{"id":3108,"date":"2020-04-19T10:33:40","date_gmt":"2020-04-19T09:33:40","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=3108"},"modified":"2024-03-31T06:50:25","modified_gmt":"2024-03-31T05:50:25","slug":"how-to-calculate-and-solve-for-flexural-strength-for-circular-cross-section-in-defects-ceramics","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/04\/19\/how-to-calculate-and-solve-for-flexural-strength-for-circular-cross-section-in-defects-ceramics\/","title":{"rendered":"How to Calculate and Solve for Flexural Strength for Circular Cross-section in Defects | Ceramics"},"content":{"rendered":"

\"\"<\/p>\n

The image above represents flexural strength for circular cross-section in defects.<\/p>\n

To compute for flexural strength for circular cross-section in defects, three essential parameters are needed and these parameters are Load at fracture (Ff<\/sub>), Specimen radius (R)<\/strong> and Distance between support Points (L).<\/strong><\/p>\n

The Formula for Calculating Flexural Strength for Circular Cross-section in Defects<\/strong><\/h3>\n

\u03c3fs<\/sub>\u00a0=\u00a0Ff<\/sub>L<\/sup> \/ \u03c0R\u00b3<\/sub><\/p>\n

Where:<\/p>\n

\u03c3fs<\/sub>\u00a0= Flexural Strength
\nL = Distance between Support Points
\nFf<\/sub>\u00a0= Load at Fracture
\nR = Specimen Radius<\/p>\n

Lets’s solve an example;
\nFind the flexural strength when the distance between support points is 30, load at fracture is 21 and the specimen radius is 11.<\/p>\n

This implies that;<\/p>\n

L = Distance between Support Points = 30
\nFf<\/sub> = Load at Fracture = 21
\nR = Specimen Radius = 11<\/p>\n

\u03c3fs<\/sub>\u00a0=\u00a0Ff<\/sub>L<\/sup> \/ \u03c0R\u00b3<\/sub>
\n\u03c3fs<\/sub>\u00a0=\u00a0(21)(30)<\/sup> \/ \u03c0(11)\u00b3<\/sub>
\nThen, \u03c3fs<\/sub>\u00a0=\u00a0(630)<\/sup> \/ \u03c0(1331)<\/sub>
\n\u03c3fs<\/sub>\u00a0=\u00a0(630)<\/sup> \/ (4181.4)<\/sub>
\n\u03c3fs<\/sub>\u00a0= 0.150<\/p>\n

Therefore, the\u00a0flexural strength for circular cross-section\u00a0<\/strong>is\u00a00.150 Pa.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Flexural Strength with Relation to Volume Fraction | Ceramics<\/a><\/p>\n

Calculating the Distance Between Support Points when the Flexural Strength for Circular Cross-section, the Specimen Radius and the Load at Fracture are Given<\/strong><\/h3>\n

L = \u03c3fs<\/sub> x \u03c0R\u00b3<\/sup> \/ Ff<\/sub><\/sub><\/p>\n

Where;<\/p>\n

L = Distance between Support Points
\n\u03c3fs<\/sub>\u00a0= Flexural Strength
\nFf<\/sub>\u00a0= Load at Fracture
\nR = Specimen Radius<\/p>\n

Let’s solve an example;
\nFind the distance between support points when the flexural strength is 44, load at fracture is 3 and specimen radius is 20.<\/p>\n

This implies that;<\/p>\n

\u03c3fs<\/sub> = Flexural Strength = 44
\nFf<\/sub> = Load at Fracture = 3
\nR = Specimen Radius = 20<\/p>\n

L = \u03c3fs<\/sub> x \u03c0R\u00b3<\/sup> \/ Ff<\/sub><\/sub>
\nL = 44 x \u03c0 x 3\u00b3<\/sup> \/ 20<\/sub>
\nSo, L = 44 x \u03c0 x 27<\/sup> \/ 20<\/sub>
\nL = 3732.2<\/sup> \/ 20<\/sub>
\nL = 186.61<\/p>\n

Therefore, the\u00a0distance between support point\u00a0<\/strong>is\u00a0186.61.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Flexural Strength for Rectangular Cross-section in Defects | Ceramics<\/a><\/p>\n

Calculating the Load at Fracture when the Flexural Strength, the Specimen Radius and the Distance Between Support Point are Given<\/strong><\/h3>\n

Ff<\/sub> = \u03c3fs<\/sub> x \u03c0R\u00b3<\/sup> \/ L<\/sub><\/p>\n

Where;<\/p>\n

Ff<\/sub>\u00a0= Load at Fracture
\n\u03c3fs<\/sub>\u00a0= Flexural Strength
\nL = Distance between Support Points
\nR = Specimen Radius<\/p>\n

