How to Calculate and Solve for Relationship between Thermal Resistivity and Temperature | Electrical Properties

The relationship betweeen thermal resistivity and temperature is illustrated by the image below.

To compute for the relationship between thermal resistivity and temperature, three essential parameters are needed and these parameters are Constant of the Metal (a), Constant of the Metal (ρo) and Temperature (T).

The formula for calculating relationship between thermal resistivity and temperature:

ρt = ρo + aT

Where:

ρt = Thermal Resistivity
ρo = Constant of the Metal
a = Constant of the Metal
T = Temperature

Let’s solve an example;
Find the relationship between thermal resistivity and temperature when the constant of the metal is 32, the constant of the metal is 8 and the temperature is 2.

This implies that;

ρo = Constant of the Metal = 32
a = Constant of the Metal = 8
T = Temperature = 2

ρt = ρo + aT
ρt = 32 + (8)(2)
ρt = 32 + (16)
ρt = 48

Therefore, the relationship between thermal resistivity and temperature is 48 Ωm.

Calculating the Constant of the Metal when the Relationship between Thermal Resistivity and Temperature, the Constant of the Metal and the Temperature is Given.

ρo = ρt – aT

Where:

ρo = Constant of the Metal
ρt = Thermal Resistivity
a = Constant of the Metal
T = Temperature

Let’s solve an example;
Find the constant of the metal when the thermal resistivity is 32, the constant of the metal is 2 and the temperature is 4.

This implies that;

ρt = Thermal Resistivity = 32
a = Constant of the Metal = 2
T = Temperature = 4

ρo = ρt – aT
ρo = 32 – 2(4)
ρo = 32 – 8
ρo = 24

Therefore, the constant of the metal is 24.

Continue reading How to Calculate and Solve for Relationship between Thermal Resistivity and Temperature | Electrical Properties

How to Calculate and Solve for Total Resistivity of Metal | Electrical Properties

The total resistivity of metal is illustrated by the image below.

To compute for total resistivity of metal, three essential parameters are needed and these parameters are Thermal Resistivity (ρt), Impurity Resistivity (ρi) and Deformation Resistivity (ρd).

The formula for calculating the total resistivity of metal:

ρtotal = ρt + ρi + ρd

Where:

ρtotal = Total Resistivity of Metal
ρt = Thermal Resistivity
ρi = Impurity Resistivity
ρd = Deformation Resistivity

Let’s solve an example;
Find the total resistivity of metal when the thermal resistivity is 20, the impurity resistivity is 10 and the deformation resistivity is 2.

This implies that;

ρt = Thermal Resistivity = 20
ρi = Impurity Resistivity = 10
ρd = Deformation Resistivity = 2

ρtotal = ρt + ρi + ρd
ρtotal = 20 + 10 + 2
ρtotal = 32

Therefore, the total resistivity of metal is 32 Ω-m.

Calculating the Thermal Resistivity when the Total Resistivity of Metal, the Impurity Resistivity and the Deformation Resistivity is Given.

ρt = ρtotal – ρi – ρd

Where:

ρt = Thermal Resistivity
ρtotal = Total Resistivity of Metal
ρi = Impurity Resistivity
ρd = Deformation Resistivity

Let’s solve an example;
Find the thermal resistivity when the total resistivity of metal is 40, the impurity resistivity is 10 and the deformation resistivity is 5.

This implies that;

ρtotal = Total Resistivity of Metal = 40
ρi = Impurity Resistivity = 10
ρd = Deformation Resistivity = 5

ρt = ρtotal – ρi – ρd
ρt = 40 – 10 – 5
ρt = 25

Therefore, the thermal resistivity is 25.

Continue reading How to Calculate and Solve for Total Resistivity of Metal | Electrical Properties

How to Calculate and Solve for Electron Drift Velocity | Electrical Properties

The electron drift velocity is illustrated by the image below.

To compute for electron drift velocity, two essential parameters are needed and these parameters are Electron Mobility (μe) and Electric Field Intensity (E).

The formula for calculating electron drift velocity:

vd = μeE

Where:

vd = Electron Drift Velocity
μe = Electron Mobility
E = Electric Field Intensity

Let’s solve an example;
Find the electron drift velocity when the electron mobility is 45 and the electron field intensity is 5.

This implies that;

μe = Electron Mobility = 45
E = Electric Field Intensity = 5

vd = μeE
vd = (45)(5)
vd = 225

Therefore, the electron drift velocity is 225 m/s.

Continue reading How to Calculate and Solve for Electron Drift Velocity | Electrical Properties

How to Calculate and Solve for Current Density | Electrical Properties

The current density is illustrated by the image below.

To compute for current density, two essential parameters are needed and the parameters are Electrical Conductivity (σ) and Electric Field Intensity (E).

The formula for calculating current density:

j = σE

Where:

j = Current Density
σ = Electrical Conductivity
E = Electric Field Intensity

Let’s solve an example;
Find the current density when the electrical conductivity is 32 and the electric field intensity is 4.

