{"id":3231,"date":"2020-04-22T23:15:36","date_gmt":"2020-04-22T22:15:36","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=3231"},"modified":"2024-03-31T08:06:25","modified_gmt":"2024-03-31T07:06:25","slug":"how-to-calculate-and-solve-for-total-cross-sectional-area-of-gates-design-of-gating-system","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/04\/22\/how-to-calculate-and-solve-for-total-cross-sectional-area-of-gates-design-of-gating-system\/","title":{"rendered":"How to Calculate and Solve for Total Cross-Sectional Area of Gates | Design of Gating System"},"content":{"rendered":"<p><img decoding=\"async\" class=\"alignnone size-full wp-image-3243\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/toal-cross-sectional-area-of-gates.png\" alt=\"\" width=\"255\" height=\"198\" \/><\/p>\n<p>The image above represents total cross-sectional area of gates. To calculate total cross-sectional area of gates, three essential parameters are needed and these parameters are <strong>Mass of the Casting (G), Specific Speed of Pouring (K<sub>s<\/sub>)<\/strong> and <strong>Time of Pouring (t).<\/strong><\/p>\n<p>The formula for calculating total cross-sectional area of gates:<\/p>\n<p>F<sub>s<\/sub>\u00a0=\u00a0<sup>G<\/sup>\u00a0\/\u00a0<sub>tKs<\/sub><\/p>\n<p>Where:<\/p>\n<p>F<sub>s<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\nK<sub>s<\/sub>\u00a0= Specific Speed Of Pouring<br \/>\nt = Time of Pouring<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the total cross-sectional area of gates when the mass of the casting is 10, specific speed of pouring is 18 and the time of pouring is 9.<\/p>\n<p>This implies that;<\/p>\n<p>G = Mass of the Casting = 10<br \/>\nK<sub>s<\/sub> = Specific Speed Of Pouring = 18<br \/>\nt = Time of Pouring = 9<\/p>\n<p>F<sub>s<\/sub>\u00a0=\u00a0<sup>G<\/sup>\u00a0\/\u00a0<sub>tK<sub>s<br \/>\n<\/sub><\/sub>So, F<sub>s<\/sub>\u00a0=\u00a0<sup>10<\/sup>\u00a0\/\u00a0<sub>9 x 18<\/sub><br \/>\nF<sub>s<\/sub>\u00a0=\u00a0<sup>10<\/sup>\u00a0\/\u00a0<sub>162<\/sub><br \/>\nF<sub>s<\/sub>\u00a0=\u00a0<b>0.0617<\/b><\/p>\n<p>Therefore, the\u00a0<strong>total cross-sectional area of gates\u00a0<\/strong>is\u00a0<strong>0.0617 m<sup>2<\/sup>.<\/strong><\/p>\n<h3><strong>Calculating the Mass of the Casting when the Total Cross-Sectional Area of Gates, Specific Speed of Pouring and the Time of Pouring are Given<\/strong><\/h3>\n<p>G = F<sub>s<\/sub> x tK<sub>s<\/sub><\/p>\n<p>Where:<\/p>\n<p>G = Mass of the Casting<br \/>\nF<sub>s<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nK<sub>s<\/sub>\u00a0= Specific Speed Of Pouring<br \/>\nt = Time of Pouring<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the mass of the casting when the total cross-sectional area of gates is 15, the specific speed of pouring is 7 and the time of pouring is 5.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>s<\/sub> = Total Cross-Sectional Area of Gates = 15<br \/>\nK<sub>s<\/sub> = Specific Speed Of Pouring = 7<br \/>\nt = Time of Pouring = 5<\/p>\n<p>G = F<sub>s<\/sub> x tK<sub>s<\/sub><br \/>\nThen, G = 15 x 5(7)<br \/>\nG = 15 x 35<br \/>\nG = 525<\/p>\n<p>Therefore, the\u00a0<strong>mass of the casting\u00a0<\/strong>is\u00a0<strong>525 m.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2020\/04\/22\/how-to-calculate-and-solve-for-volume-ratio-design-of-gating-system\/\">How to Calculate and Solve for Volume Ratio | Design of Gating System<\/a><\/p>\n<h3><strong>Calculating the Specific Speed of Pouring when the Total Cross-Sectional Area of Gates, Mass of the Casting and the Time of Pouring are Given<\/strong><\/h3>\n<p>K<sub>s<\/sub> = <sup>G<\/sup> \/ <sub>F<sub>s<\/sub> x t<\/sub><\/p>\n<p>Where;<\/p>\n<p>K<sub>s<\/sub>\u00a0= Specific Speed Of Pouring<br \/>\nF<sub>s<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\nt = Time of Pouring<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the specific speed of pouring when the total cross-sectional area of gates is 20, the mass of the casting is 18 and the time of pouring is 10.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>s<\/sub> = Total Cross-Sectional Area of Gates = 20<br \/>\nG = Mass of the Casting = 18<br \/>\nt = Time of Pouring = 10<\/p>\n<p>K<sub>s<\/sub> = <sup>G<\/sup> \/ <sub>F<sub>s<\/sub> x t<\/sub><br \/>\nThen, K<sub>s<\/sub> = <sup>18<\/sup> \/ <sub>20 x 10<\/sub><br \/>\nK<sub>s<\/sub> = <sup>18<\/sup> \/ <sub>200<\/sub><br \/>\nK<sub>s<\/sub> = 0.09<\/p>\n<p>Therefore, the\u00a0<strong>specific speed of pouring\u00a0<\/strong>is\u00a0<strong>0.09.<\/strong><\/p>\n<h3><strong>Calculating the Time of Pouring when the Total Cross-Sectional Area of Gates, the Mass of the Casting and the Specific Speed of Pouring are Given<\/strong><\/h3>\n<p>t = <sup>G<\/sup> \/ <sub>F<sub>s<\/sub> x K<sub>s<\/sub><\/sub><\/p>\n<p>Where;<\/p>\n<p>t = Time of Pouring<br \/>\nF<sub>s<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\nK<sub>s<\/sub> = Specific Speed Of Pouring<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the time of pouring when the total cross-sectional area of gates is 32, the mass of the casting is 22 and the specific speed of pouring is 14.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>s<\/sub> = Total Cross-Sectional Area of Gates = 32<br \/>\nG = Mass of the Casting = 22<br \/>\nK<sub>s<\/sub> = Specific Speed Of Pouring = 14<\/p>\n<p>t = <sup>G<\/sup> \/ <sub>F<sub>s<\/sub> x K<sub>s<\/sub><\/sub><br \/>\nSo, t = <sup>22<\/sup> \/ <sub>32 x 14<\/sub><br \/>\nt = <sup>22<\/sup> \/ <sub>448<\/sub><br \/>\nt = 0.049<\/p>\n<p>Therefore, the\u00a0<strong>time of pouring\u00a0<\/strong>is\u00a0<strong>0.049.<\/strong><\/p>\n<h3><strong>How to Calculate Total Cross-Sectional Area of Gates Using Nickzom Calculator<\/strong><\/h3>\n<p>Nickzom Calculator \u2013\u00a0<strong>The Calculator Encyclopedia<\/strong> is capable of calculating the total cross-sectional area of gates.