u00a0and\u00a0<strong>subscribe <\/strong>to have utter access to all functionalities.<br \/>\nYou can also try the\u00a0<strong>demo\u00a0<\/strong>version via\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator\">https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n<p><strong>Android (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a><br \/>\n<strong>Android (Free)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><\/p>\n<p><strong>Apple (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8\">https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a><br \/>\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0<strong>Calculator Map,\u00a0<\/strong>then click on\u00a0<b>Materials and Metallurgical\u00a0<\/b>under\u00a0<strong>Engineering<\/strong><strong>.<\/strong><\/p>\n<\/div>\n<p><img decoding=\"async\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/07\/Screenshot-2.png\" \/><\/p>\n<p>Now, Click on <b>Mineral Processing <\/b>under\u00a0<strong>Materials and Metallurgical<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6417 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-265.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-265.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-265-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-265-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-265-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, Click on <strong>Newton&#8217;s Drag Force for Turbulent Resistance<\/strong> under <strong>Mineral Processing<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6553 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-337.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-337.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-337-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-337-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-337-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>The screenshot below displays the page or activity to enter your values, to get the answer for the newton&#8217;s drag force for turbulent resistance according to the respective parameter which is the <strong>Particle Diameter (d), Terminal Velocity (v) <\/strong>and <strong>Density of Fluid (\u03c1<sub>f<\/sub>).<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6554 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-338.png\" alt=\"How to Calculate and Solve for Newton's Drag Force for Turbulent Resistance | Mineral Processing\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-338.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-338-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-338-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-338-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, enter the values appropriately and accordingly for the parameters as required by the\u00a0<strong>Particle Diameter (d)<\/strong> is <strong>8<\/strong>,<strong> Terminal Velocity (v)<\/strong> is <strong>4 <\/strong>and <strong>Density of Fluid (\u03c1<sub>f<\/sub>)<\/strong> is <strong>2<\/strong>.<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6555 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-342.png\" alt=\"How to Calculate and Solve for Newton's Drag Force for Turbulent Resistance | Mineral Processing\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-342.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-342-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-342-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-342-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Finally, Click on Calculate<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6556 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-343.png\" alt=\"How to Calculate and Solve for Newton's Drag Force for Turbulent Resistance | Mineral Processing\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-343.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-343-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-343-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-343-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><br \/>\n<img decoding=\"async\" class=\"alignnone wp-image-6557 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-344.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-344.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-344-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-344-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/11\/Screenshot-344-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>As you can see from\u00a0the screenshot above,\u00a0<strong>Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the newton&#8217;s drag force for turbulent resistance and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents newton&#8217;s drag force for turbulent resistance. To calculate newton&#8217;s drag force for turbulent resistance,&hellip;","protected":false},"author":5,"featured_media":15349,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[714,60,543,1823,1856,830,1855],"class_list":["post-6540","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-density-of-fluid","tag-engineering","tag-materials-and-metallurgical","tag-mineral-processing","tag-newtons-drag-force","tag-particle-diameter","tag-terminal-velocity","cs-entry"],"yoast_head":"<!-- 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