{"id":3507,"date":"2020-08-19T12:26:52","date_gmt":"2020-08-19T11:26:52","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=3507"},"modified":"2024-04-07T15:27:38","modified_gmt":"2024-04-07T14:27:38","slug":"how-to-calculate-and-solve-for-total-volume-discharge-per-unit-width-of-aquifer-flow-lines","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/08\/19\/how-to-calculate-and-solve-for-total-volume-discharge-per-unit-width-of-aquifer-flow-lines\/","title":{"rendered":"How to Calculate and Solve for Total Volume Discharge per Unit Width of Aquifer | Flow Lines"},"content":{"rendered":"

\"\"<\/p>\n

The image above represents total volume discharge per unit width of aquifer. To calculate total volume discharge per unit width of aquifer, four essential parameters are needed and these parameters are Hydraulic conductivity (k), Number of flow tubes (p), Total Head Loss over the Length of the Flow Lines (h)\u00a0<\/strong>and\u00a0Number of Squares or Equipotential Drops (f).<\/strong><\/p>\n

The formula for calculating total volume discharge per unit width of aquifer:<\/strong><\/h3>\n

qt<\/sup>\u00a0=\u00a0Kph<\/sup>\u00a0\/\u00a0f<\/sub><\/p>\n

Where:<\/p>\n

qt<\/sup>\u00a0= Total Volume Discharge per Unit Width of Aquifer
\nK = Hydraulic Conductivity
\np = Number of Flow Tubes
\nh = Total Head Loss over the Length of the Flow Lines
\nf = Number of Squares or Equipotential Drops<\/p>\n

Let’s solve an example;
\nFind the total volume discharge per unit width of aquifer when the hydraulic conductivity is 5, the number of flow tubes is 8, total head loss over the length of the flow lines is 11 and the number of squares or equipotential drops is 13.<\/p>\n

This implies that;<\/p>\n

K = Hydraulic Conductivity = 5
\np = Number of Flow Tubes = 8
\nh = Total Head Loss over the Length of the Flow Lines = 11
\nf = Number of Squares or Equipotential Drops = 13<\/p>\n

qt<\/sup>\u00a0=\u00a0Kph<\/sup>\u00a0\/\u00a0f<\/sub>
\nThat is, qt<\/sup>\u00a0=\u00a0(5)(8)(11)<\/sup>\u00a0\/\u00a013<\/sub>
\nqt<\/sup>\u00a0=\u00a0440<\/sup>\u00a0\/\u00a013<\/sub>
\nqt<\/sup>\u00a0= 33.84<\/p>\n

Therefore, the\u00a0total volume discharge per unit width of aquifer\u00a0<\/strong>is\u00a033.84.<\/strong><\/p>\n

Calculating the Hydraulic Conductivity when the Total Volume Discharge per Unit Width of Aquifer, the Number of Flow Tubes, Total Head Loss Over the Length of the Flow Lines and Number of Squares or Equipotential Drops are Given.<\/strong><\/h4>\n

k = qt<\/sup> x f<\/sup> \/ ph<\/sub><\/p>\n

Where;<\/p>\n

K = Hydraulic Conductivity
\nqt<\/sup>\u00a0= Total Volume Discharge per Unit Width of Aquifer
\np = Number of Flow Tubes
\nh = Total Head Loss over the Length of the Flow Lines
\nf = Number of Squares or Equipotential Drops<\/p>\n

Let’s solve an example;
\nFind the hydraulic conductivity when the total volume discharge per unit width of aquifer is 20, the number of flow tubes is 5, the total head loss over the length of the flow lines is 4 and the number of squares or equipotential drops is 2.<\/p>\n

This implies that;<\/p>\n

qt<\/sup> = Total Volume Discharge per Unit Width of Aquifer = 20
\np = Number of Flow Tubes = 5
\nh = Total Head Loss over the Length of the Flow Lines = 4
\nf = Number of Squares or Equipotential Drops = 2<\/p>\n

k = qt<\/sup> x f<\/sup> \/ ph<\/sub>
\nThat is, k = 20 x 2<\/sup> \/ 5 x 4<\/sub>
\nk = 40<\/sup> \/ 20<\/sub>
\nk = 2<\/p>\n

Therefore, the\u00a0hydraulic conductivity\u00a0<\/strong>is\u00a02.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Transmissivity | Aquifer Characteristics<\/a><\/p>\n

Calculating the Number of Flow Tubes when the Total Volume Dishcharge per Unit Width of Aquifer, the Hydraulic Conductivity, Total Head Loss Over the Length of the Flow Lines and the Number of Squares or Equipotential Drops are Given.<\/strong><\/h3>\n

p = qt<\/sup> x f<\/sup> \/ kh<\/sub><\/p>\n

Where;<\/p>\n

p = Number of Flow Tubes
\nqt<\/sup>\u00a0= Total Volume Discharge per Unit Width of Aquifer
\nK = Hydraulic Conductivity
\nh = Total Head Loss over the Length of the Flow Lines
\nf = Number of Squares or Equipotential Drops<\/p>\n

Let’s solve an example;
\nFind the number of flow tubes when the total volume discharge per unit width of aquifer is 32, the hydraulic conductivity is 7, the total head loss over the length of the flow lines is 6 and the number of squares or equipotential drops is 9.<\/p>\n

This implies that;<\/p>\n

qt<\/sup> = Total Volume Discharge per Unit Width of Aquifer = 32
\nK = Hydraulic Conductivity = 7
\nh = Total Head Loss over the Length of the Flow Lines = 6
\nf = Number of Squares or Equipotential Drops = 9<\/p>\n

p = qt<\/sup> x f<\/sup> \/ kh<\/sub>
\nSo, p = 32 x 9<\/sup> \/ 7 x 6<\/sub>
\np = 288<\/sup> \/ 42<\/sub>
\np = 6.86<\/p>\n

