{"id":6351,"date":"2021-10-02T08:53:00","date_gmt":"2021-10-02T07:53:00","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=6351"},"modified":"2024-05-16T16:44:38","modified_gmt":"2024-05-16T15:44:38","slug":"how-to-calculate-and-solve-for-flow-rate-darcys-law-transport-phenomena","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2021\/10\/02\/how-to-calculate-and-solve-for-flow-rate-darcys-law-transport-phenomena\/","title":{"rendered":"How to Calculate and Solve for Flow Rate | Darcy&#8217;s Law | Transport Phenomena"},"content":{"rendered":"<p><img decoding=\"async\" class=\"alignnone size-full wp-image-6378\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/flow-rate.png\" alt=\"\" width=\"291\" height=\"173\" \/><\/p>\n<p>The image above represents flow rate. To calculate flow rate, four essential parameters are needed and these parameters are <strong>Permeability (K), Cross-Sectional Area (A), Change in Pressure (\u0394P) <\/strong>and <strong>Length of Pipe (L).<\/strong><\/p>\n<h3><strong>The formula for calculating flow rate:<\/strong><\/h3>\n<p>Q = <sup>KA\u0394P<\/sup> \/ <sub>L<\/sub><\/p>\n<p>Where:<\/p>\n<p>Q = Flow Rate | Darcy&#8217;s Law<br \/>\nK = Permeability<br \/>\nA = Cross-sectional Area<br \/>\n\u0394P = Change in Pressure<br \/>\nL = Length of Pipe<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the flow rate when the permeability is 9, the cross-sectional area is 12, the change in pressure is 3 and the length of pipe is 10.<\/p>\n<p>This implies that;<\/p>\n<p>K = Permeability = 9<br \/>\nA = Cross-sectional Area = 12<br \/>\n\u0394P = Change in Pressure = 3<br \/>\nL = Length of Pipe = 10<\/p>\n<p>Q = <sup>KA\u0394P<\/sup> \/ <sub>L<\/sub><br \/>\nQ = <sup>(9)(12)(3)<\/sup> \/ <sub>10<\/sub><br \/>\nThat is, Q = <sup>324<\/sup> \/ <sub>10<\/sub><br \/>\nQ = 32.4<\/p>\n<p>Therefore, the <strong>flow rate <\/strong>is <strong>32.4 m\u00b3\/s.<\/strong><\/p>\n<h3><strong>Calculating the Permeability when the Flow Rate, the Cross-Sectional Area, the Change in Pressure and the Length of Pipe are Given<\/strong><\/h3>\n<p>K = <sup>Q x L<\/sup> \/ <sub>A\u0394P<\/sub><\/p>\n<p>Where:<\/p>\n<p>K = Permeability<br \/>\nQ = Flow Rate | Darcy&#8217;s Law<br \/>\nA = Cross-sectional Area<br \/>\n\u0394P = Change in Pressure<br \/>\nL = Length of Pipe<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the permeability when the flow rate is 14, the cross-sectional area is 4, the change in pressure is 7 and the length of pipe is 2.<\/p>\n<p>This implies that;<\/p>\n<p>Q = Flow Rate | Darcy&#8217;s Law = 14<br \/>\nA = Cross-sectional Area = 4<br \/>\n\u0394P = Change in Pressure = 7<br \/>\nL = Length of Pipe = 2<\/p>\n<p>K = <sup>Q x L<\/sup> \/ <sub>A\u0394P<\/sub><br \/>\nThen, K = <sup>14 x 2<\/sup> \/ <sub>(4)(7)<\/sub><br \/>\nK = <sup>28<\/sup> \/ <sub>28<\/sub><br \/>\nK = 1<\/p>\n<p>Therefore, the <strong>permeability <\/strong>is<strong> 1.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2021\/08\/01\/how-to-calculate-and-solve-for-permeability-mass-transfer\/\">How to Calculate and Solve for Permeability | Mass Transfer<\/a><\/p>\n<h3><strong>Calculating the Cross-Sectional Area when the Flow Rate, the Permeability, the Change in Pressure and the Length of Pipe are Given<\/strong><\/h3>\n<p>A = <sup>Q x L<\/sup> \/ <sub>K\u0394P<\/sub><\/p>\n<p>Where:<\/p>\n<p>A = Cross-sectional Area<br \/>\nQ = Flow Rate | Darcy&#8217;s Law<br \/>\nK = Permeability<br \/>\n\u0394P = Change in Pressure<br \/>\nL = Length of Pipe<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the cross-sectional area when the flow rate is 10, the permeability is 6, the change in pressure is 5 and the length of pipe is 12.<\/p>\n<p>This implies that;<\/p>\n<p>Q = Flow Rate | Darcy&#8217;s Law = 10<br \/>\nK = Permeability = 6<br \/>\n\u0394P = Change in Pressure = 5<br \/>\nL = Length of Pipe = 12<\/p>\n<p>A = <sup>Q x L<\/sup> \/ <sub>K\u0394P<\/sub><br \/>\nSo, A = <sup>10 x 12<\/sup> \/ <sub>(6)(5)<\/sub><br \/>\nA = <sup>120<\/sup> \/ <sub>30<\/sub><br \/>\nA = 4<\/p>\n<p>Therefore, the <strong>cross-sectional area <\/strong>is <strong>4.