The image above represents quantity of heat loss.

To compute for quantity of heat loss, four essential parameters are needed and these parameters are **Initial Temperature (T _{1}), Final Temperature (T_{2}), a** and

**E.**

The formula for calculating quantity of heat loss:

Q = a(T_{1} – T_{2})^{5/4} + 4.88E[(^{T1 + 273}/_{100})^{4} – (^{T2 + 273}/_{100})^{4}]

Where:

Q = Quantity of Heat Loss

T_{1} = Initial Temperature

T_{2} = Final Temperature

Let’s solve an example;

Find the quantity of heat loss when the initial temperature is 21, the final temperature is 17, a is 14 and E is 15.

This implies that;

T_{1} = Initial Temperature = 21

T_{2} = Final Temperature = 17

a = 14

E = 15

Q = a(T_{1} – T_{2})^{5/4} + 4.88E[(^{T1 + 273}/_{100})^{4} – (^{T2 + 273}/_{100})^{4}]

Q = 14(21 – 17)^{5/4} + 4.88(15)[(^{21 + 273}/_{100})^{4} – (^{17 + 273}/_{100})^{4}]

Q = 14(4)^{5/4} + 4.88(15)[74.71 – 70.72809]

Q = 14(5.65) + 4.88(15)(3.98)

Q = 79.19 + 291.608

Q = 370.80

Therefore, the **quantity of heat loss **is **370.80 J/Kg K.**

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