{"id":1998,"date":"2019-07-06T06:40:00","date_gmt":"2019-07-06T05:40:00","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=1998"},"modified":"2024-03-08T07:34:43","modified_gmt":"2024-03-08T06:34:43","slug":"how-to-solve-and-calculate-for-a-dimensionless-pressure-drop-oil-rate-oil-fvf-oil-viscosity-in-well-testing-the-calculator-encyclopedia","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2019\/07\/06\/how-to-solve-and-calculate-for-a-dimensionless-pressure-drop-oil-rate-oil-fvf-oil-viscosity-in-well-testing-the-calculator-encyclopedia\/","title":{"rendered":"How to Solve and Calculate for a Dimensionless Pressure Drop, Oil Rate, Oil FVF, Oil Viscosity in Well Testing | The Calculator Encyclopedia"},"content":{"rendered":"

To calculate the dimensionless pressure drop, five essential parameters are needed, and these parameters are Permeability-Thickness Product (kh), Pressure Drop (\u0394P), Oil Rate (Qo<\/sub>), Oil Viscosity (\u03bco<\/sub>), <\/strong>and Oil FVF (Bo<\/sub>).<\/strong><\/p>\n

The formula for calculating dimensionless pressure drop:<\/p>\n

PD<\/sub>\u00a0=\u00a0kh\u0394P<\/sup> \/ 141.2Qo<\/sub>Bo<\/sub>\u03bco<\/sub><\/sub><\/p>\n

Where;<\/p>\n

PD<\/sub>\u00a0= Dimensionless Pressure Drop
\nkH = Permeability-Thickness Product
\n\u0394P = Pressure Drop
\nQo<\/sub>\u00a0= Oil Rate
\n\u03bco<\/sub>\u00a0= Oil Viscosity
\nBo<\/sub>\u00a0= Oil FVF<\/p>\n

Let’s solve an example;
\nFind the dimensionless pressure drop with a permeability-thickness product of 70, a pressure drop of 30, an oil rate of 49, an oil viscosity of 19 and oil FVF of 31.<\/p>\n

This implies that;<\/p>\n

kh = Permeability-Thickness Product = 20
\n\u0394P = Pressure Drop = 30
\nQo<\/sub> = Oil Rate = 49
\n\u03bco<\/sub> = Oil Viscosity = 19
\nBo<\/sub> = Oil FVF = 31<\/p>\n

PD<\/sub>\u00a0=\u00a0kh\u0394P<\/sup> \/ 141.2Qo<\/sub>Bo<\/sub>\u03bco<\/sub><\/sub>
\nPD<\/sub>\u00a0=\u00a020 x 30<\/sup>\/141.2 x 49 x 31 x 19<\/sub>
\nSo, PD<\/sub>\u00a0=\u00a020 x 30<\/sup>\/4075173.19<\/sub>
\nPD<\/sub>\u00a0=\u00a0600<\/sup>\/4075173.19<\/sub>
\nPD<\/sub> = 0.000147<\/p>\n

Therefore, the\u00a0dimensionless pressure drop <\/strong>is 0.000147 psi.<\/strong><\/p>\n

Calculating the Permeability-Thickness Product when Dimensionless Pressure Drop, Pressure Drop, Oil Rate, Oil Viscosity and Oil FVF<\/strong><\/h3>\n

kh = PD<\/sub> x 141.2Qo<\/sub>Bo<\/sub>\u03bco<\/sub><\/sup> \/ \u0394P<\/sub><\/p>\n

Where;<\/p>\n

kh = Permeability-Thickness Product
\nPD<\/sub>\u00a0= Dimensionless Pressure Drop
\n\u0394P = Pressure Drop
\nQo<\/sub>\u00a0= Oil Rate
\n\u03bco<\/sub>\u00a0= Oil Viscosity
\nBo<\/sub>\u00a0= Oil FVF<\/p>\n

Let’s solve an example;
\nFind the permeability-thickness product with a dimensionless pressure drop of 28, a pressure drop of 16, an oil rate of 21, an oil viscosity of 18 and oil FVF of 24.<\/p>\n

This implies that;<\/p>\n

PD<\/sub> = Dimensionless Pressure Drop = 28
\n\u0394P = Pressure Drop =16
\nQo<\/sub> = Oil Rate = 21
\n\u03bco<\/sub> = Oil Viscosity = 18
\nBo<\/sub> = Oil FVF = 24<\/p>\n

kh = PD<\/sub> x 141.2Qo<\/sub>Bo<\/sub>\u03bco<\/sub><\/sup> \/ \u0394P<\/sub>
\nThen, kh = 28 x 141.2 x 21 x 24 x 18<\/sup> \/ 16<\/sub>
\nkh = 35867059.8<\/sup> \/ 16<\/sub>
\nkh = 2241691.2<\/p>\n

Therefore, the\u00a0permeability-thickness product\u00a0<\/strong>is\u00a02241691.2.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Well, External and Dimensionless Radius | Nickzom Calculator<\/a><\/p>\n