<\/strong><\/p>\n<h3><strong>Calculating the Change in Pressure when the Flow Rate, the Permeability, the Cross-Sectional Area and the Length of Pipe are Given<\/strong><\/h3>\n<p>\u0394P = <sup>Q x L<\/sup> \/ <sub>KA<\/sub><\/p>\n<p>Where:<\/p>\n<p>\u0394P = Change in Pressure<br \/>\nQ = Flow Rate | Darcy&#8217;s Law<br \/>\nK = Permeability<br \/>\nA = Cross-sectional Area<br \/>\nL = Length of Pipe<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the change in pressure when the flow rate is 24, the permeability is 4, the cross-sectional area is 6 and the length of pipe is 2.<\/p>\n<p>This implies that;<\/p>\n<p>Q = Flow Rate | Darcy&#8217;s Law = 24<br \/>\nK = Permeability = 4<br \/>\nA = Cross-sectional Area = 6<br \/>\nL = Length of Pipe = 2<\/p>\n<p>\u0394P = <sup>Q x L<\/sup> \/ <sub>KA<\/sub><br \/>\n\u0394P = <sup>24 x 2<\/sup> \/ <sub>(4)(6)<\/sub><br \/>\nSo, \u0394P = <sup>48<\/sup> \/ <sub>24<\/sub><br \/>\n\u0394P = 2<\/p>\n<p>Therefore, the <strong>change in pressure <\/strong>is <strong>2.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2020\/02\/16\/how-to-calculate-and-solve-for-entrance-velocity-darcys-law-water-budget\/\">How to Calculate and Solve for Entrance Velocity | Darcy&#8217;s Law | Water Budget<\/a><\/p>\n<h3><strong>Calculating the Length of Pipe when the Flow Rate, the Permeability, the Cross-Sectional Area and the Change in Pressure are Given<\/strong><\/h3>\n<p>L = <sup>KA\u0394P<\/sup> \/ <sub>Q<\/sub><\/p>\n<p>Where:<\/p>\n<p>L = Length of Pipe<br \/>\nQ = Flow Rate | Darcy&#8217;s Law<br \/>\nK = Permeability<br \/>\nA = Cross-sectional Area<br \/>\n\u0394P = Change in Pressure<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the length of pipe when the flow rate is 10, the permeability is 8, the cross-sectional area is 3 and the change in pressure is 5.<\/p>\n<p>This implies that;<\/p>\n<p>Q = Flow Rate | Darcy&#8217;s Law = 10<br \/>\nK = Permeability = 8<br \/>\nA = Cross-sectional Area = 3<br \/>\n\u0394P = Change in Pressure = 5<\/p>\n<p>L = <sup>KA\u0394P<\/sup> \/ <sub>Q<\/sub><br \/>\nL = <sup>(8)(3)(5)<\/sup> \/ <sub>10<\/sub><br \/>\nThat is, L = <sup>120<\/sup> \/ <sub>10<\/sub><br \/>\nL = 12<\/p>\n<p>Therefore, the <strong>length of pipe <\/strong>is <strong>12.<\/strong><\/p>\n<h3><strong>How to Calculate Flow Rate | Darcy&#8217;s Law Using Nickzom Calculator<\/strong><\/h3>\n<p>Nickzom Calculator \u2013\u00a0<strong>The Calculator Encyclopedia<\/strong> is capable of calculating the flow rate.<\/p>\n<div>\n<p>To get the answer and workings of the flow rate using the <strong>Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n<p>You can get this app via any of these means:<\/p>\n<p><strong>Web<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator-plus\">https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n<p>To get access to the\u00a0<strong>professional\u00a0<\/strong>version via web, you need to\u00a0<strong>register<\/strong>\u00a0and\u00a0<strong>subscribe <\/strong>to have utter access to all functionalities.<br \/>\nYou can also try the\u00a0<strong>demo\u00a0<\/strong>version via\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator\">https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n<p><strong>Android (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a><br \/>\n<strong>Android (Free)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><\/p>\n<p><strong>Apple (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8\">https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a><br \/>\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0<strong>Calculator Map,\u00a0<\/strong>then click on\u00a0<b>Materials and Metallurgical\u00a0<\/b>under\u00a0<strong>Engineering<\/strong><strong>.<\/strong><\/p>\n<\/div>\n<p><img decoding=\"async\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/07\/Screenshot-2.png\" \/><\/p>\n<p>Now, Click on <b>Transport Phenomena <\/b>under\u00a0<strong>Materials and Metallurgical<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6204 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/09\/Screenshot-151.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/09\/Screenshot-151.