<\/p>\n<p>To get the answer and workings of the total cross-sectional area of gates using the <strong>Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n<p>You can get this app via any of these means:<\/p>\n<p><strong>Web<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator-plus\">https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n<p>To get access to the\u00a0<strong>professional\u00a0<\/strong>version via web, you need to\u00a0<strong>register<\/strong>\u00a0and\u00a0<strong>subscribe\u00a0<\/strong>for<strong>\u00a0NGN 1,500\u00a0<\/strong>per<strong>\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.<br \/>\nYou can also try the\u00a0<strong>demo\u00a0<\/strong>version via\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator\">https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n<p><strong>Android (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a><br \/>\n<strong>Android (Free)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><br \/>\n<strong>Apple (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8\">https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a><br \/>\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0<strong>Calculator Map,\u00a0<\/strong>then click on\u00a0<strong>Materials &amp; Metallurgical<\/strong><b>\u00a0<\/b>under\u00a0<strong>Engineering<\/strong><strong>.<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3160 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, Click on\u00a0<strong>Foundry Technology<\/strong><strong>\u00a0u<\/strong>nder\u00a0<strong>Material &amp; Metallurgical<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3159 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, Click on\u00a0<strong>Design of Gating System\u00a0<\/strong>under\u00a0<strong>Foundry Technology<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3239 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1185.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1185.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1185-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1185-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1185-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Then, Click on <strong>Total Cross-Sectional Area of Gates<\/strong><strong>\u00a0<\/strong>under\u00a0<strong>Design of Gating System<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3248 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1186.png\" alt=\"How to Calculate and Solve for Total Cross-Sectional Area of Gates | Design of Gating System\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1186.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1186-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1186-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1186-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>The screenshot below displays the page or activity to enter your values, to get the answer for the total cross-sectional area of gates according to the respective parameters which are the <strong>Mass of the Casting (G), Specific Speed of Pouring (K<sub>s<\/sub>)<\/strong> and <strong>Time of Pouring (t).<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3247 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1187.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1187.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1187-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1187-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1187-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Now, enter the values appropriately and accordingly for the parameters as required by the <strong>Mass of the Casting (G)\u00a0<\/strong>is\u00a0<strong>10<\/strong>,<strong> Specific Speed of Pouring (K<sub>s<\/sub>)\u00a0<\/strong>is\u00a0<strong>18<\/strong> and <strong>Time of Pouring (t)<\/strong> is <strong>9<\/strong>.<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3246 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1188.png\" alt=\"How to Calculate and Solve for Total Cross-Sectional Area of Gates | Design of Gating System\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1188.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1188-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1188-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1188-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Finally, Click on Calculate<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3245 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1189.png\" alt=\"How to Calculate and Solve for Total Cross-Sectional Area of Gates | Design of Gating System\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1189.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1189-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1189-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1189-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>As you can see from the screenshot above,\u00a0<strong>Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the total cross-sectional area of gates and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents total cross-sectional area of gates. To calculate total cross-sectional area of gates, three essential&hellip;","protected":false},"author":5,"featured_media":13629,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":""},"categories":[47],"tags":[870,60,871,893,543,918,919,896],"class_list":["post-3231","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-design-of-gating-system","tag-engineering","tag-foundry-technology","tag-mass-of-casting","tag-materials-and-metallurgical","tag-specific-speed-of-pouring","tag-time-of-pouring","tag-total-cross-sectional-area-of-gates","cs-entry"],"yoast_head":"<!-- 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