{"id":4003,"date":"2020-09-29T03:18:40","date_gmt":"2020-09-29T02:18:40","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=4003"},"modified":"2024-04-18T14:14:32","modified_gmt":"2024-04-18T13:14:32","slug":"how-to-calculate-and-solve-for-discharge-soil-and-water-conservation","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/09\/29\/how-to-calculate-and-solve-for-discharge-soil-and-water-conservation\/","title":{"rendered":"How to Calculate and Solve for Discharge | Soil and Water Conservation"},"content":{"rendered":"

\"\"<\/p>\n

The image above represents discharge. To calculate discharge, six essential parameters are needed and these parameters are Permeability or Hydraulic conductivity of soil (k), Hydraulic head (h), Number of equipotential drops (Nd<\/sub>), Number of flow channel (Nf<\/sub>), Dimension of the field (b)\u00a0<\/strong>and\u00a0Dimension of the field (c).<\/strong><\/p>\n

The formula for calculating discharge;<\/p>\n

q =\u00a0k . h. b. Nf<\/sub><\/sup>\u00a0\/\u00a0Nd<\/sub>\u00a0. c<\/sub><\/p>\n

Where:<\/p>\n

q = Discharge
\nk = Permeability or Hydraulic Conductivity of Soil
\nh = Hydraulic Head
\nNd<\/sub>\u00a0= Number of Equipotential Drops
\nNf<\/sub>\u00a0= Number of Flow Channel
\nb = Dimension of the Field
\nc = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the discharge when the permeability or hydraulic conductivity of soil is 9, the hydraulic head is 12, the number of equipotential drops is 7, the number of flow channel is 10, the dimension of the field is 6 and the dimension of the field is 2.<\/p>\n

This implies that;<\/p>\n

k = Permeability or Hydraulic Conductivity of Soil = 9
\nh = Hydraulic Head = 12
\nNd<\/sub> = Number of Equipotential Drops = 7
\nNf<\/sub> = Number of Flow Channel = 10
\nb = Dimension of the Field = 6
\nc = Dimension of the Field = 2<\/p>\n

q =\u00a0k . h. b. Nf<\/sub><\/sup>\u00a0\/\u00a0Nd\u00a0. c<\/sub>
\nThen, q = (9)(12)(6)(10)<\/sup>\u00a0\/\u00a0(7)(2)<\/sub>
\nq =\u00a06480<\/sup>\u00a0\/\u00a014<\/sub>
\nq = 462.8<\/p>\n

Therefore, the discharge<\/strong>\u00a0<\/strong>is\u00a0462.8.<\/strong><\/p>\n

Calculating for Permeability or Hydraulic Conductivity of soil when the Discharge, the Hydraulic Head, the Number of Equipotential Drops, the Number of Flow Channel, the Dimension of the Field and the Dimension of the Field are Given<\/strong><\/h3>\n

k = q x (Nd<\/sub>.c)<\/sup> \/ h.b.Nf<\/sub><\/sub><\/p>\n

Where;<\/p>\n

k = Permeability or Hydraulic Conductivity of Soil
\nq = Discharge
\nh = Hydraulic Head
\nNd<\/sub>\u00a0= Number of Equipotential Drops
\nNf<\/sub>\u00a0= Number of Flow Channel
\nb = Dimension of the Field
\nc = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the permeability or hydraulic conductivity of soil when the discharge is 10, the hydraulic head is 7, the number of equipotential drops is 5, the number of flow channel is 4, the dimension of the field is 12 and the dimension of the field is 6.<\/p>\n

This implies that;<\/p>\n

q = Discharge = 10
\nh = Hydraulic Head = 7
\nNd<\/sub> = Number of Equipotential Drops = 5
\nNf<\/sub> = Number of Flow Channel = 4
\nb = Dimension of the Field = 12
\nc = Dimension of the Field = 6<\/p>\n

k = q x (Nd<\/sub>.c)<\/sup> \/ h.b.Nf<\/sub><\/sub>
\nThat is, k = 10 x (5)(6)<\/sup> \/ 7.12.4<\/sub>
\nk = 30<\/sup> \/ 336<\/sub>
\nk = 0.089<\/p>\n

Therefore, the\u00a0permeability or hydraulic conductivity of soil\u00a0<\/strong>is 0.089.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Drainage Density | Soil and Water Conservation<\/a><\/p>\n

Calculating for Hydraulic Head when the Discharge, the Permeability or Hydraulic Conductivity of soil, the Number of Equipotential Drops, the Number of Flow Channel, the Dimension of the Field and the Dimension of the Field are Given<\/strong><\/h3>\n

h = q x (Nd<\/sub>.c)<\/sup> \/ k.b.Nf<\/sub><\/sub><\/p>\n

Where;<\/p>\n

h = Hydraulic Head
\nq = Discharge
\nk = Permeability or Hydraulic Conductivity of Soil
\nNd<\/sub>\u00a0= Number of Equipotential Drops
\nNf<\/sub>\u00a0= Number of Flow Channel
\nb = Dimension of the Field
\nc = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the hydraulic head when the discharge is 21, the permeability or hydraulic conductivity of soil is 14, the number of equipotential drops is 9, the number of flow channel is 3, the dimension of the field is 2 and the dimension of the field is 4.<\/p>\n