Calculating the Pressure Drop when Dimensionless Pressure Drop, Permeability-Thickness Product, Oil Rate, Oil Viscosity and Oil FVF<\/strong><\/h3>\n

\u0394P = PD<\/sub> x 141.2Qo<\/sub>Bo<\/sub>\u03bco<\/sub><\/sup> \/ kh<\/sub><\/p>\n

Where;<\/p>\n

\u0394P = Pressure Drop
\nPD<\/sub>\u00a0= Dimensionless Pressure Drop
\nkh = Permeability-Thickness Product
\nQo<\/sub>\u00a0= Oil Rate
\n\u03bco<\/sub>\u00a0= Oil Viscosity
\nBo<\/sub>\u00a0= Oil FVF<\/p>\n

Let’s solve an example;
\nFind the pressure drop with a dimensionless pressure drop of 38, a permeability-thickness product of 24, an oil rate of 11, an oil viscosity of 8 and oil FVF of 12.<\/p>\n

This implies that;<\/p>\n

PD<\/sub> = Dimensionless Pressure Drop = 38
\nkh = Permeability-Thickness Product = 24
\nQo<\/sub> = Oil Rate = 11
\n\u03bco<\/sub> = Oil Viscosity = 8
\nBo<\/sub> = Oil FVF = 12<\/p>\n

\u0394P = PD<\/sub> x 141.2Qo<\/sub>Bo<\/sub>\u03bco<\/sub><\/sup> \/ kh<\/sub>
\n\u0394P = 38 x 141.2 x 11 x 12 x 8<\/sup> \/ 24<\/sub>
\nThen, \u0394P = 5666073.6<\/sup> \/ 24<\/sub>
\n\u0394P = 236086.4<\/p>\n

Therefore, the pressure drop<\/strong> is\u00a0236086.4.<\/strong><\/p>\n

Calculating the Oil Rate when Dimensionless Pressure Drop, Permeability-Thickness Product, Pressure Drop, Oil Viscosity and Oil FVF<\/strong><\/h3>\n

Qo<\/sub> = kh\u0394P<\/sup> \/ PD<\/sub> x 141.2Bo<\/sub>\u03bco<\/sub><\/sub><\/p>\n

Where;<\/p>\n

Qo<\/sub>\u00a0= Oil Rate
\nPD<\/sub>\u00a0= Dimensionless Pressure Drop
\nkh = Permeability-Thickness Product
\n\u0394P = Pressure Drop
\n\u03bco<\/sub>\u00a0= Oil Viscosity
\nBo<\/sub>\u00a0= Oil FVF<\/p>\n

Let’s solve an example;
\nFind the oil rate with a dimensionless pressure drop of 60, a permeability-thickness product of 30, a pressure drop of 34, an oil viscosity of 11 and oil FVF of 25.<\/p>\n

This implies that;<\/p>\n

PD<\/sub> = Dimensionless Pressure Drop = 60
\nkh = Permeability-Thickness Product = 30
\n\u0394P = Pressure Drop =34
\n\u03bco<\/sub> = Oil Viscosity = 11
\nBo<\/sub> = Oil FVF = 25<\/p>\n

Qo<\/sub> = kh\u0394P<\/sup> \/ PD<\/sub> x 141.2Bo<\/sub>\u03bco<\/sub><\/sub>
\nThat is, Qo<\/sub> = 30 x 34<\/sup> \/ 60 x 141.2 x 25 x 11<\/sub>
\nQo<\/sub> = 1020<\/sup> \/ 2329800<\/sub>
\nQo<\/sub> = 4.37e-4<\/p>\n

Therefore, the\u00a0oil rate\u00a0<\/strong>is\u00a04.37e-4<\/strong><\/p>\n

Calculating the Oil FVF when Dimensionless Pressure Drop, Permeability-Thickness Product, Pressure Drop, Oil Rate and Oil Viscosity<\/strong><\/h3>\n

Bo<\/sub> = kh\u0394P<\/sup> \/ PD<\/sub> x 141.2Qo<\/sub>\u03bco<\/sub><\/sub><\/p>\n

Where;<\/p>\n

Bo<\/sub>\u00a0= Oil FVF
\nPD<\/sub>\u00a0= Dimensionless Pressure Drop
\nkh = Permeability-Thickness Product
\n\u0394P = Pressure Drop
\nQo<\/sub>\u00a0= Oil Rate
\n\u03bco<\/sub>\u00a0= Oil Viscosity<\/p>\n

Let’s solve an example;
\nFind the oil FVF with a dimensionless pressure drop of 40, a permeability-thickness product of 10, a pressure drop of 7, an oil rate of 3 and oil viscosity of 5.<\/p>\n

This implies that;<\/p>\n

PD<\/sub> = Dimensionless Pressure Drop = 40
\nkh = Permeability-Thickness Product = 10
\n\u0394P = Pressure Drop = 7
\nQo<\/sub> = Oil Rate = 3
\n\u03bco<\/sub>\u00a0= Oil Viscosity = 5<\/p>\n

