{"id":1671,"date":"2019-04-06T11:40:17","date_gmt":"2019-04-06T10:40:17","guid":{"rendered":"https:\/\/www.nickzom.org\/blog\/?p=1671"},"modified":"2024-02-18T09:36:35","modified_gmt":"2024-02-18T08:36:35","slug":"how-to-calculate-and-solve-for-the-reaction-at-the-outer-wheel-of-a-vehicle-moving-along-a-level-circular-path-nickzom-calculator","status":"publish","type":"post","link":"https:\/\/www.nickzom.org\/blog\/2019\/04\/06\/how-to-calculate-and-solve-for-the-reaction-at-the-outer-wheel-of-a-vehicle-moving-along-a-level-circular-path-nickzom-calculator\/","title":{"rendered":"How to Calculate and Solve for the Reaction at the Outer Wheel of a Vehicle moving along a Level Circular Path | Nickzom Calculator"},"content":{"rendered":"

\"\"<\/p>\n

The image represents a reaction at the outer wheel of a vehicle moving along a level circular path. To calculate the reaction, six essential parameters are needed and these parameters are the Mass of the Vechicle (m), Acceleration due to Gravity (g), Velocity of the Vehicle (v), Height of Centre of Gravity of the Vehicle from the Ground Level (h), Radius of Circular Path (r) and Half of the Distance between the Centre Lines of the Wheel (a).<\/strong><\/p>\n

The formula for calculating the reaction at the outer wheel of a vehicle moving along a level circular path:<\/p>\n

RB<\/sub>\u00a0=\u00a0mg<\/sup> \/ 2<\/sub>[1 +\u00a0v\u00b2h<\/sup>\/gra<\/sub>]<\/p>\n

Where;
\nRB<\/sub>\u00a0= Reaction at the Outer Wheel of a Vehicle moving along a Level Circular Path
\nm = Mass of the Vechicle
\ng = Acceleration due to Gravity
\nv = Velocity of the Vehicle
\nh = Height of Centre of Gravity of the Vehicle from Ground Level
\nr = Radius of Circular Path
\na = Half of the Distance between the Centre Lines of the Wheel<\/p>\n

Let’s solve an example;<\/strong><\/h5>\n

Find<\/strong> the reaction when the Mass of the Vechicle (m) is 12, Acceleration due to Gravity (g) is 9.8, Velocity of the Vehicle (v) is 28, Height of Centre of Gravity of the Vehicle from Ground Level (h) is 16, Radius of Circular Path (r) is 8 and Half of the Distance between the Centre Lines of the Wheel (a) is 4.<\/p>\n

This implies that;
\nm = Mass of the Vechicle = 12
\ng = Acceleration due to Gravity = 9.8
\nv = Velocity of the Vehicle = 28
\nh = Height of Centre of Gravity of the Vehicle from Ground Level = 16
\nr = Radius of Circular Path = 8
\na = Half of the Distance between the Centre Lines of the Wheel = 4<\/p>\n

RB<\/sub>\u00a0=\u00a0mg<\/sup> \/ 2<\/sub>[1 +\u00a0v\u00b2h<\/sup>\/gra<\/sub>]
\nRB<\/sub>\u00a0=\u00a012 x 9.8<\/sup> \/ 2<\/sub>[1 +\u00a028\u00b2 x 16<\/sup>\/9.8 x 8 x 4<\/sub>]
\nThat is, RB<\/sub>\u00a0=\u00a0117.60<\/sup> \/ 2<\/sub>[1 +\u00a0784 x 16<\/sup>\/313.6<\/sub>]
\nRB<\/sub>\u00a0=\u00a058.80[1 +\u00a040]
\nRB<\/sub>\u00a0=\u00a058.80[41]
\nSo, RB<\/sub>\u00a0=\u00a058.80[41]
\nRB<\/sub> = 2410.8<\/p>\n

Therefore, the reaction of the outer wheel of a vehicle moving along a level circular path<\/strong>\u00a0is 2410.8 N.<\/strong><\/p>\n

Read more:\u00a0How to Calculate and Solve for Maximum Velocity to avoid Overturning of a Vehicle moving along a Level Circular Path | The Calculator Encyclopedia<\/a><\/p>\n

How to Calculate the Reaction at the Outer Wheel of a Vehicle Moving along a Level Circular Path Using Nickzom Calculator<\/strong><\/h3>\n

<\/p>\n

Nickzom Calculator \u2013\u00a0The Calculator Encyclopedia<\/strong> is capable of calculating the reaction of the outer wheel of a vehicle moving along a level circular path.<\/p>\n