This implies that;

σ = Electrical Conductivity = 32
E = Electric Field Intensity = 4

j = σE
j = (32)(4)
j = 128

Therefore, the current density is 128 A/m².

Continue reading How to Calculate and Solve for Current Density | Electrical Properties

How to Calculate and Solve for Electric Field Intensity | Electrical Properties

The electric field intensity is illustrated by the image below.

To compute for electric field intensity, two essential parameters are needed and these parameters are Voltage (V) and Distance between Plates (l).

The formula for calculating electric field intensity:

E = V / l

Where:

E = Electric Field Intensity
V = Voltage
l = Distance between Plates

Let’s solve an example;
Find the electric field intensity when the voltage is 24 and the distance between plates is 8.

This implies that;

V = Voltage = 24
l = Distance between Plates = 8

E = V / l
E = 24 / 8
E = 3

Therefore, the electric field intensity is 3 Vm-1.

Calculating the Voltage when the Electric Field Intensity and the Distance between Plates is Given.

V = El

Where;

V = Voltage
E = Electric Field Intensity
l = Distance betweeen Plates

Let’s solve an example;
Find the voltage when the electric field intensity is 10 and the distance between plates is 5.

This implies that;

E = Electric Field Intensity = 10
l = Distance between Plates = 5

V = El
V = 10 x 5
V = 50

Therefore, the voltage is 50 V.

Continue reading How to Calculate and Solve for Electric Field Intensity | Electrical Properties

How to Calculate and Solve for Electrical Conductivity | Electrical Properties ewqdsx

The electrical conductivity is illustrated by the image below.

To compute for electrical conductivity, one essential parameter is needed and this parameter is Resistivity (ρ).

The formula for calculating electrical conductivity:

σ = 1 / ρ

Where:

σ = Electrical Conductivity
ρ = Resistivity

Let’s solve an example;
Find the electrical conductivity when the resistivity is 22.

This implies that;

ρ = Resistivity = 22

σ = 1 / ρ
σ = 1 / 22
σ = 0.045

Therefore, the electrical conductivity is 0.045 (Ωm)-1.

Continue reading How to Calculate and Solve for Electrical Conductivity | Electrical Properties ewqdsx

How to Calculate and Solve for Cross-Sectional Area | Electric Resistivity

The cross-sectional area is illustrated by the image below.

To compute for cross-sectional area, three essential parameters are needed and these parameters are Resistivity (ρ), Length (l) and Resistance (R).

The formula for calculating cross-sectional area:

A = pl/R

Where:

A = Cross-sectional Area
ρ = resistivity
R = Resistance
l = Length

Let’s solve an example;
Find the cross-sectional area when the resistivity is 4, the resistance is 12 and length is 6.

This implies that;

ρ = resistivity = 4
R = Resistance = 12
l = Length = 6

A = pl/R
A = (4)(6)/12
A = (24)/12
A = 2

Therefore, the cross-sectional area is 2m².

Continue reading How to Calculate and Solve for Cross-Sectional Area | Electric Resistivity

How to Calculate and Solve for Resistivity | Electric Resistivity

The resistivity is illustrated by the image below.

To compute for resistivity, three essential parameters are needed and these parameters are Cross-sectional Area (A), Length (l) and Resistance (R).

The formula for calculating the resistivity:

ρ = RA/l

Where:
ρ = resistivity
R = Resistance
A = Cross-sectional Area
l = Length

Let’s solve an example;
Find the resistivity when the resistance is 10, the cross-sectional area is 4 and the length is 2.

This implies that;

R = Resistance = 10
A = Cross-sectional Area = 4
l = Length = 2

ρ = RA/l
ρ = (2)(10)/4
ρ = (20)/4
ρ = 5

Therefore, the resistivity is 5Ω-m.

Continue reading How to Calculate and Solve for Resistivity | Electric Resistivity

How to Calculate and Solve for Resistance | Electric Resistivity

The resistance is illustrated by the image below.

To compute for resistance, two essential parameters are needed and these parameters are Voltage (V) and Current (I).

The formula for calculating resistance:

R = V / I

Where:

R = Resistance
V = Voltage
I = Current

Let’s solve an example;
Find the resistance when the voltage is 22 and the current is 11.

This implies that;

V = Voltage = 22
I = Current = 11

R = V / I
R = 22 / 11
R = 2

Therefore, the resistance is 2Ω.

Continue reading How to Calculate and Solve for Resistance | Electric Resistivity

How to Calculate and Solve for Current | Ohm’s Law

The current is illustrated by the image below.

To compute for current, two essential parameters are needed and these parameters are Voltage (I) and Resistance (R).

The formula for calculating current:

I = V / R

Where:

I = Current
V = Voltage
R = Resistance

Let’s solve an example;
Find the current when the voltage is 21 and the resistance is 7.

This implies that;

V = Voltage = 21
R = Resistance = 7

I = V / R
I = 21 / 7
I = 3

Therefore, the current is 3 A.

Continue reading How to Calculate and Solve for Current | Ohm’s Law