{"id":3089,"date":"2020-04-17T14:54:09","date_gmt":"2020-04-17T13:54:09","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=3089"},"modified":"2024-03-30T11:13:13","modified_gmt":"2024-03-30T10:13:13","slug":"how-to-calculate-and-solve-for-normally-occupied-positions-ceramics","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2020\/04\/17\/how-to-calculate-and-solve-for-normally-occupied-positions-ceramics\/","title":{"rendered":"How to Calculate and Solve for Normally Occupied Positions | Ceramics"},"content":{"rendered":"\n
\"\"<\/figure>\n\n\n\n

The image above represents normally occupied positions in ceramics. To calculate normally occupied positions, four essential parameters are needed, and these parameters are Avogadro’s number (NA<\/sub>), Density (\u03c1), Atomic weight (AK<\/sub>)<\/strong> and Atomic weights (AG<\/sub>).<\/strong><\/p>\n\n\n\n

The Formula for Calculating Normally Occupied Positions<\/strong><\/h3>\n\n\n\n

N = NA<\/sub>\u03c1 <\/sup>\/ (AK + AG)<\/sub><\/p>\n\n\n\n

N = Normally Occupied Positions
NA<\/sub> = Avogadro’s Number
AK<\/sub>, AG<\/sub> = Atomic Weights
\u03c1 = Density<\/p>\n\n\n\n

Let’s solve the following example below:
Find the normally occupied positions when the avogadro’s number is 6.022e+23, atomic weight is 12, atomic weight is 16 and the density is 10.<\/p>\n\n\n\n

This implies the following;<\/p>\n\n\n\n

NA<\/sub> = Avogadro’s Number = 6.022e+23
AK<\/sub>, AG<\/sub> = Atomic Weights = 12, 16
\u03c1 = Density = 10<\/p>\n\n\n\n

N = NA<\/sub>\u03c1 <\/sup>\/ (AK + AG)<\/sub>
So, N = (6.022e+23)(10)<\/sup>\/(12 + 16)<\/sub>
N = (6.022e+24)<\/sup>\/(28)<\/sub>
N = 2.15e+23<\/p>\n\n\n\n

Therefore, the normally occupied positions <\/strong>is 2.15e+23.<\/strong><\/p>\n\n\n\n

Calculating the Density when the Normally Occupied Positions, the Avogadro’s Number, the Atomic Weights are Given<\/strong><\/h3>\n\n\n\n

\u03c1 = N (AK<\/sub> + AG<\/sub>)<\/sup> \/ NA<\/sub><\/sub><\/p>\n\n\n\n

Where;<\/p>\n\n\n\n

\u03c1 = Density
N = Normally Occupied Positions
NA<\/sub> = Avogadro’s Number
AK<\/sub>, AG<\/sub> = Atomic Weights<\/p>\n\n\n\n

Let’s solve the following example below:
Given that normally occupied positions is 20, the avogadro’s number is 6.022e+23, atomic weights is 18, 6.<\/p>\n\n\n\n

This implies the following:<\/p>\n\n\n\n

N = Normally Occupied Positions =20
NA<\/sub> = Avogadro’s Number = 6.022e+23
AK<\/sub>, AG<\/sub> = Atomic Weights = 18, 6<\/p>\n\n\n\n

\u03c1 = N (AK<\/sub> + AG<\/sub>)<\/sup> \/ NA<\/sub><\/sub>
\u03c1 = 20 (18 + 6)<\/sup> \/ 6.022e+23<\/sub>
Then, \u03c1 = 20 (24)<\/sup> \/ 6.022e+23<\/sub>
\u03c1 = 480<\/sup> \/ 6.022e+23<\/sub>
\u03c1 = 7.970e-22<\/p>\n\n\n\n

Therefore, the density <\/strong>is 7.970e-22.<\/strong><\/p>\n\n\n\n

Calculating the Atomic Weight (AK<\/sub>) when the Normally Occupied Positions, the Avogadro’s Number, Density and Atomic Weight (AG<\/sub>) are Given<\/strong><\/h3>\n\n\n\n

AK<\/sub> = NA<\/sub>\u03c1<\/sup> \/ N<\/sub> – AG<\/sub><\/p>\n\n\n\n

Where;<\/p>\n\n\n\n

\u03c1 = Density
N = Normally Occupied Positions
NA<\/sub> = Avogadro’s Number
AK<\/sub>, AG<\/sub> = Atomic Weights<\/p>\n\n\n\n

Let’s solve the following example below:
Find the atomic weight when the normally occupied positions is 24, the density is 12, the avogadro’s number is 6.022e+23 and the atomic weight is 10.<\/p>\n\n\n\n

This implies the following:<\/p>\n\n\n\n

\u03c1 = Density = 12
N = Normally Occupied Positions = 24
NA<\/sub> = Avogadro’s Number = 6.022e+23
AG<\/sub> = Atomic Weights = 10<\/p>\n\n\n\n