This implies that;<\/p>\n

q = Discharge = 21
\nk = Permeability or Hydraulic Conductivity of Soil = 14
\nNd<\/sub> = Number of Equipotential Drops = 9
\nNf<\/sub> = Number of Flow Channel = 3
\nb = Dimension of the Field = 2
\nc = Dimension of the Field = 4<\/p>\n

h = q x (Nd<\/sub>.c)<\/sup> \/ k.b.Nf<\/sub><\/sub>
\nh = 21 x (9)(4)<\/sup> \/ 14.2.3<\/sub>
\nSo, h = 21 x 36<\/sup> \/ 84<\/sub>
\nh = 756<\/sup> \/ 84<\/sub>
\nh = 9<\/p>\n

Therefore, the\u00a0hydraulic head\u00a0<\/strong>is\u00a09.<\/strong><\/p>\n

Calculating for Number of Equipotential Drops when the Discharge, the Permeability or Hydraulic Conductivity of soil, the Hydraulic Head, the Number of Flow Channel, the Dimension of the Field and the Dimension of the Field are Given<\/strong><\/h3>\n

Nd<\/sub> = k.b.Nf<\/sub><\/sup> \/ q x c<\/sub><\/p>\n

Where;<\/p>\n

Nd<\/sub>\u00a0= Number of Equipotential Drops
\nq = Discharge
\nk = Permeability or Hydraulic Conductivity of Soil
\nh = Hydraulic Head
\nNf<\/sub>\u00a0= Number of Flow Channel
\nb = Dimension of the Field
\nc = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the number of equipotential drops when the discharge is 24, the permeability or hydraulic conductivity of soil is 12, the hydraulic head is 7, the number of flow channel is 5, dimension of the field is 6 and the dimension of the field is 3.<\/p>\n

This implies that;<\/p>\n

q = Discharge = 24
\nk = Permeability or Hydraulic Conductivity of Soil = 12
\nh = Hydraulic Head = 7
\nNf<\/sub> = Number of Flow Channel = 5
\nb = Dimension of the Field = 6
\nc = Dimension of the Field = 3<\/p>\n

Nd<\/sub> = k.b.Nf<\/sub><\/sup> \/ q x c<\/sub>
\nSo, Nd<\/sub> = 12.6.5<\/sup> \/ 24 x 3<\/sub>
\nNd<\/sub> = 360<\/sup> \/ 72<\/sub>
\nNd<\/sub> = 5<\/p>\n

Therefore, the\u00a0number of equipotential drops\u00a0<\/strong>is\u00a05.<\/strong><\/p>\n

Read more:\u00a0How to calculate for Tractive Force | Soil Mechanics and Foundation<\/a><\/p>\n

Calculating for Number of Flow Channel when the Discharge, the Permeability or Hydraulic Conductivity of soil, the Hydraulic Head, the Number of Equipotential Drops, the Dimension of the Field and the Dimension of the Field are Given<\/strong><\/h3>\n

Nf<\/sub> = q x (Nd<\/sub>.c)<\/sup> \/ k.h.b<\/sub><\/p>\n

Where;<\/p>\n

Nf<\/sub>\u00a0= Number of Flow Channel
\nq = Discharge
\nk = Permeability or Hydraulic Conductivity of Soil
\nh = Hydraulic Head
\nNd<\/sub>\u00a0= Number of Equipotential Drops
\nb = Dimension of the Field
\nc = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the number of flow channel when the discharge is 11, the permeability or hydraulic conductivity of soil is 10, the hydraulic head is 20, the number of equipotential drops is 6, the dimension of the field is 4 and the dimension of the field is 8.<\/p>\n

This implies that;<\/p>\n

q = Discharge = 11
\nk = Permeability or Hydraulic Conductivity of Soil = 10
\nh = Hydraulic Head = 20
\nNd<\/sub> = Number of Equipotential Drops = 6
\nb = Dimension of the Field = 4
\nc = Dimension of the Field = 8<\/p>\n

Nf<\/sub> = q x (Nd<\/sub>.c)<\/sup> \/ k.h.b<\/sub>
\nThat is, Nf<\/sub> = 11 x (6)(8)<\/sup> \/ 10.20.4<\/sub>
\nNf<\/sub> = 528<\/sup> \/ 800<\/sub>
\nNf<\/sub> = 0.66<\/p>\n

Therefore, the\u00a0number of flow channel\u00a0<\/strong>is\u00a00.66.<\/strong><\/p>\n

