{"id":6115,"date":"2021-09-23T03:38:12","date_gmt":"2021-09-23T02:38:12","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=6115"},"modified":"2024-05-13T15:51:42","modified_gmt":"2024-05-13T14:51:42","slug":"how-to-calculate-and-solve-for-thermal-conductivity-of-gases-energy-transport","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2021\/09\/23\/how-to-calculate-and-solve-for-thermal-conductivity-of-gases-energy-transport\/","title":{"rendered":"How to Calculate and Solve for Thermal Conductivity of Gases | Energy Transport"},"content":{"rendered":"

\"\"<\/p>\n

The image above represents thermal conductivity of gases. To calculate thermal conductivity of gases, four essential parameters are needed and these parameters are Viscosity (\u03b7), Heat Capacity at Constant Pressure (cp<\/sub>), Gas Constant (R)<\/strong> and Molar Mass of Gas (M).<\/strong><\/p>\n

The formula for calculating thermal conductivity of gases:<\/strong><\/h3>\n

k = \u03b7(cp<\/sub> + 1.25R<\/sup>\/M<\/sub>)<\/p>\n

Where:<\/p>\n

k = Thermal Conductivity of Gases
\n\u03b7 = Viscosity
\ncp<\/sub> = Heat Capacity at Constant Pressure
\nR = Gas Constant
\nM = Molar Mass of Gas<\/p>\n

Let’s solve an example;
\nFind the thermal conductivity of gases when the viscosity is 12, the heat capacity at constant pressure is 18, the gas constant is 22 and the molar mass of gas is 14.<\/p>\n

This implies that;<\/p>\n

\u03b7 = Viscosity = 12
\ncp<\/sub> = Heat Capacity at Constant Pressure = 18
\nR = Gas Constant = 22
\nM = Molar Mass of Gas = 14<\/p>\n

k = \u03b7(cp<\/sub> + 1.25R<\/sup>\/M<\/sub>)
\nThat is, k = 12(18 + 1.25(22)<\/sup>\/14<\/sub>)
\nk = 12(18 + 27.5<\/sup>\/14<\/sub>)
\nk = 12(18 + 1.96)
\nSo, k = 12(19.96)
\nk = 239.57<\/p>\n

Therefore, the thermal conductivity of gases <\/strong>is 239.57 W\/mK.<\/strong><\/p>\n

Calculating the Viscosity when the Thermal Conductivity of Gases, the Heat Capacity at Constant Pressure, the Gas Constant and the Molar Mass of Gas are Given<\/strong><\/h3>\n

\u03b7 = k<\/sup> \/ (cp<\/sub> + 1.25R<\/sup> \/ M<\/sub>)<\/sub><\/p>\n

Where:<\/p>\n

\u03b7 = Viscosity
\nk = Thermal Conductivity of Gases
\ncp<\/sub> = Heat Capacity at Constant Pressure
\nR = Gas Constant
\nM = Molar Mass of Gas<\/p>\n

Let’s solve an example;
\nFind the viscosity when the thermal conductivity of gases is 40, the heat capacity at constant pressure is 22, the gas constant is 2 and the molar mass of gas is 8.<\/p>\n

This implies that;<\/p>\n

k = Thermal Conductivity of Gases = 40
\ncp<\/sub> = Heat Capacity at Constant Pressure = 22
\nR = Gas Constant = 2
\nM = Molar Mass of Gas = 8<\/p>\n

\u03b7 = k<\/sup> \/ (cp<\/sub> + 1.25R<\/sup> \/ M<\/sub>)<\/sub>
\n\u03b7 = 40<\/sup> \/ (22 + 1.25(2)<\/sup> \/ 8<\/sub>)<\/sub>
\nSo, \u03b7 = 40<\/sup> \/ (22 + 2.5<\/sup> \/ 8<\/sub>)<\/sub>
\n\u03b7 = 40<\/sup> \/ (22 + 0.313)<\/sub>
\nThat is, \u03b7 = 40<\/sup> \/ 22.313<\/sub>
\n\u03b7 = 1.79<\/p>\n

Therefore, the viscosity <\/strong>is 1.79.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Thermal Conductivity | Heat Capacity per Unit Volume | Energy Transport<\/a><\/p>\n

Calculating the Heat Capacity at Constant Pressure when the Thermal Conductivity of Gases, the Viscosity, the Gas Constant and the Molar Mass of Gas are Given<\/strong><\/h3>\n

cp<\/sub> = k\u03b7 – (1.25R<\/sup> \/ M<\/sub>)<\/p>\n

Where:<\/p>\n

cp<\/sub> = Heat Capacity at Constant Pressure
\nk = Thermal Conductivity of Gases
\n\u03b7 = Viscosity
\nR = Gas Constant
\nM = Molar Mass of Gas<\/p>\n

Let’s solve an example;
\nFind the heat capacity at constant pressure when the thermal conductivity of gases is 20, the viscosity is 5, the gas constant is 4 and the molar mass of gas is 10.<\/p>\n

This implies that;<\/p>\n

k = Thermal Conductivity of Gases = 20
\n\u03b7 = Viscosity = 5
\nR = Gas Constant = 4
\nM = Molar Mass of Gas = 10<\/p>\n

cp<\/sub> = k\u03b7 – (1.25R<\/sup> \/ M<\/sub>)
\ncp<\/sub> = (20)(5) – (1.25(4)<\/sup> \/ 10<\/sub>)
\nSo, cp<\/sub> = 100 – (5<\/sup> \/ 10<\/sub>)
\ncp<\/sub> = 100 – 0.5
\ncp<\/sub> = 99.5<\/p>\n