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/09\/Screenshot-151-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/09\/Screenshot-151-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/09\/Screenshot-151-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, Click on <strong>Flow Rate <\/strong>under <strong>Transport Phenomena<br \/>\n<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6387 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-245.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-245.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-245-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-245-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-245-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>The screenshot below displays the page or activity to enter your values, to get the answer for the flow rate according to the respective parameter which is the\u00a0<strong>Permeability (K), Cross-Sectional Area (A), Change in Pressure (\u0394P) <\/strong>and <strong>Length of Pipe (L).<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6388 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-246.png\" alt=\"How to Calculate and Solve for Flow Rate | Darcy's Law | Transport Phenomena\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-246.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-246-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-246-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-246-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, enter the values appropriately and accordingly for the parameters as required by the\u00a0<strong>Permeability (K)<\/strong> is <strong>9<\/strong>,<strong> Cross-Sectional Area (A)<\/strong> is <strong>12<\/strong>,<strong> Change in Pressure (\u0394P)<\/strong> is <strong>3 <\/strong>and <strong>Length of Pipe (L)<\/strong> is <strong>10<\/strong>.<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6389 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-247.png\" alt=\"How to Calculate and Solve for Flow Rate | Darcy's Law | Transport Phenomena\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-247.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-247-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-247-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-247-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Finally, Click on Calculate<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-6390 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-248.png\" alt=\"How to Calculate and Solve for Flow Rate | Darcy's Law | Transport Phenomena\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-248.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-248-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-248-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-248-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><br \/>\n<img decoding=\"async\" class=\"alignnone wp-image-6391 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-249.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-249.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-249-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-249-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2021\/10\/Screenshot-249-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>As you can see from\u00a0the screenshot above,\u00a0<strong>Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the flow rate and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents flow rate. To calculate flow rate, four essential parameters are needed and these parameters&hellip;","protected":false},"author":5,"featured_media":15260,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[972,294,60,1814,1811,543,549,1775],"class_list":["post-6351","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-change-in-pressure","tag-cross-sectional-area","tag-engineering","tag-flow-rate","tag-length-of-pipe","tag-materials-and-metallurgical","tag-permeability","tag-transport-phenomena","cs-entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.0 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>How to Calculate and Solve for Flow Rate | Darcy&#039;s Law | Transport Phenomena<\/title>\n<meta name=\"description\" content=\"Here are the steps and the formula on How to Calculate Flow Rate | Darcy&#039;s Law in Transport Phenomena. 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