{"id":3152,"date":"2020-04-20T16:40:47","date_gmt":"2020-04-20T15:40:47","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=3152"},"modified":"2024-03-31T07:11:05","modified_gmt":"2024-03-31T06:11:05","slug":"how-to-calculate-and-solve-for-total-cross-sectional-areas-of-gates-design-of-gating-system-by-a-hydraulic-method","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/04\/20\/how-to-calculate-and-solve-for-total-cross-sectional-areas-of-gates-design-of-gating-system-by-a-hydraulic-method\/","title":{"rendered":"How to Calculate and Solve for Total Cross-Sectional Areas of Gates | Design of Gating System by a Hydraulic Method"},"content":{"rendered":"<p><img decoding=\"async\" class=\"alignnone size-full wp-image-3153\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/total-cross-sectional-areas-of-gates.png\" alt=\"\" width=\"281\" height=\"180\" \/><\/p>\n<p>The image above represents total cross-sectional areas of gates. To calculate total cross-sectional areas of gates, four essential parameters are needed and these parameters are <strong>mass of the casting (G), density of melt (\u03c1), pouring time (t)\u00a0<\/strong>and\u00a0<strong>pouring speed (v).<\/strong><\/p>\n<h3><strong>The Formula for Calculating Total Cross-sectional Areas of Gates<\/strong><\/h3>\n<p>The formula to calculate total cross-sectional areas of gates is:<\/p>\n<p>F<sub>g<\/sub>\u00a0=\u00a0<sup>G<\/sup>\u00a0\/\u00a0<sub>\u03c1tv<\/sub><\/p>\n<p>Where:<\/p>\n<p>F<sub>g<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\n\u03c1 = Density of Melt<br \/>\nt = Pouring Time<br \/>\nv = Pouring Speed<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the total cross-sectional areas of gates when mass of the casting is 12, density of melt is 16, pouring time is 5 and pouring speed is 25.<\/p>\n<p>This implies that;<\/p>\n<p>G = Mass of the Casting = 12<br \/>\n\u03c1 = Density of Melt = 16<br \/>\nt = Pouring Time = 5<br \/>\nv = Pouring Speed = 25<\/p>\n<p>F<sub>g<\/sub>\u00a0=\u00a0<sup>G<\/sup>\u00a0\/\u00a0<sub>\u03c1tv<\/sub><br \/>\nSo, F<sub>g<\/sub>\u00a0=\u00a0<sup>12<\/sup>\u00a0\/\u00a0<sub>16 x 5 x 25<\/sub><br \/>\nF<sub>g<\/sub>\u00a0=\u00a0<sup>12<\/sup>\u00a0\/\u00a0<sub>2000<\/sub><br \/>\nF<sub>g<\/sub>\u00a0=\u00a00.006<\/p>\n<p>Therefore, the\u00a0<strong>total cross-sectional areas of gates\u00a0<\/strong>is\u00a0<strong>0.006 m<sup>2<\/sup>.<\/strong><\/p>\n<h4><strong>Calculating the Mass of the Casting when the Total Cross-Sectional Areas of Gates, the Density of Melt, the Pouring Time and the Pouring Speed are Given.<\/strong><\/h4>\n<p>G = F<sub>g<\/sub> x \u03c1tv<\/p>\n<p>Where;<\/p>\n<p>G = Mass of the Casting<br \/>\nF<sub>g<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\n\u03c1 = Density of Melt<br \/>\nt = Pouring Time<br \/>\nv = Pouring Speed<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the mass of the casting when the total cross-sectional areas of gates is 32, the density of melt is 4, the pouring time is 10 and the pouring speed is 2.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>g<\/sub> = Total Cross-Sectional Area of Gates = 32<br \/>\n\u03c1 = Density of Melt = 4<br \/>\nt = Pouring Time\u00a0 = 10<br \/>\nv = Pouring Speed = 2<\/p>\n<p>G = F<sub>g<\/sub> x \u03c1tv<br \/>\nThen, G = 32 x 4 x 10 x 2<br \/>\nG = 2560<\/p>\n<p>Therefore, the\u00a0<strong>mass of the Casting\u00a0<\/strong>is\u00a0<strong>2560 m.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2020\/04\/22\/how-to-calculate-and-solve-for-time-of-pouring-design-of-gating-system\/\">How to Calculate and Solve for Time of Pouring | Design of Gating System<\/a><\/p>\n<h3><strong>Calculating the Density of Melt when the Total Cross-Sectional Areas of Gates, the Mass of the Casting, Pouring Time and the Pouring Speed are Given<\/strong><\/h3>\n<p>\u03c1 = <sup>G \/ F<sub>g<\/sub><\/sup> \/ <sub>tv<\/sub><\/p>\n<p>Where;<\/p>\n<p>\u03c1 = Density of Melt<br \/>\nF<sub>g<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\nt = Pouring Time<br \/>\nv = Pouring Speed<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the density of melt when the total cross-sectional area of gates is 15, the mass of the casting is 30, the pouring time is 8 and the pouring speed is 12.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>g<\/sub> = Total Cross-Sectional Area of Gates = 15<br \/>\nG = Mass of the Casting = 30<br \/>\nt = Pouring Time = 8<br \/>\nv = Pouring Speed = 12<\/p>\n<p>\u03c1 = <sup>G \/ F<sub>g<\/sub><\/sup> \/ <sub>tv<\/sub><br \/>\nThat is, \u03c1 = <sup>30 \/ 15<\/sup> \/ <sub>8 x 12<\/sub><br \/>\n\u03c1 = <sup>2<\/sup> \/ <sub>96<\/sub><br \/>\n\u03c1 = 0.02<\/p>\n<p>Therefore, the\u00a0<strong>density of melt\u00a0<\/strong>is\u00a0<strong>0.02.