Therefore, the\u00a0number of flow tubes\u00a0<\/strong>is\u00a06.86.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Average Linear Velocity | Aquifer Characteristics<\/a><\/p>\n

Calculating the Total Head Loss Over the Length of the Flow Lines when the Total Volume Discharge per Unit Width of Aquifer, the Hydraulic Conductivity, the Number of Flow Tubes and the Number of Squares or Equipotenial Drops are Given<\/strong><\/h3>\n

h = qt<\/sup> x f<\/sup> \/ kp<\/sub><\/p>\n

Where;<\/p>\n

h = Total Head Loss over the Length of the Flow Lines
\nqt<\/sup>\u00a0= Total Volume Discharge per Unit Width of Aquifer
\nK = Hydraulic Conductivity
\np = Number of Flow Tubes
\nf = Number of Squares or Equipotential Drops<\/p>\n

Let’s solve an example;
\nFind the total head loss over the length of the flow lines when the total volume discharge per unit width of aquifer is 14, the hydraulic conductivity is 10, the number of flow tubes is 4 and the number of squares or equipotential drops is 12.<\/p>\n

This implies that;<\/p>\n

qt<\/sup> = Total Volume Discharge per Unit Width of Aquifer = 14
\nK = Hydraulic Conductivity = 10
\np = Number of Flow Tubes = 4
\nf = Number of Squares or Equipotential Drops = 12<\/p>\n

h = qt<\/sup> x f<\/sup> \/ kp<\/sub>
\nThat means, h = 14 x 12<\/sup> \/ 10 x 4<\/sub>
\nh = 168<\/sup> \/ 40<\/sub>
\nh = 4.2<\/p>\n

Therefore, the\u00a0total head loss over the length of the flow lines <\/strong>is\u00a04.2.<\/strong><\/p>\n

Calculating the Number of Squares or Equipotential Drops when the Total Volume Discharge per Unit Width of Aquifer, the Hydraulic Conductivity, the Number of Flow Tubes and the Total Head Loss Over the Length of the Flow Lines are Given<\/strong><\/h3>\n

f = kph<\/sup> \/ qt<\/sup><\/sub><\/p>\n

Where;<\/p>\n

f = Number of Squares or Equipotential Drops
\nqt<\/sup>\u00a0= Total Volume Discharge per Unit Width of Aquifer
\nK = Hydraulic Conductivity
\np = Number of Flow Tubes
\nh = Total Head Loss over the Length of the Flow Lines<\/p>\n

Let’s solve an example;
\nFind the number of squares or equipotential drops when the total volume discharge per unit width of aquifer is 26, the hydraulic conductivity is 14, the number of flow tubes is 21 and the total head loss over the length of the flow lines is 17.<\/p>\n

This implies that;<\/p>\n

qt<\/sup> = Total Volume Discharge per Unit Width of Aquifer = 26
\nK = Hydraulic Conductivity = 14
\np = Number of Flow Tubes = 21
\nh = Total Head Loss over the Length of the Flow Lines = 17<\/p>\n

f = kph<\/sup> \/ qt<\/sup><\/sub>
\nf = 14 x 21 x 17<\/sup> \/ 26<\/sub>
\nSo, f = 4998<\/sup> \/ 26<\/sub>
\nf = 192.2<\/p>\n

Therefore, the\u00a0number of squares or equipotential drops\u00a0<\/strong>is\u00a0192.2.<\/strong><\/p>\n

How to Calculate Total Volume Discharge per Unit Width of Aquifer | Flow Lines Using Nickzom Calculator<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the total volume discharge per unit width of aquifer.<\/p>\n

To get the answer and workings of the total volume discharge per unit width of aquifer using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/h4>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 2,000\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Geology<\/strong>\u00a0<\/b>under\u00a0Add-on<\/strong>.<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on\u00a0Flow Lines\u00a0<\/strong>under\u00a0Geology<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on\u00a0Total Volume Discharge Per Unit Width of Aquifer\u00a0<\/strong>under\u00a0Flow Lines<\/strong><\/p>\n

\"How<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the total volume discharge per unit width of aquifer according to the respective parameters which are the Hydraulic conductivity (k), Number of flow tubes (p), Total Head Loss over the Length of the Flow Lines (h)\u00a0<\/strong>and\u00a0Number of Squares or Equipotential Drops (f).<\/strong><\/p>\n

\"\"<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the Hydraulic conductivity (k)<\/strong> is 5<\/strong>, Number of flow tubes (p)<\/strong> is 8<\/strong>, Total Head Loss over the Length of the Flow Lines (h) <\/strong>is 11<\/strong>and\u00a0Number of Squares or Equipotential Drops (f)<\/strong> is 13<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How<\/p>\n

As you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the total volume discharge per unit width of the aquifer and presents the formula, workings and steps too. And that’s how to Calculate and Solve for Total Volume Discharge per Unit Width of Aquifer.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents total volume discharge per unit width of aquifer. To calculate total volume discharge per…","protected":false},"author":5,"featured_media":13762,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[48],"tags":[658,984,64,843,981,983,982],"class_list":["post-3507","post","type-post","status-publish","format-standard","has-post-thumbnail","category-geology","tag-add-on","tag-flow-lines","tag-geology","tag-hydraulic-conductivity","tag-number-of-flow-tubes","tag-number-of-squares-or-equipotential-drops","tag-total-head-loss-over-the-length-of-the-flow-lines","cs-entry"],"yoast_head":"\nHow 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