Bo<\/sub> = kh\u0394P<\/sup> \/ PD<\/sub> x 141.2Qo<\/sub>\u03bco<\/sub><\/sub>
\nHence, Bo<\/sub> = 10 x 7<\/sup> \/ 40 x 141.2 x 3 x 5<\/sub>
\nBo<\/sub> = 70<\/sup> \/ 84720<\/sub>
\nBo<\/sub> = 8.26e-4<\/p>\n

Therefore, the\u00a0oil FvF\u00a0<\/strong>is\u00a08.26e-4.<\/strong><\/p>\n

Calculating the Oil Viscosity when Dimensionless Pressure Drop, Permeability-Thickness Product, Pressure Drop, Oil Rate and Oil FVF<\/strong><\/h3>\n

\u03bco<\/sub> = kh\u0394P<\/sup> \/ PD<\/sub> x 141.2Qo<\/sub>Bo<\/sub><\/sub><\/p>\n

Where;<\/p>\n

\u03bco<\/sub>\u00a0= Oil Viscosity
\nPD<\/sub>\u00a0= Dimensionless Pressure Drop
\nkh = Permeability-Thickness Product
\n\u0394P = Pressure Drop
\nQo<\/sub>\u00a0= Oil Rate
\nBo<\/sub>\u00a0= Oil FVF<\/p>\n

Let’s solve an example;
\nFind the oil viscosity with a dimensionless pressure drop of 20, a permeability-thickness product of 9.5, a pressure drop of 4.6, an oil rate of 3.5 and oil FVF of 4.<\/p>\n

This implies that;<\/p>\n

PD<\/sub> = Dimensionless Pressure Drop = 20
\nkh = Permeability-Thickness Product = 9.5
\n\u0394P = Pressure Drop = 4.6
\nQo<\/sub> = Oil Rate = 3.5
\nBo<\/sub> = Oil FVF = 4<\/p>\n

\u03bco<\/sub> = kh\u0394P<\/sup> \/ PD<\/sub> x 141.2Qo<\/sub>Bo<\/sub><\/sub>
\n\u03bco<\/sub> = 9.5 x 4.6<\/sup> \/ 20 x 141.2 x 3.5 x 4<\/sub>
\nSo, \u03bco<\/sub> = 43.7<\/sup> \/ 39536<\/sub>
\n\u03bco<\/sub> = 0.001105<\/p>\n

Therefore, the\u00a0oil viscosity\u00a0<\/strong>is\u00a00.001105.<\/strong><\/p>\n

How to Calculate for a Dimensionless Pressure Drop Using The Calculator Encyclopedia<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the dimensionless pressure drop.<\/p>\n

To get the answer and workings of the dimensionless pressure drop using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 1,500\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a>
\nOnce, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Petroleum\u00a0<\/strong>under\u00a0Engineering<\/strong><\/p>\n

\"How<\/p>\n

Now, Click on\u00a0Well Testing<\/strong>\u00a0<\/strong>under\u00a0Petroleum<\/strong><\/p>\n

\"How<\/p>\n

Now, Click on\u00a0D<\/strong>imensionless Pressure Drop<\/strong>\u00a0<\/strong>under\u00a0Well Testing<\/strong><\/p>\n

\"\"<\/p>\n

The screenshot below displays the page or activity to enter your values to get the answer for the dimensionless pressure drop according to the respective parameters, which are the Permeability-Thickness Product (kh), Pressure Drop (\u0394P), Oil Rate (Qo<\/sub>), Oil Viscosity (\u03bco<\/sub>) <\/strong>and Oil FVF (Bo<\/sub>).<\/strong><\/p>\n

\"How<\/p>\n

Now, enter the values appropriately and accordingly for the parameters as required by the Permeability-Thickness Product (kh) is 20, Pressure Drop (\u0394P)<\/strong> is 30<\/strong>, Oil Rate (Qo<\/sub>)<\/strong> is 49<\/strong>, Oil Viscosity (\u03bco<\/sub>) <\/strong>is 19 <\/strong>and Oil FVF (Bo<\/sub>)<\/strong> is 31<\/strong>.<\/p>\n

\"\"<\/p>\n

Finally, Click on Calculate<\/p>\n

\"\"
\n\"\"<\/p>\n

As\u00a0you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong>\u2013 The Calculator Encyclopedia solves for the dimensionless pressure drop and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"To calculate the dimensionless pressure drop, five essential parameters are needed, and these parameters are Permeability-Thickness Product (kh),…","protected":false},"author":5,"featured_media":13064,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47],"tags":[84,60,87,632,630,633,149,73,635,604],"class_list":["post-1998","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","tag-calculator-encyclopedia","tag-engineering","tag-nickzom-calculator","tag-oil-fvf","tag-oil-rate","tag-oil-viscosity","tag-petroleum","tag-pressure","tag-pressure-drop","tag-well-testing","cs-entry"],"yoast_head":"\nHow 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