Calculating for Dimension of the Field when the Discharge, the Permeability or Hydraulic Conductivity of soil, the Hydraulic Head, the Number of Equipotential Drops, the Number of Flow Channel and the Dimension of the Field are Given<\/strong><\/h3>\n

b = q x (Nd<\/sub>.c)<\/sup> \/ k.h.Nf<\/sub><\/sub><\/p>\n

Where;<\/p>\n

b = Dimension of the Field
\nq = Discharge
\nk = Permeability or Hydraulic Conductivity of Soil
\nh = Hydraulic Head
\nNd<\/sub>\u00a0= Number of Equipotential Drops
\nNf<\/sub>\u00a0= Number of Flow Channel
\nc = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the dimension of the field when the discharge is 10, the permeability or hydraulic conductivity of soil is 8, the hydraulic head is 4, the number of equipotential drops is 2, the number of flow channel is 9 and the dimension of the field is 3.<\/p>\n

This implies that;<\/p>\n

q = Discharge = 10
\nk = Permeability or Hydraulic Conductivity of Soil = 8
\nh = Hydraulic Head = 4
\nNd<\/sub> = Number of Equipotential Drops = 2
\nNf<\/sub> = Number of Flow Channel = 9
\nc = Dimension of the Field = 3<\/p>\n

b = q x (Nd<\/sub>.c)<\/sup> \/ k.h.Nf<\/sub><\/sub>
\nSo, b = 10 x (2)(3)<\/sup> \/ 8.4.9<\/sub>
\nb = 60<\/sup> \/ 288<\/sub>
\nb = 0.208<\/p>\n

Therefore, the\u00a0dimension of the field\u00a0<\/strong>is\u00a00.208.<\/strong><\/p>\n

Calculating for Dimension of the Field when the Discharge, the Permeability or Hydraulic Conductivity of soil, the Hydraulic Head, the Number of Equipotential Drops, the Number of Flow Channel and the Dimension of the Field are Given<\/strong><\/h3>\n

c = k.b.Nf<\/sub><\/sup> \/ q x Nd<\/sub><\/sub><\/p>\n

Where;<\/p>\n

c = Dimension of the Field
\nq = Discharge
\nk = Permeability or Hydraulic Conductivity of Soil
\nh = Hydraulic Head
\nNd<\/sub>\u00a0= Number of Equipotential Drops
\nNf<\/sub>\u00a0= Number of Flow Channel
\nb = Dimension of the Field<\/p>\n

Let’s solve an example;
\nFind the dimension of the field when the discharge is 28, the permeability or hydraulic conductivity of soil is 18, the hydraulic head is 15, the number of equipotential drops is 4, the number of flow channel is 2 and the dimension of the field is 1.<\/p>\n

This implies that;<\/p>\n

q = Discharge = 28
\nk = Permeability or Hydraulic Conductivity of Soil = 18
\nh = Hydraulic Head = 15
\nNd<\/sub> = Number of Equipotential Drops = 4
\nNf<\/sub> = Number of Flow Channel = 2
\nb = Dimension of the Field = 1<\/p>\n

c = k.b.Nf<\/sub><\/sup> \/ q x Nd<\/sub><\/sub>
\nThen, c = 18.1.2<\/sup> \/ 28 x 4<\/sub>
\nc = 36<\/sup> \/ 112<\/sub>
\nc = 0.321<\/p>\n

Therefore, the\u00a0dimension of the field\u00a0<\/strong>is\u00a00.321.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Stream Density | Soil and Water Conservation<\/a><\/p>\n

How to Calculate Discharge in Soil and Water Conservation Using Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the discharge.<\/p>\n

To get the answer and workings of the discharge using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 2,000\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Agricultural<\/strong>\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on\u00a0Soil and Water Conservation <\/strong>under\u00a0Agricultural<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Discharge<\/strong>\u00a0<\/strong>under\u00a0Soil and Water Conservation<\/strong><\/p>\n

\"How<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the discharge according to the respective parameters which is the Permeability or Hydraulic conductivity of soil (k), Hydraulic head (h), Number of equipotential drops (Nd<\/sub>), Number of flow channel (Nf<\/sub>), Dimension of the field (b)\u00a0<\/strong>and\u00a0Dimension of the field (c).<\/strong><\/p>\n

\"How<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the Permeability or Hydraulic conductivity of soil (k)<\/strong> is 9<\/strong>, Hydraulic head (h)<\/strong> is 12<\/strong>, Number of equipotential drops (Nd<\/sub>)<\/strong> is 7<\/strong>, Number of flow channel (Nf<\/sub>)<\/strong> is 10<\/strong>, Dimension of the field (b) <\/strong>is 6 <\/strong>and\u00a0Dimension of the field (c)<\/strong> is 2<\/strong>.<\/p>\n

\"\"<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How
\n\"\"<\/p>\n

As you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the discharge and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents discharge. To calculate discharge, six essential parameters are needed and these parameters are Permeability…","protected":false},"author":5,"featured_media":14006,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[828,1136,838,60,1133,1134,1135,1132,1129],"class_list":["post-4003","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-agricultural","tag-dimension-of-the-field","tag-discharge","tag-engineering","tag-hydraulic-head","tag-number-of-equipotential-drops","tag-number-of-flow-channel","tag-permeability-or-hydraulic-conductivity-of-soil","tag-soil-and-water-conservation","cs-entry"],"yoast_head":"\nHow 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