To get the answer and workings of the reaction of the outer wheel of a vehicle moving along a level circular path using the Nickzom Calculator \u2013 The Calculator Encyclopedia.\u00a0<\/strong>First, you need to obtain the app.<\/p>\n

You can get this app via any of these means:<\/p>\n

Get the Nickzom Calculator below:<\/strong><\/h4>\n

Web<\/strong>\u00a0\u2013\u00a0https:\/\/www.nickzom.org\/calculator-plus<\/a><\/p>\n

To get access to the\u00a0professional\u00a0<\/strong>version via web, you need to\u00a0register<\/strong>\u00a0and\u00a0subscribe\u00a0<\/strong>for\u00a0NGN 1,500\u00a0<\/strong>per\u00a0annum<\/strong>\u00a0to have utter access to all functionalities.
\nYou can also try the\u00a0demo\u00a0<\/strong>version via\u00a0https:\/\/www.nickzom.org\/calculator<\/a><\/p>\n

Android (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=org.nickzom.nickzomcalculator<\/a>
\nAndroid (Free)<\/strong>\u00a0\u2013\u00a0https:\/\/play.google.com\/store\/apps\/details?id=com.nickzom.nickzomcalculator<\/a>
\nApple (Paid)<\/strong>\u00a0\u2013\u00a0https:\/\/itunes.apple.com\/us\/app\/nickzom-calculator\/id1331162702?mt=8<\/a><\/p>\n

Once, you have obtained the calculator encyclopedia app, proceed to the\u00a0Calculator Map,\u00a0<\/strong>then click on\u00a0Mechanics\u00a0<\/strong>under\u00a0Engineering<\/strong><\/p>\n

\"How<\/p>\n

Now, Click on\u00a0Motion of Circular Path\u00a0<\/strong>under\u00a0Mechanics<\/strong><\/p>\n

\"How<\/p>\n

Click on Reaction of the outer wheel of a vehicle moving along a level circular path<\/strong>\u00a0<\/strong>under\u00a0Motion of Circular Path<\/strong><\/p>\n

\"How<\/p>\n

The screenshot below displays the page or activity to enter your value, to get the answer for the reaction of the outer wheel of a vehicle moving along a level circular path according to the respective parameter which are the Mass of the Vechicle (m), Acceleration due to Gravity (g), Velocity of the Vehicle (v), Height of Centre of Gravity of the Vehicle from Ground Level (h), Radius of Circular Path (r) and Half of the Distance between the Centre Lines of the Wheel (a).<\/strong><\/p>\n

\"\"<\/p>\n

Now, enter the value appropriately and accordingly for the parameter as required by the Mass of the Vechicle (m)<\/strong> is 12<\/strong>, Acceleration due to Gravity (g)<\/strong> is 9.8<\/strong>, Velocity of the Vehicle (v)<\/strong> is 28<\/strong>, Height of Centre of Gravity of the Vehicle from Ground Level (h)<\/strong> is 16<\/strong>, Radius of Circular Path (r)<\/strong> is 8<\/strong> and Half of the Di<\/strong>stance between the Centre Lines of the Wheel (a)<\/strong> is 4<\/strong>.<\/p>\n

\"\"<\/p>\n

Finally, Click on Calculate<\/p>\n

\"\"\"\"<\/p>\n

As you can see from the screenshot above,\u00a0Nickzom Calculator<\/strong> \u2013 The Calculator Encyclopedia solves for the reaction of the outer wheel of a vehicle moving along a level circular path and presents the formula, workings and steps too.<\/p>\n","protected":false},"excerpt":{"rendered":"The image represents a reaction at the outer wheel of a vehicle moving along a level circular path.…","protected":false},"author":5,"featured_media":12842,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_opengraph-title":"","_yoast_wpseo_opengraph-description":"","_yoast_wpseo_twitter-title":"","_yoast_wpseo_twitter-description":"","_lmt_disableupdate":"","_lmt_disable":"","_sitemap_exclude":false,"_sitemap_priority":"","_sitemap_frequency":"","_yoast_wpseo_focuskw_text_input":"","csco_display_header_overlay":false,"csco_singular_sidebar":"","csco_page_header_type":"","footnotes":"","_members_access_role":[],"_members_access_error":""},"categories":[47,51],"tags":[209,84,537,535,540,289,87,536,538,117,539],"class_list":["post-1671","post","type-post","status-publish","format-standard","has-post-thumbnail","category-engineering","category-physics","tag-acceleration-due-to-gravity","tag-calculator-encyclopedia","tag-distance","tag-height-of-center-of-gravity","tag-level-circular-path","tag-mass","tag-nickzom-calculator","tag-radius-of-circular-path","tag-reaction","tag-velocity","tag-wheels","cs-entry"],"yoast_head":"\nHow 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