{"id":1698,"date":"2019-04-06T23:43:27","date_gmt":"2019-04-06T22:43:27","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=1698"},"modified":"2024-02-18T09:53:28","modified_gmt":"2024-02-18T08:53:28","slug":"how-to-calculate-and-solve-for-maximum-velocity-to-avoid-overturning-of-a-vehicle-moving-along-a-level-circular-path-the-calculator-encyclopedia","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2019\/04\/06\/how-to-calculate-and-solve-for-maximum-velocity-to-avoid-overturning-of-a-vehicle-moving-along-a-level-circular-path-the-calculator-encyclopedia\/","title":{"rendered":"How to Calculate and Solve for Maximum Velocity to avoid Overturning of a Vehicle moving along a Level Circular Path | The Calculator Encyclopedia"},"content":{"rendered":"

\"\"<\/p>\n

The image above shows the maximum velocity to avoid overturning of a vehicle moving along a level circular path. To calculate the maximum velocity, four essential parameters are needed and these parameters are Acceleration due to Gravity (g), Height of Centre of Gravity of the Vehicle from Ground Level (h), Radius of Circular Path (r), and Half of the Distance between the Centre Lines of the Wheel (a).<\/strong><\/p>\n

The formula for calculating the maximum velocity:<\/p>\n

vmax<\/sub>\u00a0= \u221a(gra<\/sup> \/ h<\/sub>)<\/p>\n

Where:
\nvmax<\/sub>\u00a0= Maximum Velocity to avoid Overturning of a Vehicle moving along a Level Circular Path
\ng = Acceleration due to Gravity
\nh = Height of Centre of Gravity of the Vehicle from Ground Level
\nr = Radius of Circular Path
\na = Half of the Distance between the Centre Lines of the Wheel<\/p>\n

Let’s solve an example;
\nFind the maximum velocity when the Acceleration due to Gravity (g) is 10.2, Height of Centre of Gravity of the Vehicle from Ground Level (h) is 14, Radius of Circular Path (r) is 22 and Half of the Distance between the Centre Lines of the Wheel (a) is 32.<\/p>\n

This implies that;
\ng = Acceleration due to Gravity = 10.2
\nh = Height of Centre of Gravity of the Vehicle from Ground Level = 14
\nr = Radius of Circular Path = 22
\na = Half of the Distance between the Centre Lines of the Wheel = 32<\/p>\n

vmax<\/sub>\u00a0= \u221a(gra<\/sup> \/ h<\/sub>)
\nvmax<\/sub>\u00a0= \u221a((10.2)(22)(32)<\/sup>\/14<\/sub>)
\nSo, vmax<\/sub>\u00a0= \u221a((7180.79)<\/sup>\/14<\/sub>)
\nvmax<\/sub> = \u221a(512.91)
\nvmax<\/sub>\u00a0= 22.647<\/p>\n

Therefore, the maximum velocity to avoid Overturning of a Vehicle moving along a Level Circular Path<\/strong> is 22.647 m\/s.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for the Reaction at the Inner Wheel of a Vehicle moving along a Level Circular Path | The Calculator Encyclopedia<\/a><\/p>\n

How to Calculate the Maximum Velocity to Avoid Overturning of a Vehicle Moving along a Level Circular Path Using The Calculator Encyclopedia<\/strong><\/h3>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the maximum velocity to avoid overturning of a vehicle moving along a level circular path.<\/p>\n

To get the answer and workings of the maximum velocity to avoid overturning of a vehicle moving along a level circular path using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

Get the Nickzom Calculator below:<\/strong><\/h4>\n

You can get this app via any of these means:<\/p>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 1,500\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a><\/p>\n

Steps to Calculate<\/strong><\/h4>\n

Once, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Mechanics\u00a0<\/strong>under\u00a0Engineering<\/strong><\/p>\n

\"How<\/p>\n

Now, Click on\u00a0Motion of Circular Path\u00a0<\/strong>under\u00a0Mechanics<\/strong><\/p>\n

\"How<\/p>\n

Click on M<\/strong>aximum Velocity to avoid overturning of a vehicle moving along a level circular path<\/strong>\u00a0<\/strong>under\u00a0Motion of Circular Path<\/strong><\/p>\n

\"How<\/p>\n

The screenshot below displays the page or activity to enter your value, to get the answer for the maximum velocity to avoid overturning of a vehicle moving along a level circular path according to the respective parameter which are the Acceleration due to Gravity (g), Height of Centre of Gravity of the Vehicle from Ground Level (h), Radius of Circular Path (r) and Half of the Distance between the Centre Lines of the Wheel (a).<\/strong><\/p>\n

\"\"<\/p>\n

Now, enter the value appropriately and accordingly for the parameter as required by the Acceleration due to Gravity (g)<\/strong> is 10.2<\/strong>, Height of Centre of Gravity of the Vehicle from Ground Level (h)<\/strong> is 14<\/strong>, Radius of Circular Path (r)<\/strong> is 22<\/strong> and Half of the Distance between the Centre Lines of the Wheel (a)<\/strong> is 32<\/strong>.<\/p>\n

\"\"<\/p>\n

Finally, Click on Calculate<\/p>\n

\"\"
\n\"\"<\/p>\n

As you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong> \u2013 The Calculator Encyclopedia solves for the maximum velocity to avoid overturning of a vehicle moving along a level circular path and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image above shows the maximum velocity to avoid overturning of a vehicle moving along a level circular…","protected":false},"author":5,"featured_media":12861,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47,51],"tags":[209,84,537,535,540,289,87,536,538,117,539],"class_list":["post-1698","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","category-physics","tag-acceleration-due-to-gravity","tag-calculator-encyclopedia","tag-distance","tag-height-of-center-of-gravity","tag-level-circular-path","tag-mass","tag-nickzom-calculator","tag-radius-of-circular-path","tag-reaction","tag-velocity","tag-wheels","cs-entry"],"yoast_head":"\nHow 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