Then, AK<\/sub> = NA<\/sub>\u03c1<\/sup> \/ N<\/sub> – AG<\/sub>
AK<\/sub> = 6.022e+23 x 12<\/sup> \/ 24<\/sub> – 10
That is, AK<\/sub> = 7.2264e+24<\/sup> \/ 24<\/sub> – 10
AK<\/sub> = 3.011e-23 – 10
AK<\/sub> = – 6.98e-23<\/p>\n\n\n\n

Therefore, the atomic weight <\/strong>is – 6.98e-23.<\/strong><\/p>\n\n\n\n

Read more: How to Calculate and Solve for Flexural Strength for Rectangular Cross-section in Defects | Ceramics<\/a><\/p>\n\n\n\n

Calculating the Atomic Weight (AG<\/sub>) when the Normally Occupied Positions, the Avogadro’s Number, Density and Atomic Weight (AK<\/sub>) are Given<\/strong><\/h3>\n\n\n\n

AG<\/sub> = NA<\/sub>\u03c1<\/sup> \/ N<\/sub> – AK<\/sub><\/p>\n\n\n\n

Where;<\/p>\n\n\n\n

\u03c1 = Density
N = Normally Occupied Positions
NA<\/sub> = Avogadro’s Number
AK<\/sub>, AG<\/sub> = Atomic Weights<\/p>\n\n\n\n

Let’s solve for the following example:
Find the atomic weight when the normally occupied positions is 10, the density is 10, the avogadro’s number is 6.022e+23 and the atomic weight is 4.<\/p>\n\n\n\n

This implies the following:<\/p>\n\n\n\n

\u03c1 = Density = 10
N = Normally Occupied Positions = 10
NA<\/sub> = Avogadro’s Number = 6.022e+23
AG<\/sub> = Atomic Weights = 4<\/p>\n\n\n\n

So, AG<\/sub> = NA<\/sub>\u03c1<\/sup> \/ N<\/sub> – AK<\/sub>
AG<\/sub> = 6.022e+23 x 10<\/sup> \/ 10<\/sub> – 4
That is, AG<\/sub> = 6.022e+24<\/sup> \/ 10<\/sub> – 4
AG<\/sub> = 6.022e-23 – 4
AG<\/sub> = 2.022e-23<\/p>\n\n\n\n

Therefore, the\u00a0atomic weight\u00a0<\/strong>is\u00a02.022e-23.<\/strong><\/p>\n\n\n\n

Read more: How to Calculate and Solve for Theoretical Density of Ceramics | Ceramics<\/a><\/p>\n\n\n\n

How to Calculate and Solve for Normally Occupied Positions in Ceramics Using Nickzom Calculator<\/strong><\/h3>\n\n\n\n

Nickzom Calculator \u2013 The Calculator Encyclopedia<\/strong> is capable of calculating the normally occupied positions.<\/p>\n\n\n\n

To get the answer and workings of the normally occupied positions using the Nickzom Calculator \u2013 The Calculator Encyclopedia. <\/strong>First, you need to obtain the app.<\/p>\n\n\n\n

You can get this app via any of these means:<\/p>\n\n\n\n

Web<\/strong> \u2013 https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n\n\n\n

To get access to the professional <\/strong>version via web, you need to register<\/strong> and subscribe <\/strong>for NGN 1,500 <\/strong>per annum<\/strong> to have utter access to all functionalities.
You can also try the demo <\/strong>version via https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n\n\n\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
Android (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
Apple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
Once you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Materials & Metallurgical<\/strong>\u00a0<\/b>under\u00a0Engineering.<\/strong><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

So, Click on\u00a0Ceramics\u00a0<\/strong>under\u00a0Material & Metallurgical<\/strong><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Then, Click on\u00a0Normally Occupied Positions<\/strong> under\u00a0Ceramics<\/strong><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

So, the screenshot below displays the page or activity to enter your values, to get the answer for the normally occupied positions according to the respective parameters which are the Avogadro’s number (NA<\/sub>), Density (\u03c1), Atomic weight (AK<\/sub>)<\/strong> and Atomic weights (AG<\/sub>).<\/strong><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Then, enter the values appropriately and accordingly for the parameters as required by the Avogadro’s number (NA<\/sub>)<\/strong> is 6.022e+23<\/strong>, Density (\u03c1)<\/strong> is 10<\/strong>, Atomic weight (AK<\/sub>)<\/strong> is 12 <\/strong>and Atomic weights (AG<\/sub>)<\/strong> is 16<\/strong>.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Finally, Click on Calculate<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

As you can see from the screenshot above, Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the normally occupied positions and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above represents normally occupied positions in ceramics. To calculate normally occupied positions, four essential parameters are…","protected":false},"author":5,"featured_media":13548,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[880,863,865,507,60,543,881],"class_list":["post-3089","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-atomic-weight","tag-avogadros-number","tag-ceramics","tag-density","tag-engineering","tag-materials-and-metallurgical","tag-normally-occupied-position","cs-entry"],"yoast_head":"\nHow to Calculate and 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