{"id":3827,"date":"2020-09-25T12:18:16","date_gmt":"2020-09-25T11:18:16","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=3827"},"modified":"2024-04-17T17:57:32","modified_gmt":"2024-04-17T16:57:32","slug":"how-to-calculate-and-solve-for-rate-of-flow-hydrology-ii","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/09\/25\/how-to-calculate-and-solve-for-rate-of-flow-hydrology-ii\/","title":{"rendered":"How to Calculate and Solve for Rate of Flow | Hydrology II"},"content":{"rendered":"

\"\"<\/p>\n

The image above represents rate of flow. To calculate rate of flow, three essential parameters are needed and these parameters are Co-efficient of Permeability (k), Hydraulic gradient (i) <\/strong>and Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow (A).<\/strong><\/p>\n

The formula for calculating rate of flow:<\/p>\n

Q = kiA<\/p>\n

Where:<\/p>\n

Q = Rate of Flow
\nk = Coefficient of Permeability
\ni = Hydraulic Gradient
\nA = Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow<\/p>\n

Let’s solve an example;
\nFind the rate of flow when the co-efficient of permeability is 14, hydraulic gradient is 22 and the cross-sectional area of soil mass perpendicular to the direction of flow is 10.<\/p>\n

This implies that;<\/p>\n

k = Coefficient of Permeability = 14
\ni = Hydraulic Gradient = 22
\nA = Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow = 10<\/p>\n

That is, Q = kiA
\nQ = (14)(22)(10)
\nQ = 3080<\/p>\n

Therefore, the\u00a0rate of flow\u00a0<\/strong>is\u00a03080.<\/strong><\/p>\n

Calculating for the Co-efficient of Permeability when the Rate of Flow, the Hydraulic Gradient and the Cross-Sectional Area of Soil Mass Perpendicular to Direction of Flow are Given<\/strong><\/h3>\n

k = <\/span>Q<\/sup> \/ <\/span>iA<\/sub><\/p>\n

Where;<\/p>\n

k = Co-efficient of Permeability
\nQ = Rate of Flow
\ni = Hydraulic Gradient
\nA = Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow<\/p>\n

Let’s solve an example;
\nFind the co-efficient of permeability when the rate of flow is 40, the hydraulic gradient is 15 and the cross-sectional area of soil mass perpendicular to direction of flow is 2.<\/p>\n

This implies that;<\/p>\n

Q = Rate of flow = 40
\ni = Hydraulic Gradient = 15
\nA = Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow = 2<\/p>\n

k = <\/span>Q<\/sup> \/ <\/span>iA<\/sub>
\nThen, k = <\/span>40<\/sup> \/ <\/span>15 x 2<\/sub>
\nk = <\/span>40<\/sup> \/ <\/span>30<\/sub>
\nk = 1.33<\/p>\n

Therefore, the co-efficient of permeability<\/strong> is 1.33.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Discharge Velocity | Hydrology II<\/a><\/p>\n

How to Calculate for Hydraulic Gradient when the Rate of Flow, the Co-efficient of Permeability and the Cross-sectional Area of Soil Mass perpendicular to Direction of Flow are Given<\/strong><\/h3>\n

i = Q<\/sup> \/ kA<\/sub><\/p>\n

Where;<\/p>\n

i = Hydraulic Gradient
\nQ = Rate of Flow
\nk = Co-efficient of Permeability
\nA = Cross-sectional Area of Soil Mass Perpendicular to Direction of Flow<\/p>\n

Let’s Solve an example;
\nFind the hydraulic Gradient when the Rate of Flow is 35, the co-efficient of permeability is 5 and the cross-sectional area of soil Mass perpendicular to Direction of flow is 3.<\/p>\n

This implies that;<\/p>\n

Q = Rate of Flow = 35
\nk = Co-efficient of Permeability = 5
\nA = Cross-sectional Area of Soil Mass Perpendicular to Direction of Flow = 3<\/p>\n

i = Q<\/sup> \/ kA<\/sub>
\nThen, i = 35<\/sup> \/ 5 x 3<\/sub>
\ni = 35<\/sup> \/ 15<\/sub>
\ni = 2.33<\/p>\n

Therefore, the hydraulic gradient<\/strong> is 2.33<\/strong><\/p>\n

How to Calculate for Cross-sectional Area of Soil Mass Perpendicular to Direction of Flow when the Rate of Flow, the Co-efficient of Permeability and the Hydraulic Gradient are Given<\/strong><\/h3>\n

A = Q<\/sup> \/ ki<\/sub><\/p>\n

Where;<\/p>\n

A = Cross-sectional Area of Soil Mass Perpendicular to Direction of Flow
\nQ = Rate of Flow
\nk = Co-efficient of Permeability
\ni = Hydraulic Gradient<\/p>\n

Let’s Solve an example;
\nFind the Cross-sectional Area of Soil Mass Perpendicular to Direction of Flow when the Rate of flow is 20, the Co-efficient of Permeability is 10 and the Hydraulic Gradient is 1.<\/p>\n

This implies that;<\/p>\n

Q = Rate of Flow = 20
\nk = Co-efficient of Permeability = 10
\ni = Hydraulic Gradient = 1<\/p>\n

A = Q<\/sup> \/ ki<\/sub>
\nSo, A = 20<\/sup> \/ 10 x 1<\/sub>
\nA = 20<\/sup> \/ 10<\/sub>
\nA = 2<\/p>\n

Therefore, the Cross-sectional Area of Soil Mass Perpendicular to Direction of Flow<\/strong> is 2.<\/strong><\/p>\n

How to Calculate and Solve for Rate of Flow in Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the rate of flow.<\/p>\n

To get the answer and workings of the rate of flow using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 2,000\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Agricultural<\/strong>\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on\u00a0Hydrology II\u00a0<\/strong>under\u00a0Agricultural<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Rate of Flow <\/strong>under\u00a0Hydrology II<\/strong><\/p>\n

\"How<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the rate of flow according to the respective parameters which is the Co-efficient of Permeability (k), Hydraulic gradient (i) <\/strong>and Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow (A).<\/strong><\/p>\n

\"\"<\/p>\n

Now, enter\u00a0the values appropriately and accordingly for the parameters as required by the Co-efficient of Permeability (k)<\/strong> is 14<\/strong>, Hydraulic gradient (i) <\/strong>is 22 <\/strong>and Cross-Sectional Area of Soil Mass perpendicular to Direction of Flow (A)<\/strong> is 10<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How<\/p>\n

As you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the rate of flow and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents rate of flow. To calculate rate of flow, three essential parameters are needed and…","protected":false},"author":5,"featured_media":13914,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"Calculate Rate of Flow","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"Master the steps and the formula on How to Calculate and Solve for Rate of Flow in Hydrology. Get precise results with Nickzom calculator.","_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":""},"categories":[47],"tags":[828,1074,1076,60,1075,1063,1077],"class_list":["post-3827","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-agricultural","tag-coefficient-of-permeability","tag-cross-sectional-area-of-soil-mass-perpendicular-to-direction-of-flow","tag-engineering","tag-hydraulic-gradient","tag-hydrology-ii","tag-rate-of-flow","cs-entry"],"yoast_head":"\nHow to Calculate and Solve for Rate of Flow | Hydrology II<\/title>\n<meta name=\"description\" content=\"Master the steps and the formula on How to Calculate and Solve for Rate of Flow in Hydrology. 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