Therefore, the heat capacity at constant pressure <\/strong>is 99.5<\/strong><\/p>\n

Calculating the Gas Constant when the Thermal Conductivity of Gases, the Viscosity, the Heat Capacity at Constant Pressure and the Molar Mass of Gas are Given<\/strong><\/h2>\n

R = (k\u03b7 – cp<\/sub>)M<\/sup> \/ 1.25<\/sub><\/p>\n

Where:<\/p>\n

R = Gas Constant
\nk = Thermal Conductivity of Gases
\n\u03b7 = Viscosity
\ncp<\/sub> = Heat Capacity at Constant Pressure
\nM = Molar Mass of Gas<\/p>\n

Let’s solve an example;
\nFind the gas constant when the thermal conductivity of gases is 14, the viscosity is 2, the heat capacity at constant pressure is 8 and the molar mass of gas is 12.<\/p>\n

This implies that;<\/p>\n

k = Thermal Conductivity of Gases = 14
\n\u03b7 = Viscosity = 2
\ncp<\/sub> = Heat Capacity at Constant Pressure = 8
\nM = Molar Mass of Gas = 12<\/p>\n

R = (k\u03b7 – cp<\/sub>)M<\/sup> \/ 1.25<\/sub>
\nThat is, R = (14(2) – 8)12<\/sup> \/ 1.25<\/sub>
\nR = (28 – 8)12<\/sup> \/ 1.25<\/sub>
\nR = (20)12<\/sup> \/ 1.25<\/sub>
\nSo, R = 240<\/sup> \/ 1.25<\/sub>
\nR = 192<\/p>\n

Therefore, the gas constant <\/strong>is 192.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Total Conductivity | Thermal Properties<\/a><\/p>\n

Calculating the Molar Mass of Gas when the Thermal Conductivity of Gases, the Viscosity, the Heat Capacity at Constant Pressure and the Gas Constant are Given<\/strong><\/h3>\n

M = 1.25R<\/sup> \/ (k\u03b7 – cp<\/sub>)<\/sub><\/p>\n

Where:<\/p>\n

M = Molar Mass of Gas
\nk = Thermal Conductivity of Gases
\n\u03b7 = Viscosity
\ncp<\/sub> = Heat Capacity at Constant Pressure
\nR = Gas Constant<\/p>\n

Let’s solve an example;
\nFind the molar mass of gas when the thermal conductivity of gases is 4, the viscosity is 6, the heat capacity at constant pressure is 3 and the gas constant is 9.<\/p>\n

This implies that;<\/p>\n

k = Thermal Conductivity of Gases = 4
\n\u03b7 = Viscosity = 6
\ncp<\/sub> = Heat Capacity at Constant Pressure = 3
\nR = Gas Constant = 9<\/p>\n

M = 1.25R<\/sup> \/ (k\u03b7 – cp<\/sub>)<\/sub>
\nM = 1.25(9)<\/sup> \/ (4(6) – 3)<\/sub>
\nSo, M = 11.25<\/sup> \/ (24 – 3)<\/sub>
\nM = 11.25<\/sup> \/ 21<\/sub>
\nM = 0.53<\/p>\n

Therefore, the molar mass of gas <\/strong>is 0.53.<\/strong><\/p>\n

How to Calculate Thermal Conductivity of Gases Using Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the thermal conductivity of gases.<\/p>\n

\n

To get the answer and workings of the thermal conductivity of gases using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 2,000\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><\/p>\n

Apple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Materials and Metallurgical\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n<\/div>\n

<\/p>\n

Now, Click on Energy Transport <\/b>under\u00a0Materials and Metallurgical<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Thermal Conductivity of Gases <\/strong>under Energy Transport
\n<\/strong><\/p>\n

\"\"<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the thermal conductivity of gases according to the respective parameter which is the Viscosity (\u03b7), Heat Capacity at Constant Pressure (cp<\/sub>), Gas Constant (R) and Molar Mass of Gas (M).<\/strong><\/p>\n

\"How<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the\u00a0Viscosity (\u03b7)<\/strong> is 12<\/strong>, Heat Capacity at Constant Pressure (cp<\/sub>)<\/strong> is 18<\/strong>, Gas Constant (R)<\/strong> is 22<\/strong> and Molar Mass of Gas (M)<\/strong> is 14<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How
\n\"\"<\/p>\n

As you can see from\u00a0the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the thermal conductivity of gases and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents thermal conductivity of gases. To calculate thermal conductivity of gases, four essential parameters are…","protected":false},"author":5,"featured_media":15152,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[1732,60,1639,1690,543,1736,1737,118],"class_list":["post-6115","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-energy-transport","tag-engineering","tag-gas-constant","tag-heat-capacity-at-constant-pressure","tag-materials-and-metallurgical","tag-molar-mass-of-gas","tag-thermal-conductivity-of-gases","tag-viscosity","cs-entry"],"yoast_head":"\nHow to Calculate and Solve for Thermal Conductivity of Gases | Energy Transport<\/title>\n<meta name=\"description\" content=\"Master the steps and the formula on How to Calculate Thermal Conductivity of Gases | Energy Transport. 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