<\/strong><\/p>\n<h3><strong>Calculating the Pouring Time when the Total Cross-Sectional Areas of Gates, the Mass of the Casting, the Density of Melt and the Pouring Speed are Given<\/strong><\/h3>\n<p>t = <sup>G \/ F<sub>g<\/sub><\/sup> \/ <sub>\u03c1v<\/sub><\/p>\n<p>Where;<\/p>\n<p>t = Pouring Time<br \/>\nF<sub>g<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\n\u03c1 = Density of Melt<br \/>\nv = Pouring Speed<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the pouring time when the total cross-sectional areas of gates is 20, the mass of the casting is 14, the density of melt is 16 and the pouring speed is 10.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>g<\/sub> = Total Cross-Sectional Area of Gates = 20<br \/>\nG = Mass of the Casting = 14<br \/>\n\u03c1 = Density of Melt = 16<br \/>\nv = Pouring Speed = 10<\/p>\n<p>t = <sup>G \/ F<sub>g<\/sub><\/sup> \/ <sub>\u03c1v<\/sub><br \/>\nSo, t = <sup>14 \/ 20<\/sup> \/ <sub>16 x 10<\/sub><br \/>\nt = <sup>0.7<\/sup> \/ <sub>160<\/sub><br \/>\nt = 0.004375<\/p>\n<p>Therefore, the\u00a0<strong>pouring time\u00a0<\/strong>is\u00a0<strong>0.004375 s.<\/strong><\/p>\n<p>Read more:\u00a0<a href=\"https:\/\/www.nickzom.org\/blog\/2020\/04\/21\/how-to-calculate-and-solve-for-pouring-time-for-medium-sized-and-large-casting-up-to-1000kg-in-mass-design-of-gating-system\/\">How to Calculate and Solve for Pouring Time for Medium-Sized and Large Casting up to 1000kg in Mass | Design of Gating System<\/a><\/p>\n<h4><strong>Calculating the Pouring Speed when the Total Cross-Sectional Areas of Gates, the Mass of the Casting, the Density of Melt and the Pouring Time are Given.<\/strong><\/h4>\n<p>v = <sup>G \/ F<sub>g<\/sub><\/sup> \/ <sub>\u03c1t<\/sub><\/p>\n<p>Where;<\/p>\n<p>v = Pouring Speed<br \/>\nF<sub>g<\/sub>\u00a0= Total Cross-Sectional Area of Gates<br \/>\nG = Mass of the Casting<br \/>\n\u03c1 = Density of Melt<br \/>\nt = Pouring Time<\/p>\n<p>Let&#8217;s solve an example;<br \/>\nFind the pouring speed when the total cross-sectional areas of gates is 7, mass of the casting is 28, density of melt is 21 and the pouring time is 2.<\/p>\n<p>This implies that;<\/p>\n<p>F<sub>g<\/sub> = Total Cross-Sectional Area of Gates = 7<br \/>\nG = Mass of the Casting = 28<br \/>\n\u03c1 = Density of Melt = 21<br \/>\nt = Pouring Time = 2<\/p>\n<p>v = <sup>G \/ F<sub>g<\/sub><\/sup> \/ <sub>\u03c1t<\/sub><br \/>\nSo, v = <sup>28 \/ 7<\/sup> \/ <sub>21 x 2<\/sub><br \/>\nv = <sup>4<\/sup> \/ <sub>42<\/sub><br \/>\nv = 0.095<\/p>\n<p>Therefore, the\u00a0<strong>pouring speed\u00a0<\/strong>is\u00a0<strong>0.095.<\/strong><\/p>\n<h3><strong>How to Calculate Total Cross-Sectional Areas of Gates Using Nickzom Calculator<\/strong><\/h3>\n<p>Nickzom Calculator \u2013\u00a0<strong>The Calculator Encyclopedia<\/strong> is capable of calculating the total cross-sectional areas of gates.<\/p>\n<p>To get the answer and workings of the total cross-sectional areas of gates using the <strong>Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n<p>You can get this app via any of these means:<\/p>\n<p><strong>Web<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator-plus\">https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n<p>To get access to the\u00a0<strong>professional\u00a0<\/strong>version via web, you need to\u00a0<strong>register<\/strong>\u00a0and\u00a0<strong>subscribe\u00a0<\/strong>for<strong>\u00a0NGN 1,500\u00a0<\/strong>per<strong>\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.<br \/>\nYou can also try the\u00a0<strong>demo\u00a0<\/strong>version via\u00a0<a href=\"https:\/\/www.nickzom.org\/calculator\">https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n<p><strong>Android (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a><br \/>\n<strong>Android (Free)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator\">https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a><br \/>\n<strong>Apple (Paid)<\/strong>\u00a0\u2013\u00a0<a href=\"https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8\">https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a><br \/>\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0<strong>Calculator Map,\u00a0<\/strong>then click on <strong>Materials &amp; Metallurgical<\/strong><b>\u00a0<\/b>under\u00a0<strong>Engineering<\/strong><strong>.<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3160 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1095-2-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Then, Click on <strong>Foundry Technology<\/strong><strong>\u00a0<\/strong>under\u00a0<strong>Material &amp; Metallurgical<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3159 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1145-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Then, Click on <strong>Design of Gating System\u00a0<\/strong>under\u00a0<strong>Foundry Technology<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3158 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1146.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1146.