Let’s solve an example;
\nFind the load at fracture when the distance between support points is 14, the flexural strength is 7 and the specimen radius is 4.<\/p>\n

This implies that;<\/p>\n

\u03c3fs<\/sub> = Flexural Strength = 7
\nL = Distance between Support Points = 14
\nR = Specimen Radius = 4<\/p>\n

Ff<\/sub> = \u03c3fs<\/sub> x \u03c0R\u00b3<\/sup> \/ L<\/sub>
\nFf<\/sub> = 7 x \u03c0 x 4\u00b3<\/sup> \/ 14<\/sub>
\nThat is, Ff<\/sub> = 7 x \u03c0 x 64<\/sup> \/ 14<\/sub>
\nFf<\/sub> = 1407.4<\/sup> \/ 14<\/sub>
\nFf<\/sub> = 100.5<\/p>\n

Therefore, the\u00a0load at fracture\u00a0<\/strong>is\u00a0100.5.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Schottky Defect | Ceramics<\/a><\/p>\n

Calculating the Specimen Radius when the Flexural Strength, the Distance Between Support Points and the Load at fracture are Given<\/strong><\/h3>\n

R = 3<\/sup>\u221a(Ff<\/sub>L<\/sup> \/ \u03c3fs<\/sub><\/sub> x 1<\/sup> \/ \u03c0<\/sub>)<\/p>\n

Where;<\/p>\n

R = Specimen Radius
\n\u03c3fs<\/sub>\u00a0= Flexural Strength
\nL = Distance between Support Points
\nFf<\/sub> = Load at Fracture<\/p>\n

Let’s solve an example;
\nFind the specimen radius when the flexural strength is 18, the distance between support points is 11 and the load at fracture is 7.<\/p>\n

This implies that;<\/p>\n

\u03c3fs<\/sub> = Flexural Strength = 18
\nL = Distance between Support Points = 11
\nFf<\/sub> = Load at Fracture = 7<\/p>\n

R = 3<\/sup>\u221a(Ff<\/sub>L<\/sup> \/ \u03c3fs<\/sub><\/sub> x 1<\/sup> \/ \u03c0<\/sub>)
\nThat is, R = 3<\/sup>\u221a(7 x 11<\/sup> \/ 18<\/sub> x 1<\/sup> \/ \u03c0<\/sub>)
\nR = 3<\/sup>\u221a(77<\/sup> \/ 18<\/sub> x 0.318)
\nR = 3<\/sup>\u221a(4.27 x 0.318)
\nSo, R = 3<\/sup>\u221a1.35786
\nR = 1.107<\/p>\n

Therefore, the\u00a0specimen radius\u00a0<\/strong>is\u00a01.107.<\/strong><\/p>\n

How to Calculate Flexural Strength for Circular Cross-section in Defects in Ceramics<\/strong><\/h3>\n

Nickzom Calculator \u2013 The Calculator Encyclopedia<\/strong> is capable of calculating the flexural strength for circular cross-section.<\/p>\n

To get the answer and workings of the flexural strength for circular cross-section using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 1,500\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Materials & Metallurgical<\/strong>\u00a0<\/b>under\u00a0Engineering<\/strong>.<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on\u00a0Ceramics<\/strong>\u00a0<\/strong>under\u00a0Material & Metallurgical<\/strong><\/p>\n

\"\"<\/p>\n

Now, Click on Flexural Strength for Circular Cross-Section in Defects<\/strong>\u00a0<\/strong>under\u00a0Ceramics<\/strong><\/p>\n

\"\"<\/p>\n

The screenshot below displays the page or activity to enter your values, to get the answer for the flexural strength for circular cross-section in defects\u00a0 according to the respective parameters which are the Load at fracture (Ff<\/sub>), Specimen radius (R)<\/strong> and Distance between support Points (L).<\/strong><\/p>\n

\"How<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the Load at fracture (Ff<\/sub>)<\/strong> is 21<\/strong>, Specimen radius (R)\u00a0<\/strong>is\u00a011<\/strong> and Distance between support Points (L)<\/strong> is 30<\/strong>.<\/p>\n

\"How<\/p>\n

Finally, Click on Calculate<\/p>\n

\"How<\/p>\n

As you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the flexural strength for cross-section in defects and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents flexural strength for circular cross-section in defects. To compute for flexural strength for circular…","protected":false},"author":5,"featured_media":13567,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":""},"categories":[47],"tags":[865,889,60,890,887,543,888],"class_list":["post-3108","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-ceramics","tag-distance-between-support-points","tag-engineering","tag-flexural-strength-for-circular-cross-section-in-defects","tag-load-at-fracture","tag-materials-and-metallurgical","tag-specimen-radius","cs-entry"],"yoast_head":"\nHow to 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