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1146-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1146-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1146-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>So, Click on <strong>Total Cross-Sectional Areas of Gates<\/strong><strong>\u00a0<\/strong>under\u00a0<strong>Design of Gating System<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3157 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1147.png\" alt=\"\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1147.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1147-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1147-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1147-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Then, the screenshot below displays the page or activity to enter your values, to get the answer for the total cross-sectional areas of gates according to the respective parameters which are the <strong>mass of the casting (G), density of melt (\u03c1), pouring time (t)\u00a0<\/strong>and\u00a0<strong>pouring speed (v).<\/strong><\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3156 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1148.png\" alt=\"How to Calculate and Solve for Total Cross-Sectional Areas of Gates | Design of Gating System by a Hydraulic Method\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1148.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1148-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1148-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1148-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>So, enter the values appropriately and accordingly for the parameters as required by the <strong>mass of the casting (G)<\/strong> is <strong>12<\/strong>,<strong> density of melt (\u03c1)<\/strong> is <strong>16<\/strong>,<strong> pouring time (t) <\/strong>is <strong>5 <\/strong>and\u00a0<strong>pouring speed (v)<\/strong> is <strong>25<\/strong>.<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3155 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1149.png\" alt=\"How to Calculate and Solve for Total Cross-Sectional Areas of Gates | Design of Gating System by a Hydraulic Method\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1149.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1149-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1149-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1149-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>Finally, Click on Calculate<\/p>\n<p><img decoding=\"async\" class=\"alignnone wp-image-3154 size-full\" src=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1150.png\" alt=\"How to Calculate and Solve for Total Cross-Sectional Areas of Gates | Design of Gating System by a Hydraulic Method\" width=\"1366\" height=\"768\" srcset=\"https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1150.png 1366w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1150-300x169.png 300w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1150-1024x576.png 1024w, https:\/\/www.nickzom.org\/blog\/wp-content\/uploads\/2020\/04\/Screenshot-1150-768x432.png 768w\" sizes=\"(max-width: 1366px) 100vw, 1366px\" \/><\/p>\n<p>As you can see from the screenshot above,\u00a0<strong>Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the total cross-sectional areas of gates and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents total cross-sectional areas of gates. To calculate total cross-sectional areas of gates, four essential&hellip;","protected":false},"author":5,"featured_media":13584,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":""},"categories":[47],"tags":[894,870,60,871,893,543,869,895,896],"class_list":["post-3152","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-density-of-melt","tag-design-of-gating-system","tag-engineering","tag-foundry-technology","tag-mass-of-casting","tag-materials-and-metallurgical","tag-pouring-speed","tag-pouring-time","tag-total-cross-sectional-area-of-gates","cs-entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.8 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>How to Calculate and Solve for Total Cross-Sectional Areas of Gates | Design of Gating System by a Hydraulic Method<\/title>\n<meta name=\"description\" content=\"These are the steps on How to Calculate and Solve for Total Cross-Sectional Areas of Gates in Design of Gating System by a Hydraulic Method\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.nickzom.org\/blog\/2020\/04\/20\/how-to-calculate-and-solve-for-total-cross-sectional-areas-of-gates-design-of-gating-system-by-a-hydraulic-method\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How to Calculate and Solve for Total Cross-Sectional Areas of Gates | Design of Gating System